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Advances in Continuous and Discrete Models

Theory and Modern Applications

Table 7 The maximum errors of Algorithm 2 to Example 2 for \(\tau=0.0004\)

From: A new parallel algorithm for solving parabolic equations

 

h = 1/19

h = 1/25

h = 1/31

h = 1/37

t = 0.2

6.0275e−4

1.5451e−4

8.0677e−5

4.9096e−5

t = 0.4

4.4976e−4

1.9272e−4

1.0052e−4

6.1127e−5

t = 0.5

5.1593e−4

2.1305e−4

1.1113e−4

6.7574e−5

t = 0.6

5.7284e−4

2.3546e−4

1.2282e−4

7.4684e−5

t = 0.8

7.0014e−4

2.8760e−4

1.5001e−4

9.1219e−5

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