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Theory and Modern Applications

Table 4 The solution errors of Example 4 for \(\varepsilon=10^{-3}\) and \(\varepsilon=10^{-4}\) at \(h=0.001\)

From: Absolutely stable difference scheme for a general class of singular perturbation problems

\(x_{i}\)

ε = 10−3

ε = 10−4

CFD

ASCD

CFD

ASCD

 

\(\delta_{i}=\frac{4}{\omega|p_{i}|}\)

\(\delta_{i}=\delta_{\mathrm{op}}\)

 

\(\delta_{i}=\frac{4}{\omega|p_{i}|}\)

\(\delta_{i}=\delta_{\mathrm{op}}\)

0.000

2.4425e − 15

0.0000e + 00

2.4425e − 15

2.2204e − 15

0.0000e + 00

0.0000e + 00

0.500

2.4425e − 15

0.0000e + 00

2.4425e − 15

2.2204e − 15

0.0000e + 00

0.0000e + 00

0.700

2.4425e − 15

0.0000e + 00

2.4425e − 15

2.2204e − 15

0.0000e + 00

0.0000e + 00

0.900

2.4425e − 15

0.0000e + 00

2.4425e − 15

2.2204e − 15

0.0000e + 00

0.0000e + 00

0.950

2.4425e − 15

0.0000e + 00

2.4425e − 15

1.5683e − 09

0.0000e + 00

0.0000e + 00

0.980

1.7744e − 09

2.0612e − 09

1.7744e − 09

3.0073e − 04

0.0000e + 00

0.0000e + 00

0.990

2.8465e − 05

4.5400e − 05

2.8465e − 05

1.7342e − 02

0.0000e + 00

0.0000e + 00

0.991

7.2605e − 05

1.2341e − 04

7.2605e − 05

2.6012e − 02

0.0000e + 00

0.0000e + 00

0.992

1.8305e − 04

3.3546e − 04

1.8305e − 04

3.9018e − 02

0.0000e + 00

0.0000e + 00

0.993

4.5463e − 04

9.1188e − 04

4.5463e − 04

5.8528e − 02

0.0000e + 00

0.0000e + 00

0.994

1.1070e − 03

2.4788e − 03

1.1070e − 03

8.7791e − 02

0.0000e + 00

0.0000e + 00

0.995

2.6227e − 03

6.7379e − 03

2.6227e − 03

1.3169e − 01

0.0000e + 00

0.0000e + 00

0.996

5.9700e − 03

1.8316e − 02

5.9700e − 03

1.9753e − 01

0.0000e + 00

0.0000e + 00

0.997

1.2750e − 02

4.9787e − 02

1.2750e − 02

2.9630e − 01

9.3592e − 14

9.3592e − 14

0.998

2.4224e − 02

1.3534e − 01

2.4224e − 02

4.4444e − 01

2.0612e − 09

2.0612e − 09

0.999

3.4546e − 02

3.6788e − 01

3.4546e − 02

6.6671e − 01

4.5400e − 05

4.5400e − 05

1.000

0.0000e + 00

0.0000e + 00

0.0000e + 00

2.2204e − 16

0.0000e + 00

0.0000e + 00