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Table 6 \(L_{1}\) and \(L_{\infty }\) errors and CPU time at some different values of time-step size k for Problem 1 at time \(2.5\times 10^{-3}\) with spatial mesh size \(h=0.01\) using NSFD scheme, where \(T_{\max }=2.5\times 10^{-3}\)

From: On the numerical solution of Fisher’s equation with coefficient of diffusion term much smaller than coefficient of reaction term

Time step (k) \(L_{1}\) error \(L_{\infty }\) error CPU (s)
\(T_{\max }/25\) 1.9125 × 10−1 9.8876 × 10−1 0.683
\(T_{\max }/50\) 1.2304 × 10−1 9.2384 × 10−1 0.743
\(T_{\max }/100\) 7.0554 × 10−2 7.0761 × 10−1 0.689
\(T_{\max }/200\) 3.6165 × 10−2 4.1770 × 10−1 0.724
\(T_{\max }/300\) 2.3031 × 10−2 2.7850 × 10−1 0.738
\(T_{\max }/400\) 1.6095 × 10−2 1.9599 × 10−1 0.758
\(T_{\max }/500\) 1.1808 × 10−2 1.4689 × 10−1 0.831
\(T_{\max }/600\) 8.8945 × 10−3 1.1268 × 10−1 0.814
\(T_{\max }/700\) 6.7864 × 10−3 8.7538 × 10−2 0.854
\(T_{\max }/800\) 5.1909 × 10−3 6.8368 × 10−2 0.900
\(T_{\max }/900\) 3.9428 × 10−3 5.3310 × 10−2 0.960
\(T_{\max }/1000\) 2.9430 × 10−3 4.1187 × 10−2 0.972
\(T_{\max }/1100\) 2.1324 × 10−3 3.1229 × 10−2 0.939
\(T_{\max }/1200\) 1.4815 × 10−3 2.2908 × 10−2 0.995
\(T_{\max }/1300\) 9.7728 × 10−4 1.5854 × 10−2 1.034
\(T_{\max }/1400\) 6.3200 × 10−4 9.8018 × 10−3 1.077
\(T_{\max }/1500\) 4.5216 × 10−4 4.5522 × 10−3 1.175
\(T_{\max }/1600\) 5.0673 × 10−4 5.3751 × 10−3 1.210
\(T_{\max }/1700\) 8.4460 × 10−4 7.6933 × 10−3 1.263
\(T_{\max }/1800\) 1.1475 × 10−3 1.0160 × 10−2 1.298