# On a three step crisis integro-differential equation

## Abstract

One of the interesting fractional integro-differential equations is the three step crisis equation which has been reviewed recently. In this paper, we investigate the existence of solutions for a three step crisis fractional integro-differential equation under some boundary conditions.

## Preliminaries

It is well known that we can make better exact models for most natural phenomena by using fractional differential equations. Most researchers are working on fractional integro-differential equations (see, for example, [1, 2, 5,6,7,8, 10,11,12,13,14,15,16,17,18,19,20,21]).

In 2010, Agarwal et al. reviewed the existence of solutions $$D^{\alpha } u(t)+ f(t , u(t) )=0$$ with boundary conditions $$u'(0) = \cdots = u^{(n-1)} = 0$$ and $$u(1)=\int _{0} ^{1} u(s) \,d\mu (s)$$, where $$n \geq 2$$, $$\alpha \in (n-1,n)$$, $$\mu (s)$$ is a functional of bounded variation, f may have singularity at $$t=0$$ and $$\int _{0} ^{1} d\mu (s) < 1$$ [3]. In 2012, Agarwal et al. studied positive solutions for the integral value problem $$D^{\alpha } u_{i}(t)+ f_{i}(t , u_{1}(t) , u_{2}(t) )=0$$ with boundary conditions $$u_{i}(0)=u'_{i}(0)=0$$ and $$u_{i}(1) = \int _{0} ^{1} u_{i}(t) \,d\eta (t)$$ for $$i=1,2$$, where $$t \in (0,1)$$, $$\alpha \in (2,3]$$, $$D^{\alpha }$$ is the Riemann–Liouville fractional derivative of order α, $$f_{i}$$ is a real valued continuous map on $$[0,1] \times \mathbb{R} ^{+} \times \mathbb{R}^{+}$$ and $$\int _{0} ^{1} u_{i}(t) \,d\eta (t)$$ denotes the Riemann–Stieltjes integral [4]. In 2013, the singular fractional problem $$D^{\alpha } u+ f(t , u , D^{ \gamma } u, D^{\mu } u )+ g(t , u , D^{\gamma } u, D^{\mu } u)=0$$ with boundary conditions $$u(0)=u'(0)=u''(0)=u'''(0)=0$$ was reviewed, where $$3< \alpha < 4$$, $$0< \gamma <1$$, $$1<\mu <2$$, $$D^{\alpha }$$ is the Caputo fractional derivative and f is a Caratheodory function on $$[0,1] \times (0 , \infty )^{3}$$ [9].

Recently, the authors introduced a new model for investigating the fractional differential equations called three step crisis integro-differential equations [11]. By using the idea, we investigate the existence of solutions for the three step crisis integro-differential equation

\begin{aligned} D^{\alpha } x(t)+ f\biggl(t , x(t), x'(t), D^{\beta }x(t), \int _{0}^{t} h( \xi ) x(\xi ) \,d\xi \biggr)=0 \end{aligned}
(1)

with boundary conditions $$x(0)=x'(T_{0})$$, $$x(1)=x'(T_{1})$$ and $$x''(0)=x^{(n)}(0)=0$$, where $$\alpha >1$$ with $$n=[\alpha ]-1$$, $$T_{0},T_{1}, \beta , \lambda , \mu \in (0,1)$$, $$h \in L^{1}[0,1]$$, $$D^{\alpha }$$ is the Caputo fractional derivative of order α, $$f(t,x_{1}(t),\ldots, x_{5}(t))=f_{1}(t,x_{1}(t),\ldots, x_{4}(t))$$ on $$[0,\lambda )$$, $$f(t,x_{1}(t),\ldots, x_{5}(t))=f_{2}(t,x_{1}(t),\ldots, x _{4}(t))$$ on $$[\lambda ,\mu ]$$ and $$f(t,x_{1}(t),\ldots, x_{5}(t))=f(t,x _{1}(t),\ldots, x_{4}(t))$$ on $$(\mu ,1]$$ in which $$f_{1}(t,\cdot,\cdot,\cdot,\cdot)$$ and $$f_{3}(t,\cdot,\cdot,\cdot,\cdot)$$ are continuous on $$[0,\lambda )$$ and $$(\mu ,1]$$, respectively, and $$f_{2}(t,\cdot,\cdot,\cdot,\cdot)$$ is singular at some points $$t \in [\lambda ,\mu ]$$. In this case, we use the symbol $$f=[f_{1},f _{2},f_{3},\lambda ,\mu ]$$ [11].

As is well known, the Caputo fractional derivative of order $$\alpha >0$$ of a function $$f:(0,\infty )\to \mathbb{R}$$ is defined by $${}^{c}D^{\alpha }f(t)=\frac{1}{\varGamma (n-\alpha )} \int _{0}^{t}\!\frac{f^{n}(s)}{(t-s)^{\alpha +1-n}}\,ds$$, where $$n=[\alpha ]+1$$ (see, for example, [13]). Let Ψ be the family of nondecreasing functions $$\psi :[0,\infty ) \to [0,\infty )$$ such that $$\sum_{n=1}^{\infty } \psi ^{n}(t)<\infty$$ for all $$t> 0$$ [22]. One can check that $$\psi (t)< t$$ for all $$t>0$$ [22]. Let $$T:X \to X$$ and $$\alpha :X \times X \to [0,\infty )$$ be two maps. Then T is called an α-admissible map whenever $$\alpha (x,y) \geq 1$$ implies $$\alpha (Tx,Ty) \geq 1$$ [22]. Let $$(X,d)$$ be a complete metric space, $$\psi \in \varPsi$$ and $$\alpha :X \times X \to [0,\infty )$$ a map. A self-map $$T:X \to X$$ is called an α-ψ-contraction whenever $$\alpha (x,y) d(Tx,Ty) \leq \psi (d(x,y))$$ for all $$x,y \in X$$ [22]. We need the following results.

### Lemma 1

([23])

Let $$0< n-1\leq \alpha < n$$. Then $$I^{\alpha } D^{\alpha }x(t)=x(t)+ \sum_{i=0}^{n-1} c_{i}t^{i}$$ for some constants $$c_{0},\dots ,c_{n-1}$$.

### Lemma 2

([24])

If E is a closed, bounded and convex subset of a Banach space X and $$T : E \to E$$ is completely continuous, then T has a fixed point in E.

### Lemma 3

([22])

Let $$(X,d)$$ be a complete metric space, $$\psi \in \varPsi$$, $$\alpha :X \times X \to [0,\infty )$$ a map and $$T:X \to X$$ an α-admissible α-ψ-contraction. If T is continuous and there exists $$x_{0} \in X$$ such that $$\alpha (x _{0}, Tx_{0}) \geq 1$$, then T has a fixed point.

## Main results

Now, we are ready to state and prove our main results.

### Lemma 4

Let $$\alpha > 1$$, $$n=[\alpha ] +1$$, $$T_{0}, T_{1} \in (0,1)$$ and $$f \in L^{1}[0,1]$$. Then $$x(t)= \int ^{1}_{0} G(t,s) f(s) \,ds$$ is the solution of the pointwise defined equation $$D^{\alpha }x(t) +f(t) = 0$$ with boundary conditions $$x(0)=x'(T_{0})$$, $$x(1)=x'(T_{1})$$ and $$x''(0) = \cdots =x^{(n-1)}(0)=0$$, where $$G(t,s)=\frac{-(t-s)^{\alpha -1}}{\varGamma (\alpha )}+ \frac{(1+t)(1-s)^{\alpha -1}}{\varGamma (\alpha )} - \frac{(1+t)(T_{1} -s)^{\alpha -2}}{\varGamma (\alpha -1 )} - \frac{t(T _{0} -s)^{\alpha -2}}{\varGamma (\alpha -1 )}$$ whenever $$0\leq s \leq t$$, $$s \leq T_{0}$$, $$G(t,s)=\frac{-(t-s)^{\alpha -1}}{\varGamma (\alpha )}+ \frac{(1+t)(1-s)^{ \alpha -1}}{\varGamma (\alpha )} - \frac{(1+t)(T_{1} -s)^{\alpha -2}}{ \varGamma (\alpha -1 )}$$ whenever $$0\leq T_{0} \leq s \leq t$$, $$s \leq T _{1}$$, $$G(t,s)=\frac{(1+t)(1-s)^{\alpha -1}}{\varGamma (\alpha )} - \frac{(1+t)(T _{1} -s)^{\alpha -2}}{\varGamma (\alpha -1 )}$$ whenever $$0\leq t \leq s \leq T_{1}$$, $$s \geq T_{0}$$, $$G(t,s)=\frac{(1+t)(1-s)^{\alpha -1}}{ \varGamma (\alpha )} - \frac{(1+t)(T_{1} -s)^{\alpha -2}}{\varGamma (\alpha -1 )} - \frac{t(T_{0} -s)^{\alpha -2}}{\varGamma (\alpha -1 )}$$ whenever $$0\leq t \leq s \leq T_{0} \leq T_{1}$$, $$G(t,s)=\frac{-(t-s)^{\alpha -1}}{\varGamma (\alpha )}+ \frac{(1+t)(1-s)^{\alpha -1}}{\varGamma (\alpha )}$$ whenever $$0\leq T_{0} \leq T_{1} \leq s \leq t$$ and $$G(t,s)=\frac{(1+t)(1-s)^{ \alpha -1}}{\varGamma (\alpha )}$$ whenever $$0 \leq t \leq s$$, $$s \geq T _{1}$$.

### Proof

Suppose that the equation $$D^{\alpha }x(t) +f(t) = 0$$ holds for all $$t \in E \subset [0,1]$$, where $$m(E^{c})=0$$ and m is the Lebesgue measure on $$\mathbb{R}$$. Let $$f_{0}$$ be a function such that $$f_{0}=f$$ on E. It is easy to check that $$I^{\alpha }(f(t))=I^{ \alpha }(f_{0}(t))$$ for all $$t\in [0,1]$$. This implies that $$I^{\alpha }(D^{\alpha }x(t))= I^{\alpha }(-f_{0}(t))$$ and by using Lemma 1 we get $$x(t)= - \frac{1}{\varGamma (\alpha )} \int ^{t} _{0} (t-s)^{\alpha - 1} f(s) \,ds +c_{0}+ c_{1} t$$ for some constants $$c_{0}$$ and $$c_{1}$$. By using the boundary conditions, we obtain $$x(0)=c_{0}$$ and

$$x'(T_{0})= - \frac{1}{\varGamma (\alpha - 1)} \int ^{T_{0}}_{0} (T_{0}-s)^{ \alpha - 1} f(s) \,ds +c_{1}.$$

Thus, $$c_{1}-c_{0}= - \frac{1}{\varGamma (\alpha - 1)} \int ^{T_{0}}_{0} (T_{0}-s)^{\alpha - 1} f(s) \,ds$$. Since $$x(1)= x'(T_{1})$$, we get

$$c_{0}=\frac{1}{\varGamma (\alpha - 1)} \int ^{1}_{0} (1-s)^{\alpha - 1} f(s) \,ds - \frac{1}{\varGamma (\alpha - 1)} \int ^{T_{1}}_{0} (T_{1}-s)^{\alpha - 1} f(s) \,ds$$

and so

\begin{aligned} c_{1} =&\frac{1}{\varGamma (\alpha )} \int ^{1}_{0} (1-s)^{\alpha - 1} f(s) \,ds \\ &{}- \frac{1}{\varGamma (\alpha - 1)} \int ^{T_{1}}_{0} (T_{1}-s)^{\alpha - 2} f(s) \,ds- \frac{1}{\varGamma (\alpha - 1)} \int ^{T_{0}}_{0} (T_{0}-s)^{ \alpha - 2} f(s) \,ds. \end{aligned}

Hence,

\begin{aligned} x(t) =& - \frac{1}{\varGamma (\alpha )} \int ^{t}_{0} (t-s)^{\alpha - 1} f(s) \,ds - \frac{1}{\varGamma (\alpha )} \int ^{1}_{0} (1-s)^{\alpha - 1} f(s) \,ds \\ &{}- \frac{1}{\varGamma (\alpha - 1)} \int ^{T_{1}}_{0} (T_{1}-s)^{\alpha - 2} f(s) \,ds +\frac{t}{\varGamma (\alpha )} \int ^{1}_{0} (1-s)^{\alpha - 1} f(s) \,ds \\ &{}- \frac{t}{\varGamma (\alpha - 1)} \int ^{T_{1}}_{0} (T_{1}-s)^{\alpha - 2} f(s) \,ds -\frac{t}{\varGamma (\alpha -1)} \int ^{T_{0}}_{0} (T_{0}-s)^{ \alpha - 2} f(s) \,ds \\ =& - \frac{1}{\varGamma (\alpha )} \int ^{t}_{0} (t-s)^{\alpha - 1} f(s) \,ds - \frac{1+t}{\varGamma (\alpha )} \int ^{1}_{0} (1-s)^{\alpha - 1} f(s) \,ds \\ &{}-\frac{1+t}{\varGamma (\alpha -1)} \int ^{T_{1}}_{0} (T_{1}-s)^{\alpha - 2} f(s) \,ds -\frac{t}{\varGamma (\alpha -1)} \int ^{T_{0}}_{0} (T_{0}-s)^{ \alpha - 2} f(s) \,ds. \end{aligned}

Now it is easy to check that $$x(t)= \int _{0}^{1} G(t,s) f(s)\,ds$$, where G is the given Green function. □

By using some usual calculations, we find that $$|G(t,s)| \leq \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} (1-s)^{\alpha -2}$$ for all $$t,s \in [0,1]$$ and $$|\frac{\partial G}{\partial t}(t,s)| \leq \frac{3 \alpha }{\varGamma (\alpha )} (1-s)^{\alpha -2}$$ for all $$t,s \in [0,1]$$. Also, it is easy to see that $$D^{\mu } x \in C[0,1]$$ and $$|D^{\mu } x| \leq \frac{ \Vert x' \Vert }{\varGamma (2-\mu )}$$ whenever $$x \in C^{1}[0,1]$$. Here, $$0 \leq \mu \leq 1$$. Now, consider the Banach space $$X= C^{1}[0,1]$$ with the norm $$\|x\|_{*} = \max \{ \|x\|, \|x' \| \}$$, $$\| \cdot \|$$ is the sup norm on $$C[0,1]$$. Assume that $$f=[f_{1},f_{2},f_{3},\lambda ,\mu ]$$. Define $$T:X \to X$$ by

\begin{aligned} T_{x}(t) =& \int _{0}^{1} G(t,s) f\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi , \phi \bigl(x(s) \bigr)\biggr) \,ds \\ =& - \frac{1}{\varGamma (\alpha )} \int ^{t}_{0} (t-s)^{\alpha - 1} f(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi , \phi \bigl(x(s) \bigr) \,ds \\ &{}- \frac{1+t}{\varGamma (\alpha )} \int ^{1}_{0} (1-s)^{\alpha - 1} f(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi , \phi \bigl(x(s) \bigr) \,ds \\ &{}-\frac{1+t}{\varGamma (\alpha -1)} \int ^{T_{1}}_{0} (T_{1}-s)^{\alpha - 2} f(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi , \phi \bigl(x(s) \bigr) \,ds \\ &{}-\frac{t}{\varGamma (\alpha -1)} \int ^{T_{0}}_{0} (T_{0}-s)^{\alpha - 2} f(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi , \phi \bigl(x(s) \bigr) \,ds \end{aligned}

for all $$x\in X$$ and $$t \in [0,1]$$. Note that the singular pointwise defined problem (1) has a solution if and only if T has a fixed point in X. We are going to investigate the singular pointwise defined problem (1) under two different conditions. Here. we present first one. In our second result we denote the map T by F.

### Theorem 5

Let $$f=[f_{1},f_{2},f_{3},\lambda ,\mu ]$$, $$f_{1}(t,0,0,0,0,0)=0$$, $$f_{2}(s,0,0,0,0,0)=0$$ and $$f_{3}(u,0,0,0, 0,0)=0$$ for all $$t \in [0, \lambda ]$$, $$s \in [0,\lambda ]$$ and $$u \in [\mu , 1]$$. Assume that there are nondecreasing maps $$\varLambda , \varLambda ': X \to [0, \infty )$$ and mappings $$a_{1}, a_{2}, a_{3}, a_{4} :(\lambda , \mu )\to [0, \infty )$$ such that $$\lim_{z\to 0^{+}} \frac{\varLambda (z)}{z} =q< \infty$$, $$\lim_{z\to 0^{+}} \frac{\varLambda '(z)}{z} =q< \infty$$ and $$\hat{a_{1}}, \hat{a_{2}}, \hat{a_{3}}, \hat{a_{4}} \in L^{1}[\lambda , \mu ]$$, where $$\hat{a_{i}}= (1-s)^{\alpha -2}$$ for $$i=1,2,3,4$$. Suppose that $$|f_{1}(t, x_{1}, \ldots, x_{5}) - f_{1}(t, y_{1}, \ldots, y _{5})| \leq \sum _{i=1}^{4} \varLambda (|x_{i} - y_{i}|)$$,

$$\bigl\vert f_{2}(t, x_{1}, \ldots, x_{5}) - f_{2}(t, y_{1}, \ldots, y_{5}) \bigr\vert \leq \sum _{i=1}^{4} a_{i}(t) \vert x_{i} - y_{i} \vert$$

and $$|f_{3}(t, x_{1}, \ldots, x_{5}) - f_{3}(t, y_{1}, \ldots, y_{5})| \leq \sum _{i=1}^{4} \varLambda ' (|x_{i} - y_{i}|)$$ for almost all $$t \in [0,1]$$ and every $$x_{1}, x_{2}, \ldots, x_{5}, y_{1}, y_{2}, \ldots, y_{5} \in X$$. If

$$\frac{4q}{\alpha -1} \bigl(1-(1-\lambda )^{\alpha -1}\bigr)+ \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + \frac{4q'}{\alpha -1} (1-\mu )^{ \alpha -1}< \frac{\varGamma (\alpha )}{l \theta _{0}},$$

then the pointwise defined equation (1) with boundary conditions has a solution, where $$\|h\|_{1}= m_{0}$$, $$l = \max \{ 1, \frac{1}{ \varGamma (2 - \beta )}, m_{0} \}$$ and $$\theta _{0}= \max \{ 3 \alpha , 2+ \alpha + T_{0} \}$$.

### Proof

Let $$x_{1}, x_{2} \in X$$ and $$t \in [0,1]$$. Then we have

\begin{aligned} \bigl\vert T_{x_{1}}(t)- T_{x_{2}}(t) \bigr\vert \leq{}& \int _{0}^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f\biggl(s, x_{1}(s), x'_{1}(s), D^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}(\xi )\,d \xi \biggr) \\ &{}- f\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h(\xi ) x _{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ \leq{}& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{1}\biggl(s, x_{1}(s), x'_{1}(s), D ^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}(\xi )\,d\xi \biggr) \\ &{}- f_{1}\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h( \xi ) x_{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{2}\biggl(s, x_{1}(s), x'_{1}(s), D ^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}(\xi )\,d\xi \biggr) \\ &{}- f_{2}\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h( \xi ) x_{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{3}\biggl(s, x_{1}(s), x'_{1}(s), D^{\beta }x _{1}(s), \int _{0}^{s} h(\xi ) x_{1}(\xi )\,d\xi \biggr) \\ &{}\times f_{3}\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h( \xi ) x_{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ \leq{}& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda \bigl( \bigl\vert x_{1}(s) - x_{2}(s) \bigr\vert \bigr)+ \varLambda \bigl( \bigl\vert x'_{1}(s) - x'_{2}(s) \bigr\vert \bigr) \\ &{}+ \varLambda \bigl( \bigl\vert D^{\beta } (x_{1} - x_{2}) (s) \bigr\vert \bigr) +\varLambda \biggl( \biggl\vert \int _{0}^{s} h( \xi ) \bigl(x_{1}(\xi ) - x_{2}(\xi )\bigr) \,d\xi \biggr\vert \biggr) \biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl[a_{1}(s) \bigl\vert x_{1}(s) - x_{2}(s) \bigr\vert + a _{2}(s) \bigl\vert x'_{1}(s) - x'_{2}(s) \bigr\vert \\ &{}+a_{3}(s) \bigl\vert D^{\beta } (x_{1} - x_{2}) (s) \bigr\vert +a_{4}(s) \biggl\vert \int _{0}^{s} h( \xi ) \bigl(x_{1}(\xi ) - x_{2}(\xi )\bigr) \,d\xi \biggr\vert \biggr] \,ds \\ &{}+ \int _{\mu }^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda ' \bigl( \bigl\vert x_{1}(s) - x_{2}(s) \bigr\vert \bigr)+ \varLambda ' \bigl( \bigl\vert x'_{1}(s) - x'_{2}(s) \bigr\vert \bigr) \\ &{}+ \varLambda ' \bigl( \bigl\vert D^{\beta } (x_{1} - x_{2}) (s) \bigr\vert \bigr) +\varLambda ' \biggl( \biggl\vert \int _{0} ^{s} h(\xi ) \bigl(x_{1}(\xi ) - x_{2}(\xi )\bigr) \,d\xi \biggr\vert \biggr) \biggr] \,ds \\ \leq{}& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda \bigl( \Vert x_{1} - x_{2} \Vert \bigr)+ \varLambda \bigl( \bigl\Vert x'_{1} - x'_{2} \bigr\Vert \bigr) \\ &{}+ \varLambda \bigl( \bigl\Vert D^{\beta } (x_{1} - x_{2}) \bigr\Vert \bigr) +\varLambda \biggl( \int _{0}^{s} |h( \xi ) \bigl\vert \Vert x_{1}- x_{2} \Vert \,d\xi \bigr\vert \biggr) \biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl[a_{1}(s) \Vert x_{1} - x_{2} \Vert + a _{2}(s) \bigl\Vert x'_{1} - x'_{2} \bigr\Vert \\ &{}+ a_{3}(s) \bigl\Vert D^{\beta } (x_{1} - x_{2}) \bigr\Vert +a_{4}(s) \int _{0}^{s} |h( \xi ) \bigl\vert \Vert x_{1} - x_{2} \Vert \,d\xi \bigr\vert \biggr] \,ds \\ &{}+ \int _{\mu }^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda ' \bigl( \Vert x_{1} - x_{2} \Vert \bigr)+ \varLambda ' \bigl( \bigl\Vert x'_{1} - x'_{2} \bigr\Vert \bigr) \\ &{}+ \varLambda ' \bigl(|D^{\beta } \Vert x_{1} - x_{2} \Vert \bigr) +\varLambda ' \biggl( \int _{0}^{s} |h(\xi ) \bigl\vert \Vert x_{1} - x_{2} \Vert \,d\xi \bigr\vert \biggr) \biggr] \,ds \\ \leq{}& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda \bigl( \Vert x_{1} - x_{2} \Vert \bigr)+ \varLambda \bigl( \bigl\Vert x'_{1} - x'_{2} \bigr\Vert \bigr) \\ &{}+ \varLambda \biggl( \frac{ \Vert x'_{1} - x'_{2} \Vert }{\varGamma (2- \beta )}\biggr) +\varLambda \bigl(m_{0} \Vert x_{1}- x_{2} \Vert \bigr) \biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl[a_{1}(s) \Vert x_{1} - x_{2} \Vert + a _{2}(s) \bigl\Vert x'_{1} - x'_{2} \bigr\Vert \\ &{}+ a_{3}(s) \frac{ \Vert x'_{1} - x'_{2} \Vert }{\varGamma (2- \beta )} +a_{4}(s) m _{0} \Vert x_{1} - x_{2} \Vert \biggr] \,ds \\ &{}+ \int _{\mu }^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda ' \bigl( \Vert x_{1} - x_{2} \Vert \bigr)+ \varLambda ' \bigl( \bigl\Vert x'_{1} - x'_{2} \bigr\Vert \bigr) \\ &{}+ \varLambda ' \biggl(\frac{ \Vert x'_{1} - x'_{2} \Vert }{\varGamma (2- \beta )}\biggr) +\varLambda ' \bigl( m_{0} \Vert x_{1} - x_{2} \Vert \bigr) \biggr] \,ds \\ \leq{}& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda \bigl(l \Vert x_{1} - x_{2} \Vert _{*}\bigr)+ \varLambda \bigl(l \Vert x_{1} - x_{2} \Vert _{*}\bigr) \\ &{}+ \varLambda \biggl( \frac{l \Vert x_{1} - x_{2} \Vert _{*}}{\varGamma (2- \beta )}\biggr) + \varLambda \bigl(m_{0} l \Vert x_{1} - x_{2} \Vert _{*} \bigr) \biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl[a_{1}(s) l \Vert x_{1} - x_{2} \Vert _{*} + a_{2}(s) l \Vert x_{1} - x_{2} \Vert _{*} \\ &{}+ a_{3}(s) \frac{l \Vert x_{1} - x_{2} \Vert _{*}}{\varGamma (2- \beta )} +a_{4}(s) m_{0} l \Vert x_{1} - x_{2} \Vert _{*}\biggr] \,ds \\ &{}+ \int _{\mu }^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda ' \bigl(l \Vert x_{1} - x_{2} \Vert _{*}\bigr)+ \varLambda ' \bigl(l \Vert x_{1} - x_{2} \Vert _{*}\bigr) \\ &{}+ \varLambda ' \biggl(\frac{l \Vert x_{1} - x_{2} \Vert _{*}}{\varGamma (2- \beta )}\biggr) + \varLambda ' \bigl( m_{0} l \Vert x_{1} - x_{2} \Vert _{*}\bigr) \biggr] \,ds, \end{aligned}
(*)

where $$m_{0}= \int _{0}^{1}|h(\xi )|\,d\xi$$ and $$l= \max \{1, \frac{1 }{ \varGamma (2-\beta )}, m_{0}, \theta _{0}+\theta _{1} \}$$. On the other hand, $$\lim_{z \to 0^{+}} \frac{\varLambda (z)}{z}=q$$ and so for each $$\epsilon >0$$ there exists $$0<\delta _{\varLambda }= \delta (\epsilon , \varLambda )$$ such that $$| \frac{\varLambda (z)}{z}- q| <\epsilon$$ for all $$0< z \leq \delta _{\varLambda }$$. Thus, $$0< z \leq \delta _{\varLambda }$$ implies $$| \frac{\varLambda (z)}{z}| -q \leq | \frac{\varLambda (z)}{z} -q|< \epsilon$$. Hence, $$| \varLambda (z)|< (\epsilon +q)|z|$$. By choosing $$0< z \leq \delta _{1} := \min \{ \delta _{\varLambda }, \epsilon \}$$, we have

\begin{aligned} \bigl\vert \varLambda (z) \bigr\vert < (\epsilon +q) \vert z \vert < (\epsilon +q) \epsilon . \end{aligned}
(2)

For $$\varLambda '$$ we have similar conclusion, that is,

\begin{aligned} \bigl\vert \varLambda '(z) \bigr\vert < \bigl( \epsilon +q'\bigr) \epsilon \end{aligned}
(3)

for all $$0< z \leq \delta _{1} := \min \{ \delta _{\varLambda '}, \epsilon \}$$. Let $$\epsilon >0$$ be given, $$l \|x_{1} - x_{2}\|_{*} < \min \{ \delta _{1}, \delta _{2} \}$$ and $$x_{1} \to x_{2}$$. By using (2) and (3), we get $$\varLambda ( l \|x_{1} - x_{2}\|_{*} )< ( \epsilon +q) \epsilon$$ and $$\varLambda '( l \|x_{1} - x_{2}\|_{*} )< ( \epsilon +q') \epsilon$$. Now by using (*), we obtain

\begin{aligned} &\bigl\vert T_{x_{1}}(t)- T_{x_{2}}(t) \bigr\vert \\ &\quad \leq 4(q+ \epsilon )\epsilon \int _{0}^{ \lambda } \bigl\vert G(t,s) \bigr\vert \,ds + \epsilon \int _{\lambda }^{\mu } \bigl[a_{1}(s)+ \cdots+ a_{4}(s)\bigr] \bigl\vert G(t,s) \bigr\vert \,ds \\ &\qquad {}+ 4\bigl(q'+\epsilon \bigr)\epsilon \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \,ds \leq 4(q+\epsilon )\epsilon \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \int _{0}^{\lambda } (1-s)^{\alpha -2}\,ds \\ &\qquad {}+ \frac{\epsilon (2+ \alpha + T_{0})}{\varGamma (\alpha )} \sum _{i=1} ^{4} \int _{\lambda }^{\mu } a_{i}(s) (1-s)^{\alpha -2}\,ds+ 4\bigl(q'+\epsilon \bigr)\epsilon \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \int _{\mu }^{1} (1-s)^{ \alpha -2}\,ds \\ &\quad = \epsilon \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \Biggl[4(q+\epsilon ) \cdot \frac{1}{\alpha -1} \bigl(1-(1-\lambda )^{\alpha -1} \bigr)\\ &\qquad {}+ \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + 4\bigl(q'+ \epsilon \bigr) \cdot \frac{1}{ \alpha -1} (1- \mu )^{\alpha -1} \Biggr]. \end{aligned}

Hence,

\begin{aligned} \Vert T_{x_{1}}- T_{x_{2}} \Vert \leq& \epsilon \frac{2+ \alpha + T_{0}}{ \varGamma (\alpha )} \Biggl[4(q+\epsilon ) \cdot \frac{1}{\alpha -1} \bigl(1-(1-\lambda )^{\alpha -1} \bigr) \\ &{}+ \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + 4\bigl(q'+\epsilon \bigr) \cdot \frac{1}{\alpha -1} (1- \mu )^{\alpha -1} \Biggr]. \end{aligned}

In a similar way, we get

\begin{aligned} &\bigl\vert T'_{x_{1}}(t)- T'_{x_{2}}(t) \bigr\vert \\ &\quad \leq \int _{0}^{1} \biggl\vert \frac{\partial G}{ \partial t} (t,s) \biggr\vert \biggl\vert f\biggl(s, x_{1}(s), x'_{1}(s), D^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}(\xi )\,d\xi \biggr) \\ &\qquad {}- f\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h(\xi ) x _{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &\quad \leq \int _{0}^{\lambda } \biggl\vert \frac{\partial G}{\partial t} (t,s) \biggr\vert \biggl\vert f_{1}\biggl(s, x_{1}(s), x'_{1}(s), D^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}( \xi )\,d\xi \biggr) \\ &\qquad {}- f_{1}\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h( \xi ) x_{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &\qquad {}+ \int _{\lambda }^{\mu } \biggl\vert \frac{\partial G}{\partial t} (t,s) \biggr\vert \biggl\vert f_{2}\biggl(s, x_{1}(s), x'_{1}(s), D^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}( \xi )\,d\xi \biggr) \\ &\qquad {}- f_{2}\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h( \xi ) x_{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &\qquad {}+ \int _{\mu }^{1} \biggl\vert \frac{\partial G}{\partial t} (t,s) \biggr\vert \biggl\vert f_{3}\biggl(s, x _{1}(s), x'_{1}(s), D^{\beta }x_{1}(s), \int _{0}^{s} h(\xi ) x_{1}( \xi )\,d\xi \biggr) \\ &\qquad {}- f_{3}\biggl(s, x_{2}(s), x'_{2}(s), D^{\beta }x_{2}(s), \int _{0}^{s} h( \xi ) x_{2}(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &\quad \leq 4(q+\epsilon )\epsilon \int _{0}^{\lambda } \biggl\vert \frac{\partial G}{ \partial t} (t,s) \biggr\vert \,ds + \epsilon \int _{\lambda }^{\mu } \bigl[a_{1}(s)+ \cdots+ a_{4}(s)\bigr] \bigl\vert G(t,s) \bigr\vert \,ds \\ &\qquad {}+ 4\bigl(q'+\epsilon \bigr)\epsilon \int _{\mu }^{1} \biggl\vert \frac{\partial G}{\partial t} (t,s) \biggr\vert \,ds \leq 4(q+\epsilon ) \frac{3 \epsilon \alpha }{\varGamma ( \alpha )} \int _{0}^{\lambda } (1-s)^{\alpha -2}\,ds \\ &\qquad {}+ \frac{3 \epsilon \alpha }{\varGamma (\alpha )} \sum _{i=1}^{4} \int _{\lambda }^{\mu } a_{i}(s) (1-s)^{\alpha -2}\,ds + 4\bigl(q'+\epsilon \bigr) \frac{3 \epsilon \alpha }{\varGamma (\alpha )} \int _{\mu }^{1} (1-s)^{ \alpha -2}\,ds \\ &\quad = \frac{3 \epsilon \alpha }{\varGamma (\alpha )} \Biggl[4(q+\epsilon ) \cdot \frac{1}{ \alpha -1} \bigl(1-(1- \lambda )^{\alpha -1} \bigr) \\ &\qquad {}+ \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + 4\bigl(q'+\epsilon \bigr) \cdot \frac{1}{\alpha -1} (1- \mu )^{\alpha -1} \Biggr] \end{aligned}

and so

\begin{aligned} \bigl\Vert T'_{x_{1}}- T'_{x_{2}} \bigr\Vert \leq & \frac{3 \epsilon \alpha }{\varGamma (\alpha )} \Biggl[4(q+\epsilon ) \cdot \frac{1}{\alpha -1} \bigl(1-(1-\lambda )^{ \alpha -1} \bigr) \\ &{} + \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + 4\bigl(q'+ \epsilon \bigr) \cdot \frac{1}{\alpha -1} (1- \mu )^{\alpha -1} \Biggr]. \end{aligned}

Hence,

\begin{aligned} \Vert T_{x_{1}}- T_{x_{2}} \Vert _{*} \leq & \epsilon \Biggl[4(q+\epsilon ) \cdot \frac{1}{ \alpha -1} \bigl(1-(1-\lambda )^{\alpha -1} \bigr) + \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} \\ & {}+ 4\bigl(q'+\epsilon \bigr) \cdot \frac{1}{\alpha -1} (1- \mu )^{\alpha -1} \Biggr] \max \biggl\{ \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )}, \frac{3 \alpha }{ \varGamma (\alpha )} \biggr\} . \end{aligned}

This implies that $$\|T_{x_{1}}- T_{x_{2}}\|_{*} \to 0$$ as $$x_{1} \to x_{2}$$. Hence, T is continuous. Since $$\lim_{z\to 0^{+}} \frac{ \varLambda (z)}{z} =q$$ and Λ is nondecreasing, for each $$\epsilon >0$$ there exists $$\delta _{1}= \delta _{1}(\epsilon )>0$$ such that $$\frac{\varLambda (l z)}{ l z} < q+ \epsilon$$ for all $$z\in (0, \delta _{1}]$$. Thus, $$\varLambda (l z) < (q+ \epsilon ) l z$$. By using similar reason, there exists $$\delta _{2}(\epsilon )>0$$ such that $$\varLambda '(l z) < (q'+ \epsilon ) l z$$ for all $$z\in (0,\delta _{2}]$$. Put $$\delta = \delta ( \epsilon ) := \min \{ \delta _{1}( \epsilon ), \delta _{2}( \epsilon ) \}$$. Then $$\varLambda (l z) < (q+ \epsilon ) l z$$ and $$\varLambda '(l z) < (q'+ \epsilon ) l z$$ for all $$z\in (0,\delta ]$$. In particular, $$\varLambda (l \delta ) < (q+ \epsilon ) l \delta$$ and $$\varLambda '(l \delta ) < (q'+ \epsilon ) l \delta$$. On other hand, we have $$\frac{4q}{\alpha -1} (1-(1-\lambda )^{\alpha -1})+ \sum _{i=1} ^{4} \| \hat{a_{i}}\|_{[\lambda , \mu ]} + \frac{4q'}{\alpha -1} (1- \mu )^{\alpha -1}< \frac{\varGamma (\alpha )}{l \theta _{0}}$$. Choose $$\epsilon _{0}>0$$ such that $$\frac{4(q+\epsilon _{0})}{\alpha -1} (1-(1- \lambda )^{\alpha -1})+ \sum _{i=1}^{4} \| \hat{a_{i}}\|_{[\lambda , \mu ]} + \frac{4(q' +\epsilon _{0})}{\alpha -1} (1-\mu )^{\alpha -1}< \frac{ \varGamma (\alpha )}{l \theta _{0}}$$ and put $$\delta _{0}= \delta (\epsilon _{0})$$. Then $$\varLambda (l \delta _{0}) < (q+ \epsilon ) l \delta _{0}$$ and $$\varLambda '(l \delta _{0}) < (q'+ \epsilon ) l \delta _{0}$$. Now, assume that $$E= \{ x \in X : \|x\|_{*}< \delta _{0} \}$$, $$x \in E$$ and $$t \in [0,1]$$. Then we have

\begin{aligned} \bigl\vert T_{x}(t) \bigr\vert \leq& \int _{0}^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ =& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{2}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{3}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ =& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) -f_{1}(s,0,0,0,0,0) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{2}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) -f_{2}(s,0,0,0,0,0) \biggr\vert \,ds \\ &{}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{3}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) -f_{3}(s,0,0,0,0,0) \biggr\vert \,ds \\ \leq& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda \bigl( \bigl\vert x(s) \bigr\vert \bigr) +\varLambda \bigl( \bigl\vert x'(s) \bigr\vert \bigr) +\varLambda \bigl( \bigl\vert D^{\beta }x(s) \bigr\vert \bigr) \\ &{}+ \varLambda \biggl( \int _{0}^{s} \bigl\vert h( \xi ) \bigr\vert \bigl\vert x(\xi ) \bigr\vert \,d\xi \biggr)\biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl[ a_{1}(s) \bigl\vert x(s) \bigr\vert + a_{2}(s) \bigl\vert x'(s) \bigr\vert + a_{3}(s) \bigl\vert D^{\beta }x(s) \bigr\vert \\ &{} + a_{4}(s) \int _{0}^{s} \bigl\vert h(\xi ) \bigr\vert \bigl\vert x(\xi ) \bigr\vert \,d\xi \biggr] \,ds \\ &{}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda '\bigl( \bigl\vert x(s) \bigr\vert \bigr) + \varLambda '\bigl( \bigl\vert x'(s) \bigr\vert \bigr) + \varLambda '\bigl( \bigl\vert D^{\beta }x(s) \bigr\vert \bigr) \\ &{} + \varLambda '\biggl( \int _{0}^{s} \bigl\vert h(\xi ) \bigr\vert \bigl\vert x( \xi ) \bigr\vert \,d\xi \biggr)\biggr] \,ds \\ \leq& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda \bigl( \Vert x \Vert \bigr) +\varLambda \bigl( \bigl\Vert x' \bigr\Vert \bigr) +\varLambda \biggl(\frac{ \Vert x' \Vert }{\varGamma (2- \beta )}\biggr) + \varLambda \bigl( m_{0} \Vert x \Vert \bigr)\biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl[ a_{1}(s) \Vert x \Vert + a_{2}(s) \bigl\Vert x' \bigr\Vert + a_{3}(s) \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}+ a_{4}(s) m_{0} \Vert x \Vert \biggr] \,ds \\ &{}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl[ \varLambda '\bigl( \Vert x \Vert \bigr) +\varLambda '\bigl( \bigl\Vert x' \bigr\Vert \bigr) + \varLambda '\biggl(\frac{ \Vert x' \Vert }{\varGamma (2- \beta )}\biggr) + \varLambda '\bigl( m_{0} \Vert x \Vert \bigr)\biggr] \,ds \\ \leq& 4 \varLambda \bigl(l \Vert x \Vert _{*}\bigr) \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \,ds \\ &{}+ l \Vert x \Vert _{*} \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \sum _{i=1}^{4} a_{i}(s) \,ds + 4 \varLambda \bigl(l \Vert x \Vert _{*}\bigr) \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \,ds \\ \leq& 4 \varLambda (l \delta _{0}) \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \int _{0}^{\lambda } (1-s)^{\alpha -2} \,ds \\ &{}+ l \delta _{0} \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \sum _{i=1} ^{4} \int _{\lambda }^{\mu } a_{i}(s) (1-s)^{\alpha -2} \,ds \\ &{}+ 4 \varLambda '(l \delta _{0}) \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \int _{ \mu }^{1} (1-s)^{\alpha -2} \,ds \\ \leq& 4(q+\epsilon _{0}) l \delta _{0} \frac{(2+ \alpha + T_{0})}{\varGamma (\alpha )}\cdot \frac{1}{\alpha -1}\bigl[1-(1-\lambda )^{\alpha -1}\bigr] \\ &{}+ l \delta _{0} \frac{(2+ \alpha + T_{0})}{\varGamma (\alpha )} \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} \\ &{}+ 4(q+\epsilon _{0}) l \delta _{0} \frac{(2+ \alpha + T_{0})}{\varGamma ( \alpha )}\cdot \frac{1}{\alpha -1}\bigl[1-(1-\lambda )^{\alpha -1}\bigr] \\ =&\delta _{0} \frac{(2+ \alpha + T_{0}) l}{\varGamma (\alpha )}[ \frac{4(q+ \epsilon _{0})}{\alpha -1} \bigl(1-(1- \lambda )^{\alpha -1}\bigr)\\ &{}+ \sum _{i=1} ^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + \frac{4(q' +\epsilon _{0})}{ \alpha -1} (1-\mu )^{\alpha -1}< \delta _{0}. \end{aligned}

Hence, $$\|Tx\| \leq \delta _{0}$$. By using a similar method, we get

\begin{aligned} \bigl\vert T'_{x}(t) \bigr\vert \leq& \int _{0}^{1} \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl\vert f\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d \xi \biggr) \biggr\vert \,ds \\ =& \int _{0}^{\lambda } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggr\vert f_{2}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggl\vert \,ds \\ &{}+ \int _{\mu }^{1} \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggr\vert f_{3}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr)\biggr| \,ds \\ \leq& \int _{0}^{\lambda } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl[ \varLambda \bigl( \bigl\vert x(s) \bigr\vert \bigr) + \varLambda \bigl( \bigl\vert x'(s) \bigr\vert \bigr) +\varLambda \bigl( \bigl\vert D^{\beta }x(s) \bigr\vert \bigr) \\ &{}+ \varLambda \biggl( \int _{0}^{s} \bigl\vert h(\xi ) \bigr\vert \bigl\vert x(\xi ) \bigr\vert \,d\xi \biggr)\biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl[ a_{1}(s) \bigl\vert x(s) \bigr\vert + a_{2}(s) \bigl\vert x'(s) \bigr\vert + a_{3}(s) \bigl\vert D^{\beta }x(s) \bigr\vert \\ &{} + a_{4}(s) \int _{0}^{s} \bigl\vert h(\xi ) \bigr\vert \bigl\vert x(\xi ) \bigr\vert \,d\xi \biggr] \,ds \\ &{}+ \int _{\mu }^{1} \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl[ \varLambda '\bigl( \bigl\vert x(s) \bigr\vert \bigr) +\varLambda '\bigl( \bigl\vert x'(s) \bigr\vert \bigr) +\varLambda '\bigl( \bigl\vert D^{\beta }x(s) \bigr\vert \bigr) \\ &{}+ \varLambda '\biggl( \int _{0}^{s} \bigl\vert h(\xi ) \bigr\vert \bigl\vert x(\xi ) \bigr\vert \,d\xi \biggr)\biggr] \,ds \\ \leq& \int _{0}^{\lambda } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl[ \varLambda \bigl( \Vert x \Vert \bigr) +\varLambda \bigl( \bigl\Vert x' \bigr\Vert \bigr) +\varLambda \biggl( \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}\biggr) + \varLambda \bigl( m_{0} \Vert x \Vert \bigr)\biggr] \,ds \\ &{}+ \int _{\lambda }^{\mu } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl[ a _{1}(s) \Vert x \Vert + a_{2}(s) \bigl\Vert x' \bigr\Vert + a_{3}(s) \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}+ a_{4}(s) m_{0} \Vert x \Vert \biggr] \,ds \\ &{}+ \int _{\mu }^{1} \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \biggl[ \varLambda '\bigl( \Vert x \Vert \bigr) + \varLambda '\bigl( \bigl\Vert x' \bigr\Vert \bigr) + \varLambda '\biggl( \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}\biggr) + \varLambda '\bigl( m_{0} \Vert x \Vert \bigr)\biggr] \,ds \\ \leq& 4 \varLambda \bigl(l \Vert x \Vert _{*}\bigr) \int _{0}^{\lambda } \biggl\vert \frac{ \partial G}{ \partial t}(t,s) \biggr\vert \,ds + l \Vert x \Vert _{*} \int _{\lambda }^{\mu } \biggl\vert \frac{ \partial G}{\partial t}(t,s) \biggr\vert \sum _{i=1}^{4} a_{i}(s) \,ds + 4 \varLambda \bigl(l \Vert x \Vert _{*}\bigr) \\ &{}\times \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \,ds\leq 4 \varLambda (l \delta _{0}) \frac{3 \alpha }{\varGamma (\alpha )} \int _{0}^{\lambda } (1-s)^{\alpha -2} \,ds \\ &{}+ l \delta _{0} \frac{3 \alpha }{\varGamma (\alpha )} \sum _{i=1}^{4} \int _{\lambda }^{\mu } a_{i}(s) (1-s)^{\alpha -2} \,ds+ 4 \varLambda '(l \delta _{0}) \frac{3 \alpha }{\varGamma (\alpha )} \int _{\mu }^{1} (1-s)^{ \alpha -2} \,ds \\ \leq& 4(q+\epsilon _{0}) l \delta _{0} \frac{3 \alpha }{\varGamma (\alpha )}\cdot \frac{1}{\alpha -1}\bigl[1-(1-\lambda )^{\alpha -1}\bigr] + l \delta _{0} \frac{3 \alpha }{\varGamma (\alpha )} \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} \\ &{}+ 4(q+\epsilon _{0}) l \delta _{0} \frac{3 \alpha }{\varGamma (\alpha )}\cdot \frac{1}{ \alpha -1}\bigl[1-(1-\lambda )^{\alpha -1}\bigr] \\ =&\delta _{0} \frac{3 \alpha l}{\varGamma (\alpha )}\Biggl[ \frac{4(q+\epsilon _{0})}{\alpha -1} \bigl(1-(1- \lambda )^{\alpha -1}\bigr)+ \sum _{i=1}^{4} \Vert \hat{a_{i}} \Vert _{[\lambda , \mu ]} + \frac{4(q' +\epsilon _{0})}{\alpha -1} (1-\mu )^{\alpha -1}\Biggr]\\ < & \delta _{0} \end{aligned}

for all $$x \in E$$ and $$t \in [0,1]$$. Hence, $$\|Tx\| \leq \delta _{0}$$, and so $$\|Tx\|_{*} \leq \delta _{0}$$. Thus, T maps E into E. It is easy to check that T maps bounded sets into bounded sets. Assume that $$t_{1}, t_{2} \in [0,1]$$ and $$x \in E$$. Since $$G(t,s)$$ and $$\frac{ \partial G(t,s)}{\partial t}$$ are continuous with respect to t, we get

\begin{aligned} \lim_{t_{2} \to t_{1}} T'x(t_{2}) =&\lim _{t_{2} \to t_{1}} \int _{0} ^{1} \biggl\vert \frac{ \partial G}{\partial t}(t_{2}, s) \biggr\vert \biggl\vert f\biggl(s, x(s), x'(s), D ^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ =& \int _{0}^{1} \lim_{t_{2} \to t_{1}} \frac{ \partial G}{\partial t}(t _{2}, s) f\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x( \xi )\,d\xi \biggr) \,ds \\ =& \int _{0}^{1} \frac{ \partial G}{\partial t}(t_{1}, s) f\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \,ds\\ =& T'x(t _{1}). \end{aligned}

Hence, T is equi-continuous on E and so $$T: E \to E$$ is completely continuous. Now by using Lemma 2, T has a fixed point on E and so the problem (1) has a solution. □

### Example 1

Consider the pointwise defined equation

$$D^{\frac{7}{2}} x(t) +f\biggl(t, x(t), x'(t), D^{\frac{1}{2}} x(t), \int _{0}^{t} s x(s) \,ds\biggr)=0$$

with the boundary conditions in the last result, where

$$f(t, x_{1}, x_{2}, x_{3}, x_{4}, x_{5})= \textstyle\begin{cases} t \sum _{i=1}^{4} x_{i}, & 0 \leq t < 0.2, \\ d(t) \sum _{i=1}^{4} x_{i}, & 0.2 \leq t \leq 0.8, \\ t^{2} \sum _{i=1}^{4} x_{i}, & 0.8 < t \leq 1, \end{cases}$$

and $$d(t)=0$$ whenever $$t \in [0.1, 0.8] \cap Q$$ and $$d(t)=0.1$$ whenever $$t \in [0.1, 0.8] \cap Q^{c}$$. Now, put $$f_{1}(t, x_{1}, x_{2}, x_{3}, x_{4}, x_{5})= \frac{1}{2} t \sum _{i=1}^{4} x_{i}$$, $$f_{2}(t, x_{1}, x_{2}, x_{3}, x_{4}, x_{5})= d(t) \sum _{i=1}^{4} x_{i}$$ and $$f_{3}(t, x_{1}, x_{2}, x_{3}, x_{4}, x_{5})= t^{2} \sum _{i=1}^{4} x _{i}$$. Then we have $$f_{1}(t, 0, 0, 0, 0)= f_{2}(t, 0, 0, 0, 0) = f _{3}(t, 0, 0, 0, 0) =0$$,

\begin{aligned} \bigl\vert f_{1}(t, x_{1}, x_{2}, x_{3}, x_{4})- f_{1}(t, y_{1}, y_{2}, y_{3}, y _{4}) \bigr\vert \leq& t \sum _{i=1}^{4} \bigl\vert \vert x_{i} \vert - \vert y_{i} \vert \bigr\vert \\ \leq& t \sum _{i=1}^{4} \vert x_{i} - y_{i} \vert \leq 0.1 \sum _{i=1}^{4} \varLambda \bigl( \vert x_{i} - y_{i} \vert \bigr), \\ \bigl\vert f_{2}(t, x_{1}, x_{2}, x_{3}, x_{4})- f_{2}(t, y_{1}, y_{2}, y_{3}, y _{4}) \bigr\vert \leq& d(t) \sum _{i=1}^{4} \bigl\vert \vert x_{i} \vert - \vert y_{i} \vert \bigr\vert \\ \leq& d(t) \sum _{i=1}^{4} \vert x_{i} - y_{i} \vert , \end{aligned}

and

\begin{aligned} \bigl\vert f_{3}(t, x_{1}, x_{2}, x_{3}, x_{4})- f_{3}(t, y_{1}, y_{2}, y_{3}, y _{4}) \bigr\vert \leq& \frac{1}{2} t \sum _{i=1}^{4} \bigl\vert \vert x_{i} \vert - \vert y_{i} \vert \bigr\vert \\ \leq& \frac{1}{2} t \sum _{i=1}^{4} \vert x_{i} - y_{i} \vert \leq \frac{1}{2} \sum _{i=1}^{4} \varLambda \bigl( \vert x_{i} - y_{i} \vert \bigr), \end{aligned}

where $$\varLambda (x) = |x|$$ and $$\varLambda ' (x) =\frac{1}{2} |x|$$. Hence, $$\lim_{z \to 0^{+}} \frac{\varLambda ' (z)}{z} = 0.1:= q$$, $$\lim_{z \to 0^{+}} \frac{\varLambda ' (z)}{z} = \frac{1}{2}:= q'$$, $$\hat{a_{i}}= \hat{d} \in L^{1}[0.1, 0.8]$$, $$\sum _{i=1}^{4} \| \hat{a_{i}}\|_{[\lambda , \mu ]}< 0.092$$ and

\begin{aligned} & \Biggl[ \frac{4q (1-(1-\lambda )^{\alpha -1})}{\alpha -1} + \sum _{i=1} ^{4} \Vert \hat{a_{i}} \Vert + \frac{4q' }{\alpha -1} (1-\mu )^{\alpha -1}\Biggr] \\ &\quad < \biggl[ \frac{4 \times 0.1 (1-(1-0.1)^{\frac{5}{2}}}{\frac{5}{2}}+ 0.092 +\frac{4 \times 0.5 (1-0.9)^{\frac{5}{2}}}{\frac{5}{2}} \biggr] < \frac{ \varGamma (\alpha )}{3l \alpha }. \end{aligned}

Now by using Theorem 5, the problem has a solution.

Now, we present our second result by using different conditions.

### Theorem 6

Suppose that $$f=[f_{1},f_{2},f_{3},\lambda ,\mu ]$$, f is nonnegative on $$[0,1]$$ and there exist nonnegative functions $$a_{1},a_{2}, a_{3}, a_{4}:[0,\lambda ] \to \mathbb{R}^{+}$$, maps $$b_{1},\dots , b_{k_{0}}:[ \lambda , \mu ] \to \mathbb{R}^{+}$$ for some $$k_{0} \geq 1$$, and functions $$c_{1},c_{2}, c_{3}, c_{4}:[\mu , 1] \to \mathbb{R}^{+}$$ such that $$\hat{a_{i}} \in L^{1}[0,\lambda ]$$, $$\hat{b_{j}} \in L^{1}[ \lambda , \mu ]$$, $$\hat{c_{i}} \in L^{1}[\mu , 1]$$ and $$\hat{a_{1}}(s) =(1-s)^{\alpha -2} a_{i}(s)$$. Assuming that there are nonnegative and nondecreasing functions $$\phi _{i}, \varPhi _{i} : \mathbb{R}^{+} \to \mathbb{R}^{+}$$ and $$H_{j}: \mathbb{R_{+}}^{4} \to \mathbb{R}_{+}$$ such that $$\lim_{z \to 0^{+}} \frac{\phi _{i}(z)}{z^{\mu _{i}} }:= l_{\mu _{i}}< \infty$$, $$\lim_{z \to 0^{+}} \frac{\varPhi _{i}(z)}{z^{\gamma _{i}} }:= l_{\gamma _{i}}< \infty$$ and $$\lim_{z \to 0^{+}} \frac{H_{j}(z, z, z, z)}{z^{m} }:=q_{j}< \infty$$ for some $$\mu _{i}, \gamma _{i}, m \in [1, \infty )$$ and $$H_{j}$$ are nonnegative and nondecreasing with respect to all their components ($$1 \leq i \leq 4$$, $$1 \leq j \leq k _{0}$$),

\begin{aligned}& \bigl\vert f_{1}(t, x_{1}, \ldots, x_{4}) - f_{1}(t, y_{1}, \ldots, y_{4}) \bigr\vert \leq \sum _{i=1}^{4} a_{i}(t) \phi _{i} \bigl( \vert x_{i} - y_{i} \vert \bigr), \\& \bigl\vert f_{2}(t, x_{1}, \ldots, x_{4}) - f_{2}(t, y_{1}, \ldots, y_{4}) \bigr\vert \leq \sum _{i=1}^{5} b_{j}(t) H_{j} \bigl( \vert x_{1} - y_{1} \vert , \ldots, \vert x_{4} - y _{4} \vert \bigr) \end{aligned}

and $$|f_{3}(t, x_{1}, \ldots, x_{4}) - f_{3}(t, y_{1}, \ldots, y_{4})| \leq \sum _{i=1}^{4} c_{i}(t) \varPhi _{i}(| x_{i} - y_{i} |)$$. Suppose that $$|f_{2}(t, x_{1}, \ldots, x_{4})| \leq \varTheta (t) \varLambda (x_{1}, \ldots, x_{4})$$, where Λ are nonnegative and nondecreasing with respect to all their components, $$\lim_{x \to 0^{+}} \frac{\varLambda (x, x, x, x)}{x }:=P_{2},< \infty$$, $$\hat{\varTheta } \in L^{1}[\lambda , \mu ]$$, $$\lim_{\max |x_{i}| \to 0} \frac{|f_{1}(t, x_{1}, \ldots, x_{4})|}{ \max |x_{i}|} =P_{1}(t)$$ and $$\lim_{\max |x_{i}| \to 0} \frac{|f_{3}(t, x_{1}, \ldots, x_{4})|}{\max |x_{i}|} =P_{3}(t)$$, where $$\hat{P_{1}} \in L^{1}[0, \lambda ]$$, $$\hat{P_{3}} \in L^{1}[\mu , 1]$$. If

\begin{aligned}& \begin{gathered} \max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T_{0}}{ \varGamma (\alpha ) } \biggr\} \max \Biggl\{ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} ) + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} q_{j} \\ \quad {}+\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} ] ( l_{\gamma _{i}} ) , \max \biggl\{ 1, \frac{1}{\varGamma (2- \beta ) }, m_{0} \biggr\} \bigl[ \Vert \hat{P_{1}} \Vert _{[0, \lambda ]} + P_{2} \Vert \varTheta \Vert _{[\lambda , \mu ]} + \Vert \hat{P_{3}} \Vert _{[\mu , 1]}\bigr] \Biggr\} < 1, \end{gathered} \end{aligned}

then the pointwise defined equation (1) with boundary conditions has a solution.

### Proof

Let $$x,y \in X$$ and $$t \in [0,1]$$. Then we have

\begin{aligned}& \bigl\vert F_{x}(t)-F_{y}(t) \bigr\vert \\& \quad \leq \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \\& \qquad {}-f_{1}\biggl(s, y(s), y'(s), D^{\beta }y(s), \int _{0}^{s} h(\xi ) y(\xi )\,d \xi \biggr) \biggr\vert \,ds \\& \qquad {}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{2}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \\& \qquad {}-f_{2}\biggl(s, y(s), y'(s), D^{\beta }y(s), \int _{0}^{s} h(\xi ) y(\xi )\,d \xi \biggr) \biggr\vert \,ds \\& \qquad {}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{3}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \\& \qquad {}- f_{3}\biggl(s, y(s), y'(s), D^{\beta }y(s), \int _{0}^{s} h(\xi ) y(\xi )\,d \xi \biggr) \biggr\vert \,ds \\& \quad \leq \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert [a_{1}(s) \phi \bigl( \bigl\vert x(s) - y(s) \bigr\vert \bigr)+ a _{2}(s) \phi \bigl( \bigl\vert x'(s) - y'(s) \bigr\vert \bigr) \\& \qquad {}+ a_{3}(s) \phi \bigl( \bigl\vert D^{\beta }x(s) - D^{\beta }y(s) \bigr\vert \bigr) + a_{4}(s) \phi \biggl( \biggl\vert \int _{0}^{s} h(\xi ) \bigl( x(\xi ) - y(\xi ) \bigr) \,d\xi \biggr\vert \biggr) \,ds \\& \qquad {}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \sum _{i=1}^{k_{0}} b_{i}(s) H_{i}( \bigl\vert x(s) - y(s) \bigr\vert , \bigl\vert x'(s) - y'(s) \bigr\vert , \\& \qquad {}\bigl\vert D^{\beta }x(s) - D^{\beta }y(s) \bigr\vert , \biggl\vert \int _{0}^{s} h(\xi ) \bigl( x(\xi ) - y( \xi )\, d \xi \bigr)\biggr| \,ds \\& \qquad {}+ \int _{\mu }^{1} \bigl\vert G(t,s)| \biggl[c_{1}(s) \varPhi \bigl( \bigl\vert x(s) - y(s) \bigr\vert \bigr)+ c_{2}(s) \varPhi \bigl( \bigl\vert x'(s) - y'(s) \bigr\vert \bigr) \\& \qquad {}+ c_{3}(s) \varPhi \bigl( \bigl\vert D^{\beta }x(s) - D^{\beta }y(s) \bigr\vert \bigr) + c_{4}(s) \varPhi ( \biggl\vert \int _{0}^{s} h(\xi ) \bigl( x(\xi ) - y(\xi ) \bigr) \,d\xi \biggr\vert \biggr] \,ds \\& \quad \leq \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \int _{0}^{\lambda } (1-s)^{ \alpha -2} \bigl[a_{1}(s) \phi \bigl( \Vert x - y \Vert \bigr)+ a_{2}(s) \phi \bigl( \bigl\Vert x' - y' \bigr\Vert \bigr)\bigr] \\& \qquad {}+ a_{3}(s) \phi \biggl({\frac{ \Vert x' - y' \Vert }{\varGamma (2-\beta )}} \biggr) + a_{4}(s) \phi \bigl( m_{0} \Vert x - y \Vert \bigr) \,ds \\& \qquad {}+\frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \int _{\lambda }^{\mu } (1-s)^{ \alpha -2}\\& \qquad {}\times \sum _{i=1}^{k_{0}} b_{i}(s) H_{i}\biggl( \Vert x - y \Vert , \bigl\Vert x' - y' \bigr\Vert , \frac{ \Vert x' - y' \Vert }{\varGamma (2-\beta )}, m_{0} \Vert x - y \Vert \biggr) \,ds \\& \qquad {}+ \frac{2+ \alpha + T_{0}}{\varGamma (\alpha )} \int _{\mu }^{1} (1-s)^{ \alpha -2} \biggl[c_{1}(s) \varPhi \bigl( \Vert x - y \Vert \bigr)+ c_{2}(s) \varPhi \bigl( \bigl\Vert x' - y' \bigr\Vert \bigr) \\& \qquad {}+ c_{3}(s) \varPhi \biggl({\frac{ \Vert x' - y' \Vert }{\varGamma (2-\beta )}}\biggr) + c_{4}(s) \varPhi \bigl(m_{0} \Vert x - y \Vert \bigr) \biggr] \,ds \\& \quad \leq \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \Biggl[ \sum _{i=1}^{4} \phi \bigl(l \Vert x - y \Vert _{*}\bigr) \int _{0}^{\lambda } (1-s)^{\alpha -2} a_{i}(s) \,ds \\& \qquad {}+ \sum _{i=1}^{k_{0}} H_{i}\bigl(l \Vert x - y \Vert _{*}, \ldots, l \Vert x - y \Vert _{*}\bigr) \int _{\lambda }^{\mu } (1-s)^{\alpha -2} b_{i}(s) \,ds \\& \qquad {}+\sum _{i=1}^{4} \varPhi \bigl(l \Vert x - y \Vert _{*}\bigr) \int _{\mu }^{1} (1-s)^{ \alpha -2} c_{i}(s) \,ds \Biggr] \\& \quad = \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \Biggl[ \sum _{i=1}^{5} \phi \bigl(l \Vert x - y \Vert _{*} \bigr) \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} \\& \qquad {}+ \sum _{i=1}^{k_{0}} H_{i}\bigl(l \Vert x - y \Vert _{*}, \ldots, l \Vert x - y \Vert _{*}\bigr) \Vert \hat{b_{i}} \Vert _{[\lambda , \mu ]} +\sum _{i=1}^{4} \varPhi \bigl(l \Vert x - y \Vert _{*}\bigr) \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr]. \end{aligned}

On the other hand, $$\lim_{z \to 0^{+}} \frac{\phi _{i}(z)}{z^{\mu _{i}}}= l_{\mu _{i}}$$ for $$1 \leq i \leq 4$$. This implies that for each $$\epsilon >0$$ there exists $$0< \delta _{i} = \delta _{i}(\epsilon ) < \epsilon$$ such that $$\frac{\phi _{i}(z)}{z ^{\mu _{i}}}< l_{\mu _{i}}+ \epsilon$$ for all $$z \in (0, \delta _{i}]$$. Hence, $$\phi _{i}(\delta _{i})< ( l_{\mu _{i}} +\epsilon ) \delta ^{\mu _{i}}_{i} < ( l_{\mu _{i}} +\epsilon ) \epsilon ^{\mu _{i}}$$. By using a similar method, we conclude that there exists $$0< \delta '_{i} = \delta '_{i}(\epsilon ) < \epsilon$$ such that $$\varPhi _{i}(\delta '_{i})< ( l_{\gamma _{i}} +\epsilon ) (\delta '_{i})^{\gamma _{i}} < ( l_{\gamma _{i}} +\epsilon ) \epsilon ^{\gamma _{i}}$$. Also, we have $$\lim_{z \to 0^{+}} \frac{H_{j}(z, z, z, z)}{z^{m}}= q_{j}$$ for $$1 \leq j \leq k_{0}$$ and so there exists $$0< \delta _{q_{j}} < \epsilon$$ such that $$\frac{H_{j}(z, z, z, z)}{z^{m}}< q_{j} + \epsilon$$ for all $$z \in (0, \delta _{q_{j}}]$$ and $$1 \leq j \leq k_{0}$$. Hence, $$H_{j}(z, z, z, z) < (q_{j} + \epsilon ) z^{m}$$ for all $$z \in (0, \delta _{q_{j}}]$$ and so $$H_{j}(\delta _{q_{j}}, \delta _{q_{j}}, \delta _{q_{j}}, \delta _{q_{j}}) < (q_{j} + \epsilon ) \delta _{q_{j}} ^{m} < (q_{j} + \epsilon ) \epsilon ^{m}$$. Let $$x \to y$$ in X. If $$l \|x -y\|_{*}< \delta := \min \{ \delta _{1}, \ldots, \delta _{4}, \delta '_{1}, \ldots, \delta '_{4}, \delta _{q_{1}}, \ldots, \delta _{q_{k _{0}}} \}$$, then $$\phi _{i}(\delta )< \phi _{i}(\delta _{i})< ( l_{\mu _{i}} +\epsilon ) \epsilon ^{\mu _{i}}$$, $$\varPhi _{i}(\delta )< \varPhi _{i}( \delta '_{i})< ( l_{\gamma _{i}} +\epsilon ) \epsilon ^{\gamma _{i}}$$ and $$H_{j}(\delta , \ldots, \delta ) < H_{j}(\delta _{q_{j}}, \ldots, \delta _{q _{j}}) < (q_{j} + \epsilon ) \epsilon ^{m}$$ for $$1 \leq i \leq 4$$ and $$1 \leq j \leq k_{0}$$. If $$l \|x -y\|_{*}< \delta$$, then $$|F_{x}(t)-F _{y}(t)| \leq \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } [ \sum _{i=1}^{5} \| \hat{a_{i}} \|_{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon ) \epsilon ^{\mu _{i}} + \sum _{j=1}^{k_{0}} \| \hat{b_{j}} \|_{[ \lambda , \mu ]} (q_{j} + \epsilon ) \epsilon ^{m} +\sum _{i=1}^{4} \| \hat{c_{i}} \|_{[\mu , 1]} ] ( l_{\gamma _{i}} +\epsilon ) \epsilon ^{\gamma _{i}}]$$ and so $$| F_{x}-F_{y} \| \leq \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) }\times [ \sum _{i=1}^{5} \| \hat{a_{i}} \|_{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon ) \epsilon ^{\mu _{i}} + \sum _{j=1}^{k_{0}} \| \hat{b_{j}} \|_{[\lambda , \mu ]} (q_{j} + \epsilon ) \epsilon ^{m} +\sum _{i=1}^{4} \| \hat{c_{i}} \|_{[\mu , 1]} ] ( l_{\gamma _{i}} +\epsilon ) \epsilon ^{\gamma _{i}}]$$. By a similar way, we get

\begin{aligned} \bigl\Vert F'_{x}-F'_{y} \bigr\Vert \leq{}& \frac{3 \alpha }{\varGamma (\alpha ) } \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} + \epsilon ) \epsilon ^{\mu _{i}} + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q_{j} + \epsilon ) \epsilon ^{m} \\ &{}+\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} + \epsilon ) \epsilon ^{\gamma _{i}}] \end{aligned}

and so $$\| F_{x}-F_{y} \|_{*} \leq \max \{ \frac{3 \alpha }{\varGamma ( \alpha ) }, \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \} [ \sum _{i=1}^{5} \| \hat{a_{i}} \|_{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon ) \epsilon ^{\mu _{i}} + \sum _{j=1}^{k_{0}} \| \hat{b_{j}} \|_{[ \lambda , \mu ]} (q_{j} + \epsilon ) \epsilon ^{m} +\sum _{i=1}^{4} \| \hat{c_{i}} \|_{[\mu , 1]} ] ( l_{\gamma _{i}} +\epsilon ) \epsilon ^{\gamma _{i}}]$$. Since $$\epsilon >0$$ was arbitrary, we conclude that $$\| F_{x}-F_{y} \|_{*} \to 0$$ as $$x \to y$$. This implies that F is continuous on X. Since $$\lim_{x \to 0^{+}} \frac{\varLambda (x, x, x, x)}{x} = P_{2}$$, $$\lim_{x \to 0^{+}} \frac{\varLambda (lx, lx, lx, lx)}{lx} = P_{2}$$, where $$l = \max \{ 1, \frac{1}{\varGamma (2- \beta )}, m_{0} \}$$. Thus for each $$\epsilon >0$$ there exists $$\delta _{1} = \delta _{1}(\epsilon )$$ such that $$\frac{\varLambda (lx, lx, lx, lx)}{lx} < P_{2} + \epsilon$$ for all $$x \in (0, \delta _{1}]$$. Hence,

\begin{aligned} \varLambda (lx, lx, lx, lx) < ( P_{2} + \epsilon ) l x \end{aligned}
(4)

for $$x \in (0, \delta _{1}]$$. Also, $$\lim_{|x_{i}| \to 0} \frac{|f_{1}(t, x_{1}, \ldots, x_{4})|}{\min |x_{i}|} = P_{1}(t)$$. Thus, there exists $$\delta _{2} = \delta _{2}(\epsilon )$$ such that

\begin{aligned} \bigl\vert f_{1}(t, x_{1}, \ldots, x_{4}) \bigr\vert < \bigl(P_{1}(t)+ \epsilon \bigr) \min \vert x_{i} \vert \end{aligned}
(5)

for all $$t \in [0,1]$$ and $$|x_{i}| \in (0, \delta _{2}]$$ for $$1 \leq i \leq 4$$. Similarly, there exists $$\delta _{3} = \delta _{3}( \epsilon )$$ such that

\begin{aligned} \bigl\vert f_{3}(t, x_{1}, \ldots, x_{4}) \bigr\vert < \bigl(P_{3}(t)+ \epsilon \bigr) \min \vert x_{i} \vert \end{aligned}
(6)

for all $$t \in [0,1]$$ and $$|x_{i}| \in (0, \delta _{3}]$$ for $$1 \leq i \leq 4$$. Since $$\| \hat{P_{1}} \|_{[0, \lambda ]} + P_{2} \| \varTheta \|_{[\lambda , \mu ]} + \| \hat{P_{3}} \|_{[\mu , 1]} < \frac{ \varGamma (\alpha )}{ l \theta _{0}}$$, we can choose $$\epsilon _{0} >0$$ such that $$\| \hat{P_{1}} \|_{[0, \lambda ]} + \frac{\epsilon _{0}}{\alpha -1} (1-(1-\lambda )^{\alpha -1} ) + (P_{2} + \epsilon _{0}) \| \varTheta \|_{[\lambda , \mu ]} + \| \hat{P_{3}} \|_{[\mu , 1]} + \frac{\epsilon _{0}}{\alpha -1} (1- \mu )^{\alpha -1} < \frac{\varGamma (\alpha )}{ l \theta _{0}}$$. Since

$$\max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T_{0}}{ \varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} ) + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} q_{j} +\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[ \mu , 1]} \Biggr] ( l_{\gamma _{i}} ) ] < 1,$$

pick $$\epsilon _{1} \in (0,1)$$ such that

\begin{aligned} & \max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T _{0}}{\varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon _{1}) \\ & \quad {} + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q _{j} + \epsilon _{1} ) +\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} +\epsilon _{1}) ] < 1. \end{aligned}
(7)

Let $$r_{0} = \min \{ \delta _{1}(\epsilon _{0}), \delta _{2}(\epsilon _{0}), \delta _{3}(\epsilon _{0}), \frac{\epsilon _{1}}{2} \}$$, and $$C= \{ x\in X : \|x\|_{*}< r_{0} \}$$. Define the map α on $$X\times X$$ by

$$\alpha (x, y)= \textstyle\begin{cases} 1, & x,y \in C, \\ 0, & \mbox{otherwise}. \end{cases}$$

Let $$x, y \in X$$ and $$\alpha (x, y) \geq 1$$. Then $$x, y \in C$$ and so

\begin{aligned} \bigl\vert F_{x}(t) \bigr\vert \leq& \int _{0}^{\lambda } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{2}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\mu }^{1} \bigl\vert G(t,s) \bigr\vert \biggl\vert f_{3}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int_{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggl[ \int _{0}^{\lambda } (1-s)^{\alpha -2} \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } (1-s)^{\alpha -2} \biggl\vert f_{2}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\mu }^{1} (1-s)^{\alpha -2} \biggl\vert 3_{2}\biggl(s, x(s), x'(s),D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \biggr] \\ \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggl[ \int _{0}^{\lambda} (1-s)^{\alpha -2} \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } (1-s)^{\alpha -2} \varTheta (s) \varLambda \biggl( x(s),x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \,ds \\ &{}+ \int _{\mu }^{1} (1-s)^{\alpha -2} \biggl\vert 3_{2}\biggl(s, x(s), x'(s),D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \biggr] \\ \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggl[ \int _{0}^{\lambda} (1-s)^{\alpha -2} \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } (1-s)^{\alpha -2} \varTheta (s) \varLambda \biggl( \Vert x \Vert , \bigl\Vert x' \bigr\Vert , \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}, m_{0} \Vert x \Vert \biggr) \,ds \\ &{}+ \int _{\mu }^{1} (1-s)^{\alpha -2} \biggl\vert 3_{2}\biggl(s, x(s), x'(s),D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \biggr] \\ \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggl[ \int _{0}^{\lambda} (1-s)^{\alpha -2} \biggl\vert f_{1}\biggl(s, x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \\ &{}+ \int _{\lambda }^{\mu } (1-s)^{\alpha -2} \varTheta (s) \varLambda \bigl( l \Vert x \Vert _{*}, l \Vert x \Vert _{*}, l \Vert x \Vert _{*}, l \Vert x \Vert _{*}\bigr) \,ds \\ &{}+ \int _{\mu }^{1} (1-s)^{\alpha -2} \biggl\vert 3_{2}\biggl(s, x(s), x'(s),D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr) \biggr\vert \,ds \biggr] \end{aligned}

for all $$t \in [0,1]$$. Since $$\|x\|_{*}< r_{0}$$, $$x \in [0, \min \{ \delta _{1}, \delta _{2}, \delta _{3} \} )$$ and so by using (4), (5) and (6) we conclude that

\begin{aligned} \bigl\vert F_{x}(t) \bigr\vert \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \\ &{}\times\biggl[ \int _{0}^{\lambda } (1-s)^{\alpha -2} \bigl(P_{1}(s)+ \epsilon \bigr) \min \biggl\{ x_{(}s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d\xi \biggr\} \,ds \\ &{}+ ( P_{2} + \epsilon _{0}) l \Vert x \Vert _{*} \int _{\lambda }^{\mu } (1-s)^{ \alpha -2} \varTheta (s) \,ds \\ &{}+ \int _{\mu }^{1} (1-s)^{\alpha -2} | \bigl(P_{3}(s)+ \epsilon _{0}\bigr) \min \biggl\{ x(s), x'(s), D^{\beta }x(s), \int _{0}^{s} h(\xi ) x(\xi )\,d \xi \biggr\} \,ds \biggr] \\ \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggl[ \int _{0}^{\lambda } (1-s)^{\alpha -2} \bigl(P_{1}(s)+ \epsilon \bigr) \min \biggl\{ \Vert x \Vert , \bigl\Vert x' \bigr\Vert , \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}, m_{0} \Vert x \Vert \biggr\} \,ds \\ &{}+ ( P_{2} + \epsilon _{0}) l \Vert x \Vert _{*} \Vert \hat{\varTheta } \Vert _{[\lambda , \mu ]} \\ &{}+ \int _{\mu }^{1} (1-s)^{\alpha -2} | \bigl(P_{3}(s)+ \epsilon _{0}\bigr) \min \biggl\{ \Vert x \Vert , \bigl\Vert x' \bigr\Vert , \frac{ \Vert x' \Vert }{\varGamma (2- \beta )}, m_{0} \Vert x \Vert \biggr\} \,ds \biggr] \\ \leq& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggl[l \Vert x \Vert _{*} \int _{0}^{\lambda } (1-s)^{\alpha -2} \bigl(P_{1}(s)+ \epsilon _{0}\bigr) \,ds + ( P _{2} + \epsilon ) l \Vert x \Vert _{*} \Vert \hat{\varTheta } \Vert _{[\lambda , \mu ]} \\ &{}+ l \Vert x \Vert _{*} \int _{\mu }^{1} (1-s)^{\alpha -2} \bigl(P_{3}(s)+ \epsilon _{0}\bigr) \,ds \biggr] \\ = &\frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } l \Vert x \Vert _{*} \biggl[ \int _{0} ^{\lambda } (1-s)^{\alpha -2} P_{1}(s) \,ds+ \epsilon _{0} \int _{0}^{ \lambda } (1-s)^{\alpha -2} \,ds \\ &{}+ ( P_{2} + \epsilon _{0}) \Vert \hat{\varTheta } \Vert _{[\lambda , \mu ]} + \int _{\mu }^{1} (1-s)^{\alpha -2} P_{3}(s) \,ds + \epsilon _{0} \int _{ \mu }^{1} (1-s)^{\alpha -2} \,ds\biggr] \\ =& \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } l \Vert x \Vert _{*} \biggl[ \Vert \hat{ P_{1}} \Vert _{[0, \lambda ]} +\frac{\epsilon _{0}}{\alpha -1} \bigl(1 - (1- \lambda )^{\alpha -1}\bigr) \\ &{}+ ( P_{2} + \epsilon _{0}) \Vert \hat{\varTheta } \Vert _{[\lambda , \mu ]} + \Vert \hat{ P_{3}} \Vert _{[\mu , 1]} + \frac{\epsilon _{0}}{\alpha -1} (1 - \mu )^{\alpha -1}\biggr] \\ \leq& \theta _{0} l \biggl[ \Vert \hat{ P_{1}} \Vert _{[0, \lambda ]} +\frac{\epsilon _{0}}{\alpha -1} \bigl(1 - (1-\lambda )^{\alpha -1}\bigr) \\ &{}+ ( P_{2} + \epsilon _{0}) \Vert \hat{\varTheta } \Vert _{[\lambda , \mu ]} + \Vert \hat{ P_{3}} \Vert _{[\mu , 1]} + \frac{\epsilon _{0}}{\alpha -1} (1 - \mu )^{\alpha -1}\biggr] \Vert x \Vert _{*} \\ \leq& \Vert x \Vert _{*} \end{aligned}

and so $$\|Fx \| \leq \|x\|_{*} < r_{0}$$. Also, we can conclude that $$\|F'x \| \leq \|x\|_{*} < r_{0}$$. Hence, $$\|Fx \| < r_{0}$$ and so $$F_{x} \in C$$. For the same reason, $$F_{y} \in C$$. Similar to (7), we conclude that

\begin{aligned} \Vert F_{x}-F_{y} \Vert _{*} \leq & \max \biggl\{ \frac{3 \alpha }{\varGamma ( \alpha ) }, \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon _{1}) \Vert x-y \Vert _{*}^{\mu _{i}} \\ &{} + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q _{j} + \epsilon _{1} ) \Vert x-y \Vert _{*}^{m} +\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} +\epsilon _{1}) \Vert x-y \Vert _{*}^{\gamma _{i}}] \\ \leq & \max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon _{1}) \Vert x-y \Vert _{*} \\ &{} + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q _{j} + \epsilon _{1} ) \Vert x-y \Vert _{*} +\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} +\epsilon _{1}) \Vert x-y \Vert _{*}] \\ =& \max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T _{0}}{\varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon _{1}) \\ & {}+ \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q _{j} + \epsilon _{1} ) +\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} +\epsilon _{1}) ] \Vert x-y \Vert _{*} \end{aligned}

whenever $$\|x-y\|_{*}< \epsilon _{1}$$. Thus, $$\|x - y\|_{*} \leq \|x\| _{*} + \|y\|_{*} \leq \epsilon _{0}$$ whenever $$x, y \in C$$. Hence,

\begin{aligned} \Vert F_{x}-F_{y} \Vert _{*} \leq & \max \biggl\{ \frac{3 \alpha }{\varGamma ( \alpha ) }, \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon _{1}) \\ & {}+ \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q _{j} + \epsilon _{1} ) +\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} +\epsilon _{1}) ] \Vert x-y \Vert _{*} \\ = & \psi \bigl( \Vert x-y \Vert _{*}\bigr), \end{aligned}

where

\begin{aligned} \psi (t) = & \max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T_{0}}{\varGamma (\alpha ) } \biggr\} \Biggl[ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} +\epsilon _{1}) \\ & {}+ \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} (q _{j} + \epsilon _{1} ) \\ & {}+\sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} \Biggr] ( l_{\gamma _{i}} +\epsilon _{1}) ] t. \end{aligned}

Note that $$\psi \in \varPsi$$. Now by using Theorem 6, F has a fixed point and so the pointwise defined problem (1) has a solution. □

### Example 2

Consider the problem

$$D^{\frac{7}{2}} x(t) + f\biggl(t, x(t), x'(t), D^{\frac{1}{2}} x(t), \int _{0}^{t} x(\xi ) \,d\xi \biggr)=0$$

with boundary conditions $$x(0)=x'(\frac{1}{3})$$, $$x(1)=x'(\frac{1}{2})$$ and $$x''(0) =0$$, where

$$f(t, x_{1}, \ldots, x_{4})= \textstyle\begin{cases} f_{1}(t, x_{1}, \ldots, x_{4}):= t^{2} (\sum _{i=1}^{4} x_{i}(s) ), & t \in [0, 0.7), \\ f_{2}(t, x_{1}, \ldots, x_{4}):= \frac{0.1}{p(t)} \sum _{i=1}^{4} \frac{ \vert x_{i}(t) \vert }{1+ \vert x_{i}(t) \vert }, & \frac{t}{3} \in [0.7, 0.7], \\ f_{3}(t, x_{1}, \ldots, x_{4}):= t(\sum _{i=1}^{4} x_{i}(s) ), & t \in [0.9, 1], \end{cases}$$

and

$$p(t)= \textstyle\begin{cases} 0, & t \in [0.2, 0.9] \cap Q, \\ t, & t \in [0.2, 0.9] \cap Q^{c}. \end{cases}$$

Put $$a_{i}(t) = a(t)= t^{2}$$, $$b_{j}(t)= b(t)= \frac{0.1}{p(t)}$$ and $$c_{i}(t)= c(t) = t$$ (for $$1 \leq i \leq 4$$, $$k_{0}=1$$). Then we have $$|f_{1}(t, x_{1}, \ldots, x_{4}) - f_{1}(t, y_{1}, \ldots, y_{4})| \leq t ^{2} \sum _{i=1}^{4} |x_{i} - y_{i}| =a(t) \sum _{i=1}^{4} \phi (|x _{i} - y_{i}|)$$,

$$\bigl\vert f_{3}(t, x_{1}, \ldots, x_{4}) - f_{3}(t, y_{1}, \ldots, y_{4}) \bigr\vert \leq t \sum _{i=1}^{4} \vert x_{i} - y_{i} \vert =c(t) \sum _{i=1}^{4} \varPhi \bigl( \vert x_{i} - y_{i} \vert \bigr),$$

and

$$\bigl\vert f_{2}(t, x_{1}, \ldots, x_{4}) - f_{2}(t, y_{1}, \ldots, y_{4}) \bigr\vert \leq t ^{2} \sum _{i=1}^{4} \vert x_{i} - y_{i} \vert =b(t) \sum _{i=1}^{4} H\bigl( \vert x- y \vert , \ldots, \vert x- y \vert \bigr),$$

where $$\phi (z)=z$$, $$\varPhi (z)= z$$ and $$H(z_{1}, \ldots, z_{4})= z_{1}+ \cdots+ z_{4}$$. Put $$\mu _{i}=\gamma _{i}=m= 1$$. Then we have $$\lim_{z \to 0^{+}} \frac{\phi (z)}{z }=1$$, $$\lim_{z \to 0^{+}} \frac{\varPhi (z)}{z }=1$$ and $$\lim_{z \to 0^{+}} \frac{H_{j}(z, z, z, z)}{z }=1$$. Also, $$\lim_{\max |x_{i}| \to 0} \frac{|f_{1}(t, x_{1}, \ldots, x_{4})|}{\max |x _{i}|} =4 t^{2}=P_{1}(t)$$, $$\lim_{\max |x_{i}| \to 0} \frac{|f_{3}(t, x_{1}, \ldots, x_{4})|}{\max |x_{i}|} = 4t =P_{3}(t)$$ and $$|f_{2}(t, x _{1}, \ldots, x_{4})| \leq \varTheta (t) \varLambda (x_{1}, \ldots, x_{4})$$, where $$\varTheta (t) = p(t)$$ and $$\varLambda (x_{1}, \ldots, x_{4})= \sum _{i=1} ^{5} \frac{|x_{i}|}{1+|x_{i}|}$$. It is easy to see that ϕ, Φ, H and Λ satisfy the conditions of Theorem 6 and $$\lim_{x \to 0^{+}} \frac{\varLambda (x, x, x, x)}{x } =4 :=P_{2}$$. Also, we have

\begin{aligned}& \max \biggl\{ \frac{3 \alpha }{\varGamma (\alpha ) }, \frac{2+ \alpha + T_{0}}{ \varGamma (\alpha ) } \biggr\} \cdot \max \biggl\{ \sum _{i=1}^{5} \Vert \hat{a_{i}} \Vert _{[0, \lambda ]} ( l_{\mu _{i}} ) + \sum _{j=1}^{k_{0}} \Vert \hat{b_{j}} \Vert _{[\lambda , \mu ]} q_{j} \\& \qquad {}+ \sum _{i=1}^{4} \Vert \hat{c_{i}} \Vert _{[\mu , 1]} ] ( l_{\gamma _{i}} ) , \max \biggl\{ 1, \frac{1}{\varGamma (2- \beta ) }, m_{0} \biggr\} \bigl[ \Vert \hat{P_{1}} \Vert _{[0, \lambda ]} + P_{2} \Vert \varTheta \Vert _{[\lambda , \mu ]} + \Vert \hat{P_{3}} \Vert _{[\mu , 1]}\bigr] \biggr\} \\& \quad \leq \frac{\frac{21}{2} }{\frac{15 \sqrt{\pi }}{8} } \max \bigl\{ 0.19 + 0.005+ 0.9, 1.13[0.19 + 0.02+ 0.9] \bigr\} < 1. \end{aligned}

By using Theorem 6, the pointwise defined problem has a solution.

## Conclusion

It is very important that we increase our abilities of natural phenomenon modeling. In this way, it is better we investigate different types of high order fractional integro-differential equations or new type model ones. One of the new models is described by the three step crisis fractional integro-differential equations which have been introduced recently. In this work, we reviewed the existence of solutions for a three step crisis fractional integro-differential equation under some boundary conditions.

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### Acknowledgements

The second and third authors were supported by Azarbaijan Shahid Madani University. The authors express their gratitude to the unknown referees for their helpful suggestions, which improved the final version of this paper.

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Data sharing not applicable to this paper as no datasets were generated or analyzed during the current study.

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Each of the authors contributed to each part of this study equally and approved of the final version of the manuscript.

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Correspondence to Shahram Rezapour.

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Baleanu, D., Ghafarnezhad, K. & Rezapour, S. On a three step crisis integro-differential equation. Adv Differ Equ 2019, 153 (2019). https://doi.org/10.1186/s13662-019-2088-2

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### Keywords

• Caputo derivation
• Pointwise defined equation
• Three steps crisis equation
• Singularity