Theory and Modern Applications
Table 1 Numerical results for Example 4.1
No. of Iter. \(\Theta _{k}=0\) | Alg. 1, \(\Theta _{k} \neq 0\) | CPU (Sec) \(\Theta _{k} = 0\) | Alg. 1, \(\Theta _{k} \neq 0\) | |
|---|---|---|---|---|
Choice 1. \(x_{0}=(5)\), \(x_{1}=(2)\) and N = 20 | 91 | 78 | 0.088136 | 0.059103 |
Choice 1. \(x_{0}=(5)\), \(x_{1}=(2)\) and N = 5 | 95 | 83 | 0.088177 | 0.067473 |
Choice 2. \(x_{0}=(4.7)\), \(x_{1}=(1.7)\) and N = 20 | 104 | 90 | 0.098793 | 0.091790 |
Choice 2. \(x_{0}=(4.7)\), \(x_{1}=(1.7)\) and N = 5 | 110 | 94 | 0.099405 | 0.092703 |
Choice 3. \(x_{0}=(-7)\), \(x_{1}=(4)\) and N = 20 | 95 | 81 | 0.074912 | 0.069149 |
Choice 3. \(x_{0}=(-7)\), \(x_{1}=(4)\) and N = 5 | 108 | 89 | 0.078510 | 0.071038 |