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Theory and Modern Applications

Table 10 \(C_{2}\)-order of convergence for Example 1 and different γ’s

From: A new fourth-order explicit group method in the solution of two-dimensional fractional Rayleigh–Stokes problem for a heated generalized second-grade fluid

γ = 0.4

γ = 0.5

h/τ

Max error

\(C_{2}\)-order

h/τ

Max error

\(C_{2}\)-order

\(h=\tau =\frac{1}{2}\)

3.7570 × 10−2

\(h=\tau =\frac{1}{2}\)

4.2072 × 10−2

\(h=\frac{1}{4}, \tau =\frac{1}{32}\)

2.6621 × 10−3

3.81

\(h=\frac{1}{4}, \tau =\frac{1}{32}\)

2.3925 × 10−3

4.13

\(h=\tau =\frac{1}{4}\)

1.9645 × 10−2

\(h=\tau =\frac{1}{4}\)

1.9308 × 10−2

\(h=\frac{1}{8}, \tau =\frac{1}{64}\)

1.3235 × 10−3

3.89

\(h=\frac{1}{8}, \tau =\frac{1}{64}\)

1.2333 × 10−3

3.96

γ = 0.6

γ = 0.7

h/τ

Max error

\(C_{2}\)-order

h/τ

Max error

\(C_{2}\)-order

\(h=\tau =\frac{1}{2}\)

4.0658 × 10−2

\(h=\tau =\frac{1}{2}\)

3.3869 × 10−2

\(h=\frac{1}{4}, \tau =\frac{1}{32}\)

2.0573 × 10−3

4.30

\(h=\frac{1}{4}, \tau =\frac{1}{32}\)

1.6180 × 10−3

4.38

\(h=\tau =\frac{1}{4}\)

1.6658 × 10−2

\(h=\tau =\frac{1}{4}\)

1.2312 × 10−2

\(h=\frac{1}{8}, \tau =\frac{1}{64}\)

1.0452 × 10−3

3.99

\(h=\frac{1}{8}, \tau =\frac{1}{64}\)

8.3252 × 10−3

3.88