Theory and Modern Applications

# Existence of solutions for Sturm-Liouville boundary value problems of higher-order coupled fractional differential equations at resonance

## Abstract

This paper focuses on the existence of solutions for a higher-order coupled system of fractional differential equations with Sturm-Liouville boundary value conditions at resonance. By applying Mawhin continuation theorem, some new existence results are established. Furthermore, two examples are supplied to demonstrate the main results.

## Introduction

In the last two decades, fractional differential equations have been widely used in various fields of science, engineering and mathematics (see ). Based on the extensive application of fractional differential equations, it is of great theoretical and practical significance to study the boundary value problems (BVPs for short) of fractional differential equations. Accordingly, the research of fractional BVPs has been paid attention to by many scholars. At present, there have been many studies on various BVPs of fractional differential equations, for example, periodic BVPs (see ), anti-periodic BVPs (see [11, 12]), Dirichlet BVPs (see [13, 14]), multi-point BVPs (see ), impulsive BVPs (see ), Sturm-Liouville BVPs (see ), etc. Among them, as a classical non-resonance boundary value condition, the integer order Sturm-Liouville BVPs have been studied for a long time. By comparison, the study of fractional Sturm-Liouville BVPs is still a new field. In , Zhao considered the following fractional Sturm-Liouville BVP:

$$\textstyle\begin{cases} D_{0 + }^{\alpha}u ( t ) + f ( {t,u ( t )} ) = 0,\quad 0 < t < 1,\\ u' ( 0 ) - \beta u ( \xi ) = 0,\qquad u' ( 1 ) + \gamma u ( \eta ) = 0, \end{cases}$$

where $$1 < \alpha \le 2$$, $$D_{0 + }^{\alpha}$$ is the Caputo fractional derivative, $$0 \le \xi \le \eta \le 1$$, $$0 \le \beta ,\gamma \le 1$$, $$f: [ {0,1} ] \times {\mathbb{R}^{+} } \to {\mathbb{R}^{+} }$$ is continuous. On the basis of fixed point theorems and successive iteration method, the existence of positive solutions was obtained. On this foundation, Liu  studied such problems further by applying the Avery-Peterson fixed point theorem.

Zhao  studied the existence of at least two positive solutions by the fixed point theorem in the cone of strict-set-contraction operators for the following BVP:

$$\textstyle\begin{cases} D_{0 + }^{q}u ( t ) + f ( {t,u,u', \ldots ,{u^{ ( {n - 2} )}}} ) = 0,\quad 0 < t < 1,\\ u ( 0 ) = u' ( 0 ) = \cdots = {u^{ ( {n - 3} )}} ( 0 ) = 0,\\ \alpha {u^{ ( {n - 2} )}} ( 0 ) - \beta {u^{ ( {n - 1} )}} ( 0 ) = 0,\qquad \gamma {u^{ ( {n - 2} )}} ( 1 ) + \delta {u^{ ( {n - 1} )}} ( 1 ) = 0, \end{cases}$$

where $$n-1 < q \le n$$, $$D_{0 + }^{q}$$ is the Caputo fractional derivative, $$n\geq 2$$, α, β, γ and δ are nonnegative constants. Due to the widespread use of coupled system in the applications (see ), it is important to study a coupled system of fractional differential equations and some important results have been presented (see ). Zhang and Bai  studied the following equations:

$$\textstyle\begin{cases} D_{0 + }^{\alpha}u ( t ) = f ( {t,v ( t ),D_{0 + }^{\beta - 1}v ( t )} ),\quad 0 < t < 1,\\ D_{0 + }^{\beta}v ( t ) = g ( {t,u ( t ),D_{0 + }^{\alpha - 1}u ( t )} ),\quad 0 < t < 1,\\ u ( 0 ) = v ( 0 ) = 0,\qquad u ( 1 ) = {\sigma _{1}}u ( {{\eta _{1}}} ),\qquad v ( 1 ) = {\sigma _{2}}v ( {{\eta _{2}}} ), \end{cases}$$

where $$D_{0 + }^{\alpha}$$, $$D_{0 + }^{\beta}$$ are Riemann-Liouville fractional derivatives, $$1 < \alpha ,\beta \le 2$$, $$0 < {\eta _{1}},{\eta _{2}} < 1$$, $${\sigma _{1}},{\sigma _{2}} > 0$$, $$f,g: [ {0,1} ] \times {\mathbb{R}^{2}} \to \mathbb{R}$$ are continuous. The sufficient conditions for the existence of solutions of coupled fractional differential equations are obtained by applying the Mawhin continuation theorem.

Recently, there have appeared some papers dealing with the existence of solutions for a coupled system of higher-order fractional differential equations (see ). However, there are few results concerning a higher-order coupled system of fractional differential equations with Sturm-Liouville boundary value conditions at resonance. Motivated by the above mentioned discussion, we consider the following BVP:

$$\textstyle\begin{cases} D_{0 + }^{\alpha}u ( t ) = f ( {t,v ( t ),v' ( t ), \ldots ,{v^{ ( {n - 1} )}} ( t )} ), \\ D_{0 + }^{\beta}v ( t ) = g ( {t,u ( t ),u' ( t ), \ldots ,{u^{ ( {n - 1} )}} ( t )} ), \\ u ( 0 ) = u' ( 0 ) = \cdots = {u^{ ( {n - 3} )}} ( 0 ) = 0, \\ v ( 0 ) = v' ( 0 ) = \cdots = {v^{ ( {n - 3} )}} ( 0 ) = 0, \\ u^{ ( {n - 2} )} ( 0 ) = {\gamma _{1}}{u^{ ( {n - 1} )}} ( {{\xi _{1}}} ),\qquad {u^{ ( {n - 1} )}} ( 1 ) = {\delta _{1}}{u^{ ( {n - 2} )}} ( {{\eta _{1}}} ),\\ v^{ ( {n - 2} )} ( 0 ) = {\gamma _{2}}{v^{ ( {n - 1} )}} ( {{\xi _{2}}} ),\qquad {v^{ ( {n - 1} )}} ( 1 ) = {\delta _{2}}{v^{ ( {n - 2} )}} ( {{\eta _{2}}} ), \end{cases}$$
(1.1)

where $$0 < t < 1$$, $$n - 1 < \alpha ,\beta \le n$$, $$n > 2$$, $$D_{0 + }^{\alpha}$$, $$D_{0 + }^{\beta}$$ are Caputo fractional derivatives, $$f,g: [ {0,1} ] \times {\mathbb{R}^{n}} \to \mathbb{R}$$ are continuous, $${\gamma _{1}},{\gamma _{2}},{\delta _{1}},{\delta _{2}} > 0$$, $$0 < {\xi _{1}},{\xi _{2}},{\eta _{1}},{\eta _{2}} < 1$$. Equation (1.1) is a Sturm-Liouville semi-homogeneous BVP.

The major contributions given in this paper have some new features. Firstly, the fractional differential equation established by us is a higher-order coupled system which is more difficult to construct than a projection operator. In comparison with the previous literature, the system is more general. Secondly, we also observe that few scholars have ever considered the higher-order coupled system of fractional differential equations with Sturm-Liouville boundary value conditions at resonance before. So our results serve as a further development for previous findings in this sense. In addition, we can also use the method of this paper to discuss the following BVP, which is similar to (1.1):

$$\textstyle\begin{cases} D_{0 + }^{\alpha}u ( t ) = f ( {t,v ( t ),v' ( t ), \ldots ,{v^{ ( {n - 1} )}} ( t )} ), \\ D_{0 + }^{\beta}v ( t ) = g ( {t,u ( t ),u' ( t ), \ldots ,{u^{ ( {n - 1} )}} ( t )} ),\\ u ( 0 ) = u' ( 0 ) = \cdots = {u^{ ( {n - 3} )}} ( 0 ) = 0, \\ v ( 0 ) = v' ( 0 ) = \cdots = {v^{ ( {n - 3} )}} ( 0 ) = 0,\\ {u^{ ( {n - 2} )}} ( 1 ) = {\gamma _{1}}{u^{ ( {n - 1} )}} ( {{\xi _{1}}} ),\qquad {u^{ ( {n - 1} )}} ( 0 ) = {\delta _{1}}{u^{ ( {n - 2} )}} ( {{\eta _{1}}} ), \\ {v^{ ( {n - 2} )}} ( 1 ) = {\gamma _{2}}{v^{ ( {n - 1} )}} ( {{\xi _{2}}} ),\qquad {v^{ ( {n - 1} )}} ( 0 ) = {\delta _{2}}{v^{ ( {n - 2} )}} ( {{\eta _{2}}} ). \end{cases}$$

## Preliminaries

In order to facilitate understanding, we introduce the concepts and lemmas of fractional derivatives and integrals related to this paper, and more details can be found in the recent literature (see ).

### Definition 2.1



Let X, Y be real Banach spaces, and $$L:\operatorname{dom}L\subset X\rightarrow Y$$ be a linear map. If $$\dim \operatorname{Ker}L = \operatorname{codim} \operatorname{Im} L < + \infty$$ and ImL is a closed subset in Y, then the map L is a Fredholm operator with index zero. If there exists the continuous projections $$P:X\rightarrow X$$ and $$Q:Y\rightarrow Y$$ satisfying $$\operatorname{Im} P =\operatorname{Ker}L$$ and $$\operatorname{Ker}Q=\operatorname{Im} L$$, then $$L |_{\operatorname{dom}L\cap \operatorname{Ker}P}: \operatorname{dom}L\cap \operatorname{Ker}P\rightarrow \operatorname{Im}L$$ is reversible. We denote the inverse of this map by $$K_{P}$$, i.e. $${K_{P}} = L_{P}^{ - 1}$$ and $${K_{P,Q}} = {K_{P}} ( {I - Q} )$$. If Ω is an open bounded subset of X and $$\operatorname{dom}L \cap \Omega \ne \varnothing$$, then the map N is L-compact on Ω̅ when $$QN:\overline{\Omega}\to Y$$ is bounded and $${K_{P}} ( {I - Q} )N:\overline{\Omega}\to X$$ is compact.

### Theorem 2.1



Let L be a Fredholm operator of index zero and N be L-compact on Ω̅. Assume that the following conditions are satisfied:

$${(a_{1})}$$ :

$$Lx\neq \lambda Nx$$ for any $$(x,\lambda )\in [(\operatorname{dom}L \setminus\operatorname{Ker}L ) \cap \partial \Omega ]\times (0,1)$$;

$${(a_{2})}$$ :

$$Nx\notin \operatorname{Im}L$$ for any $$x\in \operatorname{Ker}L\cap \partial \Omega$$;

$${(a_{3})}$$ :

$$\operatorname{deg}(QN| _{\operatorname{Ker}L},\Omega \cap \operatorname{Ker}L,0)\neq 0$$.

Then the equation $$Lx=Nx$$ has at least one solution in $$\operatorname{dom}L \cap \Omega$$.

### Definition 2.2



The Riemann-Liouville fractional integral of order α ($$\alpha > 0$$) for the function $$x:(0, + \infty ) \to \mathbb{R}$$ is defined as

$$I_{0 + }^{\alpha}x(t) = \frac{1}{\Gamma (\alpha )}\int_{0}^{t} (t - s)^{\alpha - 1} x(s)\,ds,$$

provided that the right-hand side integral is defined on $$(0, + \infty)$$.

### Definition 2.3



The Caputo fractional integral of order α ($$\alpha > 0$$) for the function $$x:(0, + \infty ) \to \mathbb{R}$$ is defined as

$$^{C}D_{0 + }^{\alpha}x(t) =I_{0 + }^{n - \alpha }\frac{{{d^{n}}x(t)}}{{d{t^{n}}}} = \frac{1}{{\Gamma (n - \alpha )}}\int_{0}^{t} {{(t - s)}^{n - \alpha - 1}}x^{(n)}(s)\,ds,$$

where $$n = [ \alpha ]+1$$, provided that the right-hand side integral is defined on $$(0, + \infty)$$.

### Lemma 2.1



Let $$n-1<\alpha \leq n$$, if $${}^{C}D_{0+}^{\alpha }x(t)\in C[0,1]$$, then

$$I_{0+}^{\alpha }\, ^{C}D_{0+}^{\alpha }x(t)=x(t)+c_{0}+c_{1}t+c_{2}t^{2}+ \cdots +c_{n-1}t^{n-1},$$

where $$c_{i} \in \mathbb{R}$$, $$i = 0,1, \ldots ,n-1$$, $$n = [ \alpha ]+1$$.

### Lemma 2.2



If $$n-1<\alpha \leq n$$, then the fractional differential $${}^{C}D_{0+}^{\alpha }x(t)=0$$ has the following form:

$$x(t)=c_{0}+c_{1}t+c_{2}t^{2}+\cdots +c_{n-1}t^{n-1},$$

where $$c_{i} \in \mathbb{R}$$, $$i = 0,1, \ldots ,n-1$$, $$n = [ \alpha ]+1$$.

### Lemma 2.3



Let $$x(t)\in C[0,1]$$, $$\alpha >0$$, then

$$^{C}D_{0+}^{\alpha }I_{0+}^{\alpha }x(t)=x(t).$$

### Lemma 2.4



Let $$\alpha >\beta >0$$, then for any $$x\in C[0,1]\cap L^{1}[0,1]$$,

$$^{C}D_{0+}^{\beta }I_{0+}^{\alpha }x(t)=I_{0+}^{\alpha -\beta }x(t).$$

### Lemma 2.5



Let $$x(t)\in L[0,1]$$, $$\alpha ,\beta >0$$, then

$$I_{0+}^{\alpha }I_{0+}^{\beta }x(t)=I_{0+}^{\alpha +\beta }x(t).$$

## Main result

In order to prove the solvability of BVP (1.1), some notations are introduced.

In this paper, we define $$X = {C^{n - 1}} [ {0,1} ]$$ with the norm $${ \Vert x \Vert _{X}} = \max \{ {{ \Vert x \Vert }_{\infty}},{{ \Vert {x'} \Vert }_{\infty}}, \ldots , {{ \Vert {{x^{ ( {n - 1} )}}} \Vert }_{\infty}} \}$$ and $$Y = C [ {0,1} ]$$ with the norm $${ \Vert y \Vert _{Y}} = { \Vert y \Vert _{\infty}}$$, where $${ \Vert x \Vert _{\infty}} = \max_{t \in [ {0,1} ]} \vert {x ( t )} \vert$$. It is clear that $$( {X,{{ \Vert \cdot \Vert }_{X}}} )$$ and $$( {Y,{{ \Vert \cdot \Vert }_{Y}}} )$$ are Banach space. Furthermore, we consider Banach space $$\overline{X} = X \times X$$ with the norm $${ \Vert { ( {u,v} )} \Vert _{\overline{X} }} = \max \{ {{{ \Vert u \Vert }_{X}},{{ \Vert v \Vert }_{X}}} \}$$ and $$\overline{Y}= Y \times Y$$ with the norm $${ \Vert { ( {x,y} )} \Vert _{\overline{Y} }} = \max \{ {{{ \Vert x \Vert }_{Y}},{{ \Vert y \Vert }_{Y}}} \}$$.

Define the linear operator $${L_{1}}:\operatorname{dom}{L_{1}} \subset X \to Y$$ as

$${L_{1}}u = D_{0 + }^{\alpha}u,$$

where

\begin{aligned} \operatorname{dom} {L_{1}} =& \bigl\{ {u \in X|D_{0 + }^{\alpha}u ( t ) \in Y,u ( 0 ) = u' ( 0 ) = \cdots = {u^{ ( {n - 3} )}} ( 0 ) = 0,} \\ &{{u^{ ( {n - 2} )}} ( 0 ) = {\gamma _{1}} {u^{ ( {n - 1} )}} ( {{\xi _{1}}} ),{u^{ ( {n - 1} )}} ( 1 ) = {\delta _{1}} {u^{ ( {n - 2} )}} ( {{\eta _{1}}} )} \bigr\} . \end{aligned}

Define the linear operator $${L_{2}}:\operatorname{dom}{L_{2}} \subset X \to Y$$ as

$${L_{2}}v = D_{0 + }^{\beta}v,$$

where

\begin{aligned} \operatorname{dom} {L_{2}} =& \bigl\{ v \in X|D_{0 + }^{\beta}v ( t ) \in Y,v ( 0 ) = v' ( 0 ) = \cdots = {v^{ ( {n - 3} )}} ( 0 ) = 0, \\ & {{v^{ ( {n - 2} )}} ( 0 ) = {\gamma _{2}} {v^{ ( {n - 1} )}} ( {{\xi _{2}}} ),{v^{ ( {n - 1} )}} ( 1 ) = {\delta _{2}} {v^{ ( {n - 2} )}} ( {{\eta _{2}}} )} \bigr\} . \end{aligned}

Define the operator $$L:\operatorname{dom}L \subset \overline{X} \to \overline{Y}$$ as

$$L ( {u,v} ) = ( {{L_{1}}u,{L_{2}}v} ),$$
(3.1)

where $$\operatorname{dom}L = \{ { ( {u,v} ) \in \overline{X} |u \in \operatorname{dom}{L_{1}},v \in \operatorname{dom}{L_{2}}} \}$$, and we define $$N:\overline{X} \to \overline{Y}$$ by setting

$$N ( {u,v} ) = ( {{N_{1}}v,{N_{2}}u} ),$$

where $${N_{1}}:Y \to X$$ is defined as

$${N_{1}}v ( t ) = f \bigl( {t,v ( t ),v' ( t ), \ldots ,{v^{ ( {n - 1} )}} ( t )} \bigr),$$

and $${N_{2}}:Y \to X$$ is defined as

$${N_{2}}u ( t ) = g \bigl( {t,u ( t ),u' ( t ), \ldots ,{u^{ ( {n - 1} )}} ( t )} \bigr).$$

Then BVP (1.1) is equivalent to the following operator equation:

$$L ( {u,v} ) = N ( {u,v} ), \quad ( {u,v} ) \in \operatorname{dom}L.$$

Next we establish the existence results for BVP (1.1) in the following cases:

Case (i):

$${\gamma _{1}} = {\gamma _{2}} = 0$$, $${\delta _{1}}{\eta _{1}} = {\delta _{2}}{\eta _{2}} = 1$$;

Case (ii):

$$( {{\gamma _{1}} + {\eta _{1}}} ){\delta _{1}} = ( {{\gamma _{2}} + {\eta _{2}}} ){\delta _{2}} = 1$$.

Firstly, the main conclusions of Case (i) are given as follows.

### Theorem 3.1

For Case (i), assume that the following conditions hold.

$$(\mathrm{H}_{1})$$ :

If the functions $$f,g: [ {0,1} ] \times {\mathbb{R}^{n}} \to \mathbb{R}$$ satisfy the Carathéodary condition, and there exist nonnegative functions $${a_{i}},{d_{i}},{b_{1}},{b_{2}},{r_{1}},{r_{2}} \in Y$$ and constant $${\theta _{1}},{\theta _{2}} \in [ {0,1} )$$, $$i = \overline {0,n - 1}$$, for $$\forall ( {{x_{0}},{x_{1}}, \ldots ,{x_{n - 1}}} ) \in {\mathbb{R}^{n}}$$, $$t \in [ {0,1} ]$$, the following inequalities hold:

\begin{aligned} & \bigl\vert {f ( {t,{x_{0}},{x_{1}},{x_{2}}, \ldots ,{x_{n - 1}}} )} \bigr\vert \le \sum_{i = 0}^{n - 1} {{a_{i}} ( t )} \vert {{x_{i}}} \vert + {b_{1}} ( t )\sum_{i = 0}^{n - 1} {{ \vert {{x_{i}}} \vert }^{{\theta _{1}}}} + {r_{1}} ( t ), \\ & \bigl\vert {g ( {t,{x_{0}},{x_{1}},{x_{2}}, \ldots ,{x_{n - 1}}} )} \bigr\vert \le \sum_{i = 0}^{n - 1} {{d_{i}} ( t )} \vert {{x_{i}}} \vert + {b_{2}} ( t )\sum_{i = 0}^{n - 1} {{{ \vert {{x_{i}}} \vert }^{{\theta _{2}}}} + } {r_{2}} ( t ). \end{aligned}
$$(\mathrm{H}_{2})$$ :

There exists a constant $$M>0$$ such that for $$\forall t \in [ {0,1} ]$$, if $$\vert {{u^{ ( {n- 1} )}} ( t )} \vert > M$$ and $$\vert {{v^{ ( {n - 1} )}} ( t )} \vert > M$$, then $$QN ( {u,v} ) \ne ( {0,0} )$$.

$$(\mathrm{H}_{3})$$ :

There exists a constant $$M^{*}>0$$ such that for $$\forall {c_{1}},{c_{2}} \in \mathbb{R}$$ satisfying $$\min \{ { \vert {{c_{1}}} \vert , \vert {{c_{2}}} \vert } \} > {M^{*}}$$, one has either

$${c_{1}} {N_{1}} \bigl( {{c_{2}} {t^{n - 1}}} \bigr) > 0,\qquad {c_{2}} {N_{2}} \bigl( {{c_{1}} {t^{n - 1}}} \bigr) > 0,$$

or

$${c_{1}} {N_{1}} \bigl( {{c_{2}} {t^{n - 1}}} \bigr) < 0,\qquad {c_{2}} {N_{2}} \bigl( {{c_{1}} {t^{n - 1}}} \bigr) < 0.$$
$$(\mathrm{H}_{4})$$ :

$$\max \{ 2{a_{1}}\sum_{i = 0}^{n - 1} { \Vert {{a_{i}}} \Vert }_{\infty}, {a_{1}}\sum_{i = 0}^{n - 1} { \Vert {{a_{i}}} \Vert }_{\infty}+ {a_{2}}\sum_{i = 0}^{n - 1} { \Vert {{d_{i}}} \Vert }_{\infty}, 2{a_{2}}\sum_{i = 0}^{n - 1} { \Vert {{d_{i}}} \Vert }_{\infty}\} < 1$$, where $${a_{1}} = \frac{1}{{\Gamma ( {\alpha - n + 2} )}}$$, $${a_{2}} = \frac{1}{{\Gamma ( {\beta - n + 2} )}}$$.

Then BVP (1.1) has at least one solution.

To prove the above theorem, we begin with the following lemmas.

### Lemma 3.1

Let L be defined by (3.1), then

\begin{aligned} &\operatorname{Ker}L = ( \operatorname{Ker} {L_{1}}, \operatorname{Ker} {L_{2}} ) = \bigl\{ { ( {u,v} ) \in \overline{X} | ( {u,v} ) = \bigl( {{c_{1}} {t^{n - 1}},{c_{2}} {t^{n - 1}}} \bigr),{c_{1}}, {c_{2}} \in \mathbb{R}} \bigr\} , \\ &\operatorname{Im} L = ( \operatorname{Im} {L_{1}},\operatorname{Im} {L_{2}} ) = \bigl\{ { ( {x,y} ) \in \overline{Y}|{T_{1}}x = 0, {T_{2}}y = 0} \bigr\} , \end{aligned}

where

\begin{aligned} &{T_{1}}x = { \int_{0}^{1} { ( {1 - s} )} ^{\alpha - n}}x ( s ) \,ds - \frac{{{\delta _{1}}}}{{\alpha - n + 1}}{ \int_{0}^{{\eta _{1}}} { ( {{\eta _{1}} - s} )} ^{\alpha - n + 1}}x ( s )\,ds , \\ &{T_{2}}y = { \int_{0}^{1} { ( {1 - s} )} ^{\beta - n}}y ( s ) \,ds - \frac{{{\delta _{2}}}}{{\beta - n + 1}}{ \int_{0}^{{\eta _{2}}} { ( {{\eta _{2}} - s} )} ^{\beta - n + 1}}y ( s )\,ds . \end{aligned}

### Proof

According to Lemma 2.2, $${L_{1}}u = D_{0 + }^{\alpha}u ( t ) = 0$$ has the solution

$$u ( t ) = {c_{0}} + {c_{1}}t + {c_{2}} {t^{2}} + \cdots + {c_{n - 1}} {t^{n - 1}},\quad {c_{i}} \in \mathbb{R}, i = \overline {0,n - 1} .$$

By the definition of $$\operatorname{dom}{L_{1}}$$, we have $${c_{i}} = 0$$, $$i = \overline {0,n - 2}$$, thus

$$\operatorname{Ker} {L_{1}} = \bigl\{ {u \in X|u ( t ) = {c_{1}} {t^{n - 1}}, \forall t \in [ {0,1} ], {c_{1}} \in \mathbb{R}} \bigr\} .$$

For $$x \in \operatorname{Im} {L_{1}}$$, there exists $${u \in \operatorname{dom}{L_{1}}}$$ such that $$x = {L_{1}}u \in Y$$. From Lemma 2.1, we have

$$u ( t ) = I_{0 + }^{\alpha}x ( t ) + {c_{0}} + {c_{1}}t + {c_{2}} {t^{2}} + \cdots + {c_{n - 1}} {t^{n - 1}}.$$

Then by the definition of $${\operatorname{dom}{L_{1}}}$$ we have $${c_{i}} = 0,i = \overline {0,n - 2}$$. Hence

$$u ( t ) = I_{0 + }^{\alpha}x ( t ) + {c_{n - 1}} {t^{n - 1}}.$$

According to Lemma 2.4, we obtain

\begin{aligned} &{u^{ ( {n - 1} )}} ( t ) = I_{0 + }^{\alpha - n + 1}x ( t ) + {c_{n - 1}} ( {n - 1} )!, \\ &{u^{ ( {n - 2} )}} ( t ) = I_{0 + }^{\alpha - n + 2}x ( t ) + {c_{n - 1}} ( {n - 1} )!t. \end{aligned}

Taking into account the boundary condition $${u^{ ( {n - 1} )}} ( 1 ) = {\delta _{1}}{u^{ ( {n - 2} )}} ( {{\eta _{1}}} )$$ and $${\delta _{1}}{\eta _{1}} = 1$$ of Case (i), we see that x satisfies

$${T_{1}}x = { \int_{0}^{1} { ( {1 - s} )} ^{\alpha - n}}x ( s ) \,ds - \frac{{{\delta _{1}}}}{{\alpha - n + 1}}{ \int_{0}^{{\eta _{1}}} { ( {{\eta _{1}} - s} )} ^{\alpha - n + 1}}x ( s )\,ds = 0.$$

On the other hand, assume that $$x \in Y$$ satisfies the equation $${T_{1}}x = 0$$. Let $$u ( t ) = I_{0 + }^{\alpha}x ( t )$$, then $$u \in \operatorname{dom}{L_{1}}$$. By Lemma 2.3, we have $$D_{0 + }^{\alpha}u ( t ) = x ( t )$$, so $$x \in \operatorname{Im} {L_{1}}$$. Then we get

$$\operatorname{Im} {L_{1}} = \{ {x \in Y|{T_{1}}x = 0} \}.$$

Similarly, we have

\begin{aligned} &\operatorname{Ker} {L_{2}} = \bigl\{ {v \in X|v ( t ) = {c_{2}} {t^{n - 1}},\forall t \in [ {0,1} ],{c_{2}} \in \mathbb{R}} \bigr\} , \\ &\operatorname{Im} {L_{2}} = \{ {y \in Y|{T_{2}}y = 0} \}. \end{aligned}

Then, the proof is complete. □

### Lemma 3.2

Let L be defined by (3.1), then L is a Fredholm operator of index zero. The linear continuous projector operators $$P:\overline{X} \to \overline{X}$$ and $$Q:\overline{Y} \to \overline{Y}$$ can be defined as

\begin{aligned} &P ( {u,v} ) = ( {{P_{1}}u,{P_{2}}v} ) = \biggl( { \frac{{{u^{ ( {n - 1} )}} ( 0 )}}{{ ( {n - 1} )!}}{t^{n - 1}},\frac{{{v^{ ( {n - 1} )}} ( 0 )}}{{ ( {n - 1} )!}}{t^{n - 1}}} \biggr), \\ &Q ( {x,y} ) = ( {{Q_{1}}x,{Q_{2}}y} ) = \biggl( { \frac{{\alpha - n + 1}}{{1 - \frac{{{\eta _{1}}^{\alpha - n + 1}}}{{\alpha - n + 2}}}}{T_{1}}x,\frac{{\beta - n + 1}}{{1 - \frac{{{\eta _{2}}^{\beta - n + 1}}}{{\beta - n + 2}}}}{T_{2}}y} \biggr), \end{aligned}

and $${K_{P}}:\operatorname{Im} L \to \operatorname{dom}L \cap \operatorname{Ker}P$$ by

$${K_{P}} ( {x,y} ) = \bigl( {I_{0 + }^{\alpha}x ( t ),I_{0 + }^{\beta}y ( t )} \bigr).$$

### Proof

Obviously $$\operatorname{Im} P = \operatorname{Ker}L$$ and $${P^{2}} ( {u,v} ) = P ( {u,v} )$$. Since $$( {u,v} ) = ( { ( {u,v} ) - P ( {u,v} )} ) + P ( {u,v} )$$, it is clear that $$\overline{X} = \operatorname{Ker}P + \operatorname{Ker}L$$. By calculation, we get $$\operatorname{Ker}L \cap \operatorname{Ker}P = \{ { ( {0,0} )} \}$$. Thus, we obtain

$$\overline{X} = \operatorname{Ker}L \oplus \operatorname{Ker}P.$$

For every $$( {u,v} ) \in \overline{X}$$, we have

$${ \bigl\Vert {P ( {u,v} )} \bigr\Vert _{\overline{X}}} \le \max \bigl\{ { \bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert , \bigl\vert {{v^{ ( {n - 1} )}} ( 0 )} \bigr\vert } \bigr\} .$$
(3.2)

Taking $$( {x,y} ) \in \overline{Y}$$, one has

$${Q^{2}} ( {x,y} ) = Q ( {{Q_{1}}x,{Q_{2}}y} ) = \bigl( {{Q_{1}}^{2}x,{Q_{2}}^{2}y} \bigr).$$

By the definition of $${{Q_{1}}}$$, we obtain

$$Q_{1}^{2}x = {Q_{1}}x \cdot \frac{{\alpha - n + 1}}{{1 - \frac{{{\eta _{1}}^{\alpha - n + 1}}}{{\alpha - n + 2}}}} \biggl( \int_{0}^{1} ( {1 - s} )^{\alpha - n} \,ds - \frac{\delta _{1}}{\alpha - n + 1} \int_{0}^{\eta _{1}} ( {{\eta _{1}} - s} ) ^{\alpha - n + 1} \,ds \biggr) = {Q_{1}}x,$$

where for the denominator $$1 - \frac{{{\eta _{1}}^{\alpha - n + 1}}}{{\alpha - n + 2}} > 0$$ can be verified.

Similarly, $$Q_{2}^{2}y = {Q_{2}}y$$. This gives $${Q^{2}} ( {x,y} ) = Q ( {x,y} )$$. Let $$( {x,y} ) = ( { ( {x,y} ) - Q ( {x,y} )} ) + Q ( {x,y} )$$, where $$( {x,y} ) - Q ( {x,y} ) \in \operatorname{Ker}Q = \operatorname{Im} L$$, $$Q ( {x,y} ) \in \operatorname{Im} Q$$. It follows from $$\operatorname{Ker}Q = \operatorname{Im} L$$ and $${Q^{2}} ( {x,y} ) = Q ( {x,y} )$$ that $$\operatorname{Im} Q \cap \operatorname{Im} L = \{ { ( {0,0} )} \}$$. Then, we have

$$\overline{Y} = \operatorname{Im} L \oplus \operatorname{Im} Q.$$

Thus

$$\dim \operatorname{Ker} L = \dim \operatorname{Im} Q = \operatorname{codim} \operatorname{Im} L.$$

This means that L is a Fredholm operator of index zero.

Now we prove that $${K_{P}}$$ is the inverse operator of $$L|_{\operatorname{dom}L \cap \operatorname{Ker}P}$$. By Lemma 2.3, for $$( {x,y} ) \in \operatorname{Im} L$$, we obtain

$$L{K_{P}} ( {x,y} ) = \bigl( {D_{0 + }^{\alpha}\bigl( {I_{0 + }^{\alpha}x} \bigr),D_{0 + }^{\beta}\bigl( {I_{0 + }^{\beta}y} \bigr)} \bigr) = ( {x,y} ).$$

Moreover, for $$( {u,v} ) \in \operatorname{dom}L \cap \operatorname{Ker}P$$, we have $${u^{ ( {n - 1} )}} ( 0 ) = {v^{ ( {n - 1} )}} ( 0 ) = 0$$. Together with the boundary condition, we get

$${K_{P}}L ( {u,v} ) = \bigl( {I_{0 + }^{\alpha}D_{0 + }^{\alpha}u ( t ),I_{0 + }^{\beta}D_{0 + }^{\beta}v ( t )} \bigr) = ( {u,v} ).$$

To summarize, $${K_{P}} = { ( L|_{\operatorname{dom}L \cap \operatorname{Ker}P} )^{ - 1}}$$.

Hence, for each $$( {x,y} ) \in \operatorname{Im} L$$, by the definition of $${ \Vert \cdot \Vert _{\overline{X}}}$$ we have

\begin{aligned} { \bigl\Vert {{K_{P}} ( {x,y} )} \bigr\Vert _{\overline{X}}} &\le \max \biggl\{ {\frac{1}{{\Gamma ( {\alpha - n + 2} )}}{{ \Vert x \Vert }_{\infty}}, \frac{1}{{\Gamma ( {\beta - n + 2} )}}{{ \Vert y \Vert }_{\infty}}} \biggr\} \\ &: = \max \bigl\{ {{a_{1}} {{ \Vert x \Vert }_{\infty}},{a_{2}} {{ \Vert y \Vert }_{\infty}}} \bigr\} , \end{aligned}
(3.3)

where $${a_{1}} = \frac{1}{{\Gamma ( {\alpha - n + 2} )}}$$, $${a_{2}} = \frac{1}{{\Gamma ( {\beta - n + 2} )}}$$. The proof is complete. □

The main proof of Theorem 3.1 is given by the following three steps.

### Proof of Theorem 3.1

Step 1 Let

$${\Omega _{1}} = \bigl\{ { ( {u,v} ) \in \operatorname{dom}L\backslash \operatorname{Ker} L \vert {L ( {u,v} ) = \lambda N ( {u,v} )} , \lambda \in ( {0,1} )} \bigr\} .$$

For $$( {u,v} ) \in {\Omega _{1}}$$, we have $$L ( {u,v} ) = \lambda N ( {u,v} ) \in \operatorname{Im} L = \operatorname{Ker}Q$$, thus $$QN ( {u,v} ) = ( {0,0} )$$, i.e. $${Q_{1}}{N_{1}}v ( t ) = 0$$, $${Q_{2}}{N_{2}}u ( t ) = 0$$. From $$(\mathrm{H}_{2})$$, we know there exists $${t_{0}},{t_{1}} \in ( {0,1} )$$, such that $$\vert {{v^{ ( {n - 1} )}} ( {{t_{0}}} )} \vert \le M$$ and $$\vert {{u^{ ( {n - 1} )}} ( {{t_{1}}} )} \vert \le M$$. It is easy to check that $${ \Vert u \Vert _{X}} = { \Vert {{u^{ ( {n - 1} )}}} \Vert _{\infty}},{ \Vert v \Vert _{X}} = { \Vert {{v^{ ( {n - 1} )}}} \Vert _{\infty}}$$ for all $$u \in \operatorname{dom}{L_{1}}$$, $$v \in \operatorname{dom}{L_{2}}$$. Again for $$( {u,v} ) \in {\Omega _{1}}$$, then $$( {I - P} ) ( {u,v} ) \in \operatorname{dom}L \cap \operatorname{Ker} P$$ and $$LP ( {u,v} ) = ( {0,0} )$$. Hence, from (3.3), we get

\begin{aligned}[b] { \bigl\Vert { ( {I - P} ) ( {u,v} )} \bigr\Vert _{\overline{X}}}& = { \bigl\Vert {{K_{p}}L ( {I - P} ) ( {u,v} )} \bigr\Vert _{\overline{X}}} = { \bigl\Vert {{K_{p}}L ( {u,v} )} \bigr\Vert _{\overline{X}}} = { \bigl\Vert {{K_{p}} ( {{L_{1}}u,{L_{2}}v} )} \bigr\Vert _{\overline{X}}} \\ &\le \max \bigl\{ {{a_{1}} {{ \Vert {{N_{1}}v} \Vert }_{\infty}},{a_{2}} {{ \Vert {{N_{2}}u} \Vert }_{\infty}}} \bigr\} . \end{aligned}
(3.4)

By $$L_{1} u = \lambda N_{1} u$$ and $$u \in \operatorname{dom} L_{1}$$, we have

\begin{aligned} u ( t ) ={} &\frac{\lambda }{{\Gamma ( \alpha )}} \int_{0}^{t} {{{ ( {t - s} )}^{\alpha - 1}}f \bigl( {s,v ( s ),v' ( s ), \ldots ,{v^{ ( {n - 1} )}} ( s )} \bigr)} \,ds \\ &{}- u ( 0 ) - u' ( 0 )t - \cdots - \frac{{{u^{ ( {n - 1} )}} ( 0 )}}{{ ( {n - 1} )!}}{t^{n - 1}}. \end{aligned}

Furthermore, we obtain

$${u^{ ( {n - 1} )}} ( t ) = \frac{\lambda }{{\Gamma ( {\alpha - n + 1} )}} \int_{0}^{t} {{{ ( {t - s} )}^{\alpha - n}}f \bigl( {s,v ( s ),v' ( s ), \ldots ,{v^{ ( {n - 1} )}} ( s )} \bigr)} \,ds - {u^{ ( {n - 1} )}} ( 0 ),$$

then substituting $$t=t_{1}$$ into the above equation, we get

$${u^{ ( {n - 1} )}} ( {{t_{1}}} ) = \frac{\lambda }{{\Gamma ( {\alpha - n + 1} )}} \int_{0}^{{t_{1}}} {{{ ( {{t_{1}} - s} )}^{\alpha - n}}f \bigl( {s,v ( s ),v' ( s ), \ldots ,{v^{ ( {n - 1} )}} ( s )} \bigr)} \,ds - {u^{ ( {n - 1} )}} ( 0 ).$$

Together with $$\vert {{u^{ ( {n - 1} )}} ( {{t_{1}}} )} \vert \le M$$ and $$(\mathrm{H}_{1})$$, we get

\begin{aligned} \bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert \le {}&\biggl\vert {\frac{\lambda }{{\Gamma ( {\alpha - n + 1} )}} \int_{0}^{{t_{1}}} {{{ ( {{t_{1}} - s} )}^{\alpha - n}}f \bigl( {s,v ( s ),v' ( s ), \ldots ,{v^{ ( {n - 1} )}} ( s )} \bigr)} \,ds} \biggr\vert + \bigl\vert {{u^{ ( {n - 1} )}} ( {{t_{1}}} )} \bigr\vert \\ \le{}& \frac{1}{{\Gamma ( {\alpha - n + 1} )}} \int_{0}^{{t_{1}}} {{{ ( {{t_{1}} - s} )}^{\alpha - n}} \bigl\vert {f \bigl( {s,v ( s ),v' ( s ), \ldots ,{v^{ ( {n - 1} )}} ( s )} \bigr)} \bigr\vert } \,ds + M \\ \le {}&\frac{1}{{\Gamma ( {\alpha - n + 1} )}} \int_{0}^{{t_{1}}} {{{ ( {{t_{1}} - s} )}^{\alpha - n}} \Biggl( {\sum_{i = 0}^{n - 1} {{a_{i}} ( t )} \bigl\vert {{v^{ ( i )}}} \bigr\vert + {b_{1}} ( t )\sum_{i = 0}^{n - 1} {{ \bigl\vert {{v^{ ( i )}}} \bigr\vert }^{{\theta _{1}}}} + {r_{1}} ( t )} \Biggr)} \,ds \\ &{} + M \\ \le {}&\frac{1}{{\Gamma ( {\alpha - n + 1} )}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}+ {{ \Vert {{b_{1}}} \Vert }_{\infty}}\sum_{i = 0}^{n - 1} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + {{ \Vert {{r_{1}}} \Vert }_{\infty}}} } \Biggr) \\ &{}\times\int_{0}^{{t_{1}}} {{{ ( {{t_{1}} - s} )}^{\alpha - n}}} \,ds + M \\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}+ {{ \Vert {{b_{1}}} \Vert }_{\infty}} \sum_{i = 0}^{n - 1} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + {{ \Vert {{r_{1}}} \Vert }_{\infty}}}} \Biggr) + M, \end{aligned}
(3.5)

where $${a_{1}} = \frac{1}{{\Gamma ( {\alpha - n + 2} )}}$$. Similarly, we obtain

$$\bigl\vert {v^{ ( {n - 1} )}} ( 0 ) \bigr\vert \le {a_{2}} \Biggl( \sum_{i = 0}^{n - 1} \Vert {{d_{i}}} \Vert _{\infty}\bigl\Vert {u^{ ( i )}} \bigr\Vert _{\infty}+ \Vert {{b_{2}}} \Vert _{\infty}\sum _{i = 0}^{n - 1} \bigl\Vert {u^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{2}}} + \Vert {{r_{2}}} \Vert _{\infty}\Biggr) + M,$$
(3.6)

where $${a_{2}} = \frac{1}{{\Gamma ( {\beta - n + 2} )}}$$. Combined with (3.2) and (3.4), we get

\begin{aligned} { \bigl\Vert { ( {u,v} )} \bigr\Vert _{\overline{X}}}= {}& { \bigl\Vert {P ( {u,v} ) + ( {I - P} ) ( {u,v} )} \bigr\Vert _{\overline{X}}} \\ \le{}& { \bigl\Vert {P ( {u,v} )} \bigr\Vert _{\overline{X}}} + { \bigl\Vert { ( {I - P} ) ( {u,v} )} \bigr\Vert _{\overline{X}}} \\ \le {}&\max \bigl\{ { \bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert + {a_{1}} {{ \Vert {{N_{1}}v} \Vert }_{\infty}}, \bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert + {a_{2}} {{ \Vert {{N_{2}}u} \Vert }_{\infty}},} \\ & { \bigl\vert {{v^{ ( {n - 1} )}} ( 0 )} \bigr\vert + {a_{1}} {{ \Vert {{N_{1}}v} \Vert }_{\infty}}, \bigl\vert {{v^{ ( {n - 1} )}} ( 0 )} \bigr\vert + {a_{2}} {{ \Vert {{N_{2}}u} \Vert }_{\infty}}} \bigr\} . \end{aligned}

Next, we will prove this conclusion in four cases.

Case 1 $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{u^{ ( {n - 1} )}} ( 0 )} \vert + {a_{1}}{ \Vert {{N_{1}}v} \Vert _{\infty}}$$.

By (3.5) and $$(\mathrm{H}_{1})$$, we get

\begin{aligned} { \bigl\Vert { ( {u,v} )} \bigr\Vert _{\overline{X}}} \le{}& \bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert + {a_{1}} { \Vert {{N_{1}}v} \Vert _{\infty}} \\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}} + {{ \Vert {{b_{1}}} \Vert }_{\infty}}\sum_{i = 0}^{n - 1} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + {{ \Vert {{r_{1}}} \Vert }_{\infty}}} } \Biggr) + M \\ &{} + {a_{1}} { \bigl\Vert {f \bigl( {t,v ( t ),v' ( t ), \ldots ,{v^{ ( {n - 1} )}} ( t )} \bigr)} \bigr\Vert _{\infty}} \\ \le {}& 2{a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}} + {{ \Vert {{b_{1}}} \Vert }_{\infty}}\sum_{i = 0}^{n - 1} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}}+ {{ \Vert {{r_{1}}} \Vert }_{\infty}}} \Biggr) + M \\ \le{}& 2{a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}+ n{{ \Vert {{b_{1}}} \Vert }_{\infty}} \bigl\Vert {v^{ ( n-1 )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + {{ \Vert {{r_{1}}} \Vert }_{\infty}}} \Biggr) + M \\ \le {} & 2{a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} {{ \Vert v \Vert }_{X}} + n{{ \Vert {{b_{1}}} \Vert }_{\infty}} \Vert v \Vert _{X}^{{\theta _{1}}} + {{ \Vert {{r_{1}}} \Vert }_{\infty}}} \Biggr) + M. \end{aligned}

According to $$(\mathrm{H}_{4})$$ and the definition of $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}}$$, from the above inequality, we can derive that $${ \Vert v \Vert _{X}}$$ is bounded. Therefore $${\Omega _{1}}$$ is bounded.

Case 2 $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{v^{ ( {n - 1} )}} ( 0 )} \vert + {a_{2}}{ \Vert {{N_{2}}u} \Vert _{\infty}}$$. The proof is similar to Case 1. Here, we omit it.

Case 3 $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{u^{ ( {n - 1} )}} ( 0 )} \vert + {a_{2}}{ \Vert {{N_{2}}u} \Vert _{\infty}}$$.

From (3.5) and $$(\mathrm{H}_{1})$$, we get

\begin{aligned} \bigl\Vert (u,v) \bigr\Vert _{\overline{X}} \le{}& \bigl\vert {u^{(n - 1)}}(0) \bigr\vert + {a_{2}} \Vert {N_{2}}u \Vert _{\infty}\\ \le{}& {a_{1}} \Biggl( \sum_{i = 0}^{n - 1} \Vert {a_{i}} \Vert _{\infty}\bigl\Vert {v^{(i)}} \bigr\Vert _{\infty}+ \Vert {b_{1}} \Vert _{\infty}\sum_{i = 0}^{n - 1} { \bigl\Vert {v^{(i)}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr) + M \\ &{} + {a_{2}} \bigl\Vert g \bigl(t,u(t),u'(t), \ldots ,{u^{(n - 1)}}(t) \bigr) \bigr\Vert _{\infty}\\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} \Vert {a_{i}} \Vert _{\infty}\bigl\Vert {v^{(i)}} \bigr\Vert _{\infty}+ \Vert {b_{1}} \Vert _{\infty}\sum_{i = 0}^{n - 1} \bigl\Vert {v^{(i)}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr) + M \\ &{} + {a_{2}} \Biggl( {\sum_{i = 0}^{n - 1} \Vert {d_{i}} \Vert _{\infty}\bigl\Vert {u^{(i)}} \bigr\Vert _{\infty}+ \Vert {b_{2}} \Vert _{\infty}\sum_{i = 0}^{n - 1} \bigl\Vert {u^{(i)}} \bigr\Vert _{\infty}^{{\theta _{2}}} + \Vert {r_{2}} \Vert _{\infty}} \Biggr) \\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}} \bigl\Vert {v^{ ( {n - 1} )}} \bigr\Vert _{\infty}+ n \Vert {b_{1}} \Vert _{\infty}\bigl\Vert {v^{ ( {n - 1} )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr) + M \\ &{}+ {a_{2}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {d_{i}} \Vert _{\infty}} \bigl\Vert {u^{ ( {n - 1} )}} \bigr\Vert _{\infty}+ n \Vert {b_{2}} \Vert _{\infty}\bigl\Vert {u^{ ( {n - 1} )}} \bigr\Vert _{\infty}^{{\theta _{2}}} + \Vert {r_{2}} \Vert _{\infty}} \Biggr) \\ = {}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} {{ \Vert v \Vert }_{X}} + n{{ \Vert {{b_{1}}} \Vert }_{\infty}} \Vert v \Vert _{X}^{{\theta _{1}}} + {{ \Vert {{r_{1}}} \Vert }_{\infty}}} \Biggr) \\ &{} + {a_{2}} \Biggl( {\sum_{i = 0}^{n - 1} {{{ \Vert {{d_{i}}} \Vert }_{\infty}}} {{ \Vert u \Vert }_{X}} + n{{ \Vert {{b_{2}}} \Vert }_{\infty}} \Vert u \Vert _{X}^{{\theta _{2}}} + {{ \Vert {{r_{2}}} \Vert }_{\infty}}} \Biggr) + M. \end{aligned}

By $$(\mathrm{H}_{4})$$, from the above inequality, we see that $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}}$$ is bounded. Therefore $${\Omega _{1}}$$ is bounded.

Case 4 $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{v^{ ( {n - 1} )}} ( 0 )} \vert + {a_{1}}{ \Vert {{N_{1}}v} \Vert _{\infty}}$$. The proof is similar to Case 3. Here, we omit it.

According to the above arguments, we prove that $${\Omega _{1}}$$ is bounded.

Step 2 Let

$${\Omega _{2}} = \bigl\{ { ( {u,v} ) \vert { ( {u,v} ) \in \operatorname{Ker} L,N ( {u,v} )} \in \operatorname{Im} L} \bigr\} .$$

For $$( {u,v} ) \in {\Omega _{2}}$$, we have $${ ( {u,v} ) = ( {{c_{1}}{t^{n - 1}},{c_{2}}{t^{n - 1}}} ),{c_{1}},{c_{2}} \in \mathbb{R}}$$. In view of $$N ( {u,v} ) = ( {{N_{1}}v,{N_{2}}u} ) \in \operatorname{Im} L = \operatorname{Ker}Q$$, we have $$QN ( {u,v} ) = ( {0,0} )$$, then $${Q_{1}}{N_{1}}v ( t ) = 0$$, $${Q_{2}}{N_{2}}u ( t ) = 0$$. Together with $$(\mathrm{H}_{2})$$, there exist $${t_{0}},{t_{1}} \in ( {0,1} )$$ such that $$\vert {{v^{ ( {n - 1} )}} ( {{t_{0}}} )} \vert \le M$$, $$\vert {{u^{ ( {n - 1} )}} ( {{t_{1}}} )} \vert \le M$$, which imply $$\vert {{c_{i}}} \vert \le \frac{M}{{ ( {n - 1} )!}}$$, $$i = 1,2$$. Thus, we get

$${ \bigl\Vert { ( {u,v} )} \bigr\Vert _{\overline{X}}} \le M.$$

Hence, $${\Omega _{2}}$$ is bounded.

Step 3 Let

$${\Omega _{3}} = \bigl\{ { ( {u,v} ) \in \operatorname{Ker} L \vert { \lambda ( {u,v} ) + ( {1 - \lambda } )QN ( {u,v} )} = ( {0,0} ), \lambda \in [ {0,1} ]} \bigr\} ,$$

for $$( {u,v} ) \in {\Omega _{3}}$$, we get $$( {u,v} ) = ( {{c_{1}}{t^{n - 1}},{c_{2}}{t^{n - 1}}} ),{c_{1}},{c_{2}} \in \mathbb{R}$$, and

\begin{aligned} &\lambda {c_{1}} {t^{n - 1}} + ( {1 - \lambda } ){Q_{1}} {N_{1}} ( v ) = 0, \\ &\lambda {c_{2}} {t^{n - 1}} + ( {1 - \lambda } ){Q_{2}} {N_{2}} ( u ) = 0, \end{aligned}

that is to say,

\begin{aligned} &\begin{aligned} - \lambda {c_{1}}^{2}{t^{n - 1}} ={}& ( {1 - \lambda } ){c_{1}} {Q_{1}} {N_{1}} ( v ) \\ = {}&( {1 - \lambda } ){c_{1}}\frac{{\alpha - n + 1}}{{1 - \frac{{{\eta _{1}}^{\alpha - n + 1}}}{{\alpha - n + 2}}}} \biggl( \int_{0}^{1} ( {1 - s} ) ^{\alpha - n} f \bigl( {s,{c_{2}} {s^{n - 1}},{c_{2}} ( {n - 1} ){s^{n - 2}}, \ldots ,{c_{2}} ( {n - 1} )!} \bigr)\,ds \\ & {} - \frac{{{\delta _{1}}}}{{\alpha - n + 1}} \int_{0}^{{\eta _{1}}} ( {{\eta _{1}} - s} )^{\alpha - n + 1} f \bigl( {s,{c_{2}} {s^{n - 1}},{c_{2}} ( {n - 1} ){s^{n - 2}}, \ldots ,{c_{2}} ( {n - 1} )!} \bigr) \,ds \biggr), \end{aligned} \\ &\begin{aligned} - \lambda {c_{2}}^{2}{t^{n - 1}} ={}& ( {1 - \lambda } ){c_{2}} {Q_{2}} {N_{2}} ( u ) \\ ={}& ( {1 - \lambda } ){c_{2}}\frac{{\beta - n + 1}}{{1 - \frac{{{\eta _{2}}^{\beta - n + 1}}}{{\beta - n + 2}}}} \biggl( \int_{0}^{1} ( {1 - s} ) ^{\beta - n} g \bigl( {s,{c_{1}} {s^{n - 1}},{c_{1}} ( {n - 1} ){s^{n - 2}}, \ldots ,{c_{1}} ( {n - 1} )!} \bigr) \,ds \\ &{}- \frac{{{\delta _{2}}}}{{\beta - n + 1}} \int_{0}^{{\eta _{2}}} {( {{\eta _{2}} - s} )^{\alpha - n + 1} g \bigl( {s,{c_{1}} {s^{n - 1}},{c_{1}} ( {n - 1} ){s^{n - 2}}, \ldots ,{c_{1}} ( {n - 1} )!} \bigr)\,ds } \biggr). \end{aligned} \end{aligned}

If $$\lambda = 0$$, then $${Q_{1}}{N_{1}} ( v ) = {Q_{2}}{N_{2}} ( u ) = 0$$, together with $$(\mathrm{H}_{2})$$, we have $$\vert {{u^{ ( {n - 1} )}} ( t )} \vert \le M$$, $$\vert {{v^{ ( {n - 1} )}} ( t )} \vert \le M$$, which imply $$\vert {{c_{i}}} \vert \le \frac{M}{{ ( {n - 1} )!}}$$, $$i = 1,2$$. If $$\lambda \in ( {0,1} ]$$, then $$\vert {{c_{i}}} \vert \le \frac{M}{{ ( {n - 1} )!}}$$, $$i = 1,2$$. Otherwise, if $$\vert {{c_{i}}} \vert > \frac{M}{{ ( {n - 1} )!}}$$, $$i = 1,2$$, in view of the first part of $$(\mathrm{H}_{3})$$, the left of the above two equations is less than 0, while the right is greater than 0, which is apparently contradictory. Thus, $${\Omega _{3}}$$ is bounded.

Let Ω is a bounded open set of , such that $$\bigcup _{i = 1}^{3} \overline {{\Omega _{i}}} \subset \Omega$$. It follows from Lemma 3.2 that L is a Fredholm operator of index zero. Based on the Arzela-Ascoli theorem, we obtain the result that N is L-compact on Ω̅. By Step 1 and Step 2, we see that the following two conditions hold:

$$( {{a_{1}}} )$$ :

$$L ( {u,v} ) \ne \lambda N ( {u,v} )$$, $$( { ( {u,v} ),\lambda } ) \in [ { ( {{\operatorname{dom}}L\backslash \operatorname{Ker} L} ) \cap \partial \Omega } ] \times ( {0,1} )$$,

$$( {{a_{2}}} )$$ :

$$Nx \notin \operatorname{Im}L$$, $$( {u,v} ) \in \operatorname{Ker} L \cap \partial \Omega$$.

Let

$$H \bigl( { ( {u,v} ),\lambda } \bigr) = \lambda ( {u,v} ) + ( {1 - \lambda } )QN( {u,v} ).$$

According to Step 3, we get $$H ( { ( {u,v} ),\lambda } ) \ne 0$$ for $$( {u,v} ) \in \operatorname{Ker} L \cap \partial \Omega$$. Therefore,

\begin{aligned} \deg \bigl( QN|_{{\operatorname{Ker}}L},\Omega \cap \operatorname{Ker}L, ( {0,0} ) \bigr)& = \deg \bigl( {H ( { \cdot ,0} ),\Omega \cap \operatorname{Ker}L, ( {0,0} )} \bigr) \\ & = \deg \bigl( {H ( { \cdot ,1} ),\Omega \cap \operatorname{Ker}L, ( {0,0} )} \bigr) \\ & = \deg \bigl( {I, \Omega \cap \operatorname{Ker}L, ( {0,0} )} \bigr) \\ & \ne 0. \end{aligned}

Hence, the condition $$( {{a_{3}}} )$$ of Theorem 2.1 is satisfied. By Theorem 2.1, we see that $$L ( {u,v} ) = N ( {u,v} )$$ has at least one set of fixed points in $$\operatorname{dom}L \cap \overline{\Omega}$$, so BVP (1.1) has at least one set of solutions. The proof is complete. □

### Remark 3.1

If the second part of $$(\mathrm{H}_{3})$$ is satisfied, then the set

$$\Omega _{3}^{\prime}= \bigl\{ { ( {u,v} ) \in \operatorname{Ker}L \vert { - \lambda ( {u,v} ) + ( {1 - \lambda } )QN ( {u,v} )} = ( {0,0} ), \lambda \in [ {0,1} ]} \bigr\}$$

is bounded.

Now we consider BVP (1.1) in the Case (ii); the main conclusion is given as follows.

### Theorem 3.2

For Case (ii), assume that the following conditions hold.

$${ ( {{{\mathrm{H}}_{1}}} )^{\prime}}$$ :

If the functions $$f,g \in [ {0,1} ] \times \mathbb{R}^{n} \to {\mathbb{R}}$$ satisfy the Carathéodary condition, and there exist nonnegative functions $${a_{i}},{d_{i}},{b_{1}},{b_{2}},{r_{1}},{r_{2}} \in Y$$ and constant $${\theta _{1}},{\theta _{2}} \in [ {0,1} )$$, $$i = \overline {0,n - 1}$$, for $$\forall ( {{x_{0}},{x_{1}}, \ldots ,{x_{n - 1}}} ) \in {{\mathbb{R}}^{n}}$$, $$t \in [ {0,1} ]$$, the following inequalities hold:

\begin{aligned} &\bigl\vert {f ( {t,{x_{0}},{x_{1}}, \ldots ,{x_{n - 1}}} )} \bigr\vert \le \sum_{i = 0}^{n - 1} {{a_{i}} ( t ) \vert {{x_{i}}} \vert } + {b_{1}} ( t )\sum_{i = 0}^{n - 1} {{{ \vert {{x_{i}}} \vert }^{{\theta _{1}}}}} + {r_{1}} ( t ), \\ &\vert {g ( {t,{x_{0}},{x_{1}}, \ldots ,{x_{n - 1}}} )} \vert \le \sum_{i = 0}^{n - 1} {{d_{i}} ( t ) \vert {{x_{i}}} \vert } + {b_{2}} ( t )\sum_{i = 0}^{n - 1} {{{ \vert {{x_{i}}} \vert }^{{\theta _{2}}}}} + {r_{2}} ( t ). \end{aligned}
$${ ( {{{\mathrm{H}}_{2}}} )^{\prime}}$$ :

There exists a constant $$M > 0$$, such that, for $$\forall t \in [ {0,1} ]$$, if $$\vert {{u^{ ( {n - 1} )}} ( t )} \vert > M$$ and $$\vert {{v^{ ( {n - 1} )}} ( t )} \vert > M$$, then $$QN ( {u,v} ) \ne ( {0,0} )$$.

$${ ( {{{\mathrm{H}}_{3}}} )^{\prime}}$$ :

There exists a constant $${M^{*}} > 0$$ such that, for every $${c_{1}},{c_{2}} \in {\mathbb{R}}$$ satisfying $$\min \{ { \vert {{c_{1}}} \vert , \vert {{c_{2}}} \vert } \} > {M^{*}}$$, one has either

$${c_{1}}{N_{1}} ( {{c_{2}} ( {{t^{n - 1}} + ( {n - 1} ){\gamma _{2}}{t^{n - 2}}} )} ) > 0,\qquad {c_{2}}{N_{2}} ( {{c_{1}} ( {{t^{n - 1}} + ( {n - 1} ){\gamma _{1}}{t^{n - 2}}} )} ) > 0,$$

or

$${c_{1}}{N_{1}} ( {{c_{2}} ( {{t^{n - 1}} + ( {n - 1} ){\gamma _{2}}{t^{n - 2}}} )} ) < 0,\qquad {c_{2}}{N_{2}} ( {{c_{1}} ( {{t^{n - 1}} + ( {n - 1} ){\gamma _{1}}{t^{n - 2}}} )} ) < 0.$$
$${ ( {{{\mathrm{H}}_{4}}} )^{\prime}}$$ :
\begin{aligned} &\max \Biggl\{ ( {2 + n{\gamma _{1}}} ){a_{1}}\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} ,\bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr){a_{1}}\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} + ( {1 + {\gamma _{2}}} ){a_{2}}\sum_{i = 0}^{n - 1} {{{ \Vert {{d_{i}}} \Vert }_{\infty}}} ,\\ &\quad { ( {1 + {\gamma _{1}}} ){a_{1}}\sum_{i = 0}^{n - 1} {{{ \Vert {{a_{i}}} \Vert }_{\infty}}} + \bigl( {1 + ( {n - 1} ){\gamma _{2}}} \bigr){a_{2}}\sum_{i = 0}^{n - 1} {{{ \Vert {{d_{i}}} \Vert }_{\infty}}} , ( {2 + n{\gamma _{2}}} ){a_{2}}\sum_{i = 0}^{n - 1} {{{ \Vert {{d_{i}}} \Vert }_{\infty}}} } \Biggr\} < 1, \end{aligned}

where $${a_{1}} = \frac{1}{{\Gamma ( {\alpha - n + 2} )}}$$, $${a_{2}} = \frac{1}{{\Gamma ( {\beta - n + 2} )}}$$.

Then BVP (1.1) has at least one solution.

To prove the above theorem, we have the following lemma, whose proof is similar to that of Lemma 3.1, Lemma 3.2 and is omitted.

### Lemma 3.3

Let L be defined by (3.1), then

\begin{aligned} &\begin{aligned} \operatorname{Ker}L&= ( {\operatorname{Ker} {L_{1}}, \operatorname{Ker} {L_{2}}} ) \\ & = \bigl\{ ( {u,v} ) \in \overline{X}| ( {u,v} )= \bigl( {{c_{1}} \bigl( {{t^{n - 1}} + ( {n - 1} ){\gamma _{1}} {t^{n - 2}}} \bigr),{c_{2}} \bigl( {{t^{n - 1}} + ( {n - 1} ){\gamma _{2}} {t^{n - 2}}} \bigr)} \bigr),\\ &\quad {c_{1}},{c_{2}} \in \mathbb{R} \bigr\} , \end{aligned} \\ &\operatorname{Im}L = ( {\operatorname{Im} {L_{1}},\operatorname{Im} {L_{2}}} ) = \bigl\{ ( {x,y} ) \in \bar{Y} \vert {{T_{3}}x = 0,{T_{4}}y = 0} \bigr\} , \end{aligned}

where

\begin{aligned} &\begin{aligned} {T_{3}}x ={}& \int_{0}^{1} {{ ( {1 - s} )}^{\alpha - n}}x ( s )\,ds - \frac{{{\delta _{1}}}}{{\alpha - n + 1}} \int_{0}^{{\eta _{1}}} {{{ ( {{\eta _{1}} - s} )}^{\alpha - n + 1}}x ( s )\,ds } \\ &{}- {\gamma _{1}} {\delta _{1}} \int_{0}^{{\xi _{1}}} {{{ ( {{\xi _{1}} - s} )}^{\alpha - n}}x ( s )\,ds } , \end{aligned} \\ &\begin{aligned} {T_{4}}y = {}&\int_{0}^{1} {{{ ( {1 - s} )}^{\beta - n}}y ( s )\,ds } - \frac{{{\delta _{2}}}}{{\beta - n + 1}}\int_{0}^{{\eta _{2}}} {{{ ( {{\eta _{2}} - s} )}^{\beta - n + 1}}y ( s )\,ds } \\ &{}- {\gamma _{2}}{\delta _{2}}\int_{0}^{{\xi _{2}}} {{{ ( {{\xi _{2}} - s} )}^{\beta - n}}y ( s )\,ds } . \end{aligned} \end{aligned}

For $$\forall t \in [ {0,1} ]$$, the linear continuous projector operators $$P:\overline{X} \to \overline{X}$$ and $$Q:\overline{Y} \to \overline{Y}$$ can be defined as

\begin{aligned} &P ( {u,v} ) = ( {{P_{1}}u,{P_{2}}v} ) = \biggl( {\frac{{{u^{ ( {n - 1} )}} ( 0 )}}{{ ( {n - 1} )!}} \bigl( {{t^{n - 1}} + ( {n - 1} ){\gamma _{1}} {t^{n - 2}}} \bigr), \frac{{{v^{ ( {n - 1} )}} ( 0 )}}{{ ( {n - 1} )!}} \bigl( {{t^{n - 1}} + ( {n - 1} ){\gamma _{2}} {t^{n - 2}}} \bigr)} \biggr), \\ &Q ( {x,y} ) = ( {{Q_{1}}x,{Q_{2}}y} ) = ( {{\Lambda _{1}} {T_{3}}x,{\Lambda _{2}} {T_{4}}y} ), \end{aligned}

where

$${\Lambda _{1}} = \frac{{\alpha - n + 1}}{{1 - \frac{{{\delta _{1}}}}{{\alpha - n + 2}}\eta _{1}^{\alpha - n + 2} - {\gamma _{1}}{\delta _{1}}\xi _{1}^{\alpha - n + 1}}},\qquad {\Lambda _{2}} = \frac{{\beta - n + 1}}{{1 - \frac{{{\delta _{2}}}}{{\beta - n + 2}}\eta _{2}^{\beta - n + 2} - {\gamma _{2}}{\delta _{2}}\xi _{2}^{\beta - n + 1}}}.$$

Define the operator $${K_{P}}:\operatorname{Im} L \to \operatorname{dom}L \cap \operatorname{Ker}P$$ as

\begin{aligned} {K_{P}} ( {x,y} ) ={}& \biggl( {\frac{1}{{\Gamma ( \alpha )}}} \int_{0}^{t} {{{ ( {t - s} )}^{\alpha - 1}}x ( s )\,ds } + \frac{{{\gamma _{1}}{t^{n - 2}}}}{{ ( {n - 2} )!\Gamma ( {\alpha - n + 1} )}} \int_{0}^{{\xi _{1}}} {{{ ( {{\xi _{1}} - s} )}^{\alpha - n}}x ( s )\,ds } , \\ &\frac{1}{{\Gamma ( \beta )}} \int_{0}^{t} {{{ ( {t - s} )}^{\beta - 1}}y ( s )\,ds } + \frac{{{\gamma _{2}}{t^{n - 2}}}}{{ ( {n - 2} )!\Gamma ( {\beta - n + 1} )}} \int_{0}^{{\xi _{2}}} {{{ ( {{\xi _{2}} - s} )}^{\beta - n}}y ( s )\,ds } \biggr). \end{aligned}

Next, we give the proof of Theorem 3.2 (similar to Theorem 3.1).

### Proof

Firstly, it will be proved that the set

$${\Omega _{1}} = \bigl\{ { ( {u,v} ) \in \operatorname{dom} L\backslash \operatorname{Ker} L \vert {L ( {u,v} ) = \lambda N ( {u,v} )} , \lambda \in ( {0,1} )} \bigr\}$$

is bounded. If $$( {u,v} ) \in {\Omega _{1}}$$, similar to Step 1 in the proof of Theorem 3.1, we get

$$\bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert \le {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}\bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}} + \Vert {b_{1}} \Vert _{\infty}\sum _{i = 0}^{n - 1} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + } \Vert {r_{1}} \Vert _{\infty}} \Biggr) + M,$$
(3.7)

where $${a_{1}} = \frac{1}{{\Gamma ( {\alpha - n + 2} )}}$$, and

$$\bigl\vert {{v^{ ( {n - 1} )}} ( 0 )} \bigr\vert \le {a_{2}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {d_{i}} \Vert _{\infty}} \bigl\Vert {u^{ ( i )}} \bigr\Vert _{\infty}+ \Vert {b_{2}} \Vert _{\infty}\sum_{i = 0}^{n - 1} { \bigl\Vert {u^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{2}}} + } \Vert {r_{2}} \Vert _{\infty}} \Biggr) + M,$$
(3.8)

where $${a_{2}} = \frac{1}{{\Gamma ( {\beta - n + 2} )}}$$.

So

$${ \bigl\Vert {P ( {u,v} )} \bigr\Vert _{\overline{X}}} \le \max \bigl\{ { \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr) \bigl\vert {{u^{ ( {n - 1} )}} ( 0 )} \bigr\vert , \bigl( {1 + ( {n - 1} ){\gamma _{2}}} \bigr) \bigl\vert {{v^{ ( {n - 1} )}} ( 0 )} \bigr\vert } \bigr\} .$$
(3.9)

On the other hand, for $$( {x,y} ) \in \operatorname{Im} L$$, by the definition of $${ \Vert \cdot \Vert _{\overline{X}}}$$ and $$K_{P}$$, it is easy to see that

$${ \bigl\Vert {{K_{P}} ( {x,y} )} \bigr\Vert _{\overline{X}}} \le \max \bigl\{ { ( {1 + {\gamma _{1}}} ){a_{1}} {{ \Vert x \Vert }_{\infty}}, ( {1 + {\gamma _{2}}} ){a_{2}} {{ \Vert y \Vert }_{\infty}}} \bigr\} .$$
(3.10)

Hence,

\begin{aligned}[b] {{ \bigl\Vert { ( {I - P} ) ( {u,v} )} \bigr\Vert }_{\overline{X}}}& = {{ \bigl\Vert {{K_{P}}L ( {I - P} ) ( {u,v} )} \bigr\Vert }_{\overline{X}}} = {{ \bigl\Vert {{K_{P}}L ( {u,v} )} \bigr\Vert }_{\overline{X}}} = {{ \bigl\Vert {{K_{P}} ( {{L_{1}}u,{L_{2}}v} )} \bigr\Vert }_{\overline{X}}} \\ & \le \max \bigl\{ { ( {1 + {\gamma _{1}}} ){a_{1}} {{ \Vert {{N_{1}}v} \Vert }_{\infty}}, ( {1 + {\gamma _{2}}} ){a_{2}} {{ \Vert {{N_{2}}u} \Vert }_{\infty}}} \bigr\} . \end{aligned}
(3.11)

Thus,

\begin{aligned} {{ \bigl\Vert { ( {u,v} )} \bigr\Vert }_{\overline{X}}} ={}& {{ \bigl\Vert {P ( {u,v} ) + ( {I - P} ) ( {u,v} )} \bigr\Vert }_{\overline{X}}} \\ \le{}& {{ \bigl\Vert {P ( {u,v} )} \bigr\Vert }_{\overline{X}}} + {{ \bigl\Vert { ( {I - P} ) ( {u,v} )} \bigr\Vert }_{\overline{X}}} \\ \le{}& \max \bigl\{ { \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr) \bigl\vert {u^{ ( {n - 1} )}} ( 0 ) \bigr\vert + ( {1 + {\gamma _{1}}} ){a_{1}} {{ \Vert {{N_{1}}v} \Vert }_{\infty}},} \\ & \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr) \bigl\vert {u^{ ( {n - 1} )}} ( 0 ) \bigr\vert + ( {1 + {\gamma _{2}}} ){a_{2}} { \Vert {{N_{2}}u} \Vert _{\infty}}, \\ & \bigl( {1 + ( {n - 1} ){\gamma _{2}}} \bigr) \bigl\vert {v^{ ( {n - 1} )}} ( 0 ) \bigr\vert + ( {1 + {\gamma _{1}}} ){a_{1}} { \Vert {{N_{1}}v} \Vert _{\infty}}, \\ &{ \bigl( {1 + ( {n - 1} ){\gamma _{2}}} \bigr) \bigl\vert {v^{ ( {n - 1} )}} ( 0 ) \bigr\vert + ( {1 + {\gamma _{2}}} ){a_{2}} {{ \Vert {{N_{2}}u} \Vert }_{\infty}}} \bigr\} . \end{aligned}

Next we will prove this conclusion in four cases.

Case 1′ $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le ( {1 + ( {n - 1} ){\gamma _{1}}} ) \vert {{u^{ ( {n - 1} )}} ( 0 )} \vert + ( {1 + {\gamma _{1}}} ){a_{1}}{ \Vert {{N_{1}}v} \Vert _{\infty}}$$. By (3.7) and $${ ( {{{\mathrm{H}}_{1}}} )^{\prime}}$$, we get

\begin{aligned} { \bigl\Vert { ( {u,v} )} \bigr\Vert _{\overline{X}}} \le{}& \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr){a_{1}} \Biggl( { \sum_{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}+ \Vert {b_{1}} \Vert _{\infty}\sum _{i = 0}^{n - 1} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert r \Vert _{\infty}} \Biggr) \\ &{} + \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr)M + ( {1 + { \gamma _{1}}} ){a_{1}} \bigl\Vert f \bigl( {t,v ( t ),v' ( t ), \ldots ,{v^{ ( {n - 1} )}} ( t )} \bigr) \bigr\Vert _{\infty}\\ \le{}& ( {2 + n{\gamma _{1}}} ){a_{1}} \Biggl( {\sum _{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}+ \Vert {b_{1}} \Vert _{\infty}\sum _{i = 0}^{n - 1} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + } \Vert {r_{1}} \Vert _{\infty}} \Biggr)\\ &{} + \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr)M \\ \le{}& ( {2 + n{\gamma _{1}}} ){a_{1}} \Biggl( {\sum _{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}} \bigl\Vert {v^{ ( {n - 1} )}} \bigr\Vert _{\infty}+ n \Vert {b_{1}} \Vert _{\infty}\bigl\Vert {v^{ ( {n - 1} )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr)\\ &{} + \bigl( {1 + ( {n - 1} ){ \gamma _{1}}} \bigr)M \\ ={}& ( {2 + n{\gamma _{1}}} ){a_{1}} \Biggl( {\sum _{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}} \Vert v \Vert _{X} + n \Vert {b_{1}} \Vert _{\infty} \Vert v \Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr) + \bigl( {1 + ( {n - 1} ){\gamma _{1}}} \bigr)M. \end{aligned}

According to $${ ( {{{\mathrm{H}}_{4}}} )^{\prime}}$$ and the definition of $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}}$$, we see that $${ \Vert v \Vert _{X}}$$ is bounded, therefore $${\Omega _{1}}$$ is bounded.

Case 2′ $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{v^{ ( {n - 1} )}} ( 0 )} \vert + {a_{2}}{ \Vert {{N_{2}}u} \Vert _{\infty}}$$. The proof is similar to Case 1′. Here, we omit it.

Case 3′ $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{u^{ ( {n - 1} )}} ( 0 )} \vert + {a_{2}}{ \Vert {{N_{2}}u} \Vert _{\infty}}$$. By (3.7) and $${ ( {{{\mathrm{H}}_{1}}} )^{\prime}}$$, we get

\begin{aligned} \bigl\Vert ( {u,v} ) \bigr\Vert _{\overline{X}}\le{}& \bigl\vert {u^{ ( {n - 1} )}} ( 0 ) \bigr\vert + {a_{2}} \Vert {N_{2}}u \Vert _{\infty}\\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}\bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}} + \Vert {b_{1}} \Vert _{\infty}\sum_{i = 0}^{n - 1} { \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} } \Biggr) + M \\ &{} + {a_{2}} \bigl\Vert g \bigl( {t,u ( t ),u' ( t ), \ldots ,{u^{ ( {n - 1} )}} ( t )} \bigr) \bigr\Vert _{\infty}\\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} \Vert {a_{i}} \Vert _{\infty}\bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}+ \Vert {b_{1}} \Vert _{\infty}\sum_{i = 0}^{n - 1} \bigl\Vert {v^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr) + M \\ &{} + {a_{2}} \Biggl( \sum_{i = 0}^{n - 1} \Vert {d_{i}} \Vert _{\infty}\bigl\Vert {u^{ ( i )}} \bigr\Vert _{\infty}+ \Vert {b_{2}} \Vert _{\infty}\sum_{i = 0}^{n - 1} \bigl\Vert {u^{ ( i )}} \bigr\Vert _{\infty}^{{\theta _{2}}} + \Vert {r_{2}} \Vert _{\infty}\Biggr) \\ \le{}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}\bigl\Vert {v^{ ( {n - 1} )}} \bigr\Vert _{\infty}} + n \Vert {b_{1}} \Vert _{\infty}\bigl\Vert {v^{ ( {n - 1} )}} \bigr\Vert _{\infty}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}} \Biggr) + M \\ &{} + {a_{2}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {d_{i}} \Vert _{\infty}} \bigl\Vert {u^{ ( {n - 1} )}} \bigr\Vert _{\infty}+ n \Vert {b_{2}} \Vert _{\infty}\bigl\Vert {u^{ ( {n - 1} )}} \bigr\Vert _{\infty}^{{\theta _{2}}} + \Vert {r_{2}} \Vert _{\infty}} \Biggr) \\ ={}& {a_{1}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {a_{i}} \Vert _{\infty}} \Vert v \Vert _{X}} + n \Vert {b_{1}} \Vert _{\infty} \Vert v \Vert _{X}^{{\theta _{1}}} + \Vert {r_{1}} \Vert _{\infty}\Biggr) \\ &{} + {a_{2}} \Biggl( {\sum_{i = 0}^{n - 1} { \Vert {d_{i}} \Vert _{\infty} \Vert u \Vert _{X}} + n \vert {b_{2}} \Vert _{\infty} \Vert u \Vert _{X}^{{\theta _{2}}} + \Vert {r_{2}} \Vert _{\infty}} \Biggr) + M. \end{aligned}

By $${ ( {{{\mathrm{H}}_{4}}} )^{\prime}}$$, we get $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}}$$ is bounded, therefore $${\Omega _{1}}$$ is bounded.

Case 4′ $${ \Vert { ( {u,v} )} \Vert _{\overline{X}}} \le \vert {{v^{ ( {n - 1} )}} ( 0 )} \vert + {a_{1}}{ \Vert {{N_{1}}v} \Vert _{\infty}}$$. The proof is similar to Case 3′. Here, we omit it.

In summary, we proved that $${\Omega _{1}}$$ is bounded. The remainder of the proof is just similar to the proof of Theorem 3.1 and is omitted. □

## Example

### Example 4.1

Consider the following BVP:

$$\textstyle\begin{cases} D_{0 + }^{3.5}u ( t ) = f ( {t,v,v',v'',v'''} ),\quad 0 < t < 1, \\ D_{0 + }^{3.6}v ( t ) = g ( {t,u,u',u'',u'''} ),\quad 0 < t < 1, \\ u ( 0 ) = u' ( 0 ) = u'' ( 0 ) = 0,\qquad u''' ( 1 ) = 4u'' ( {\frac{1}{4}} ), \\ v ( 0 ) = v' ( 0 ) = v'' ( 0 ) = 0,\qquad v''' ( 1 ) = 5v'' ( {\frac{1}{5}} ), \end{cases}$$
(4.1)

where $$\alpha = 3.5$$, $$\beta = 3.6$$, $$f ( {t,{x_{0}},{x_{1}},{x_{2}},{x_{3}}} ) = \frac{{{x_{0}}\cos t + {x_{1}}\sin t + {x_{2}}}}{8} + \frac{{{x_{3}}}}{{32}} + \sin ( {{x_{0}}{x_{2}} + t{x_{1}}} )$$, $$g ( t,{y_{0}},{y_{1}}, {y_{2}},{y_{3}} ) = \frac{t}{7} + \frac{{{y_{0}}\sin 2t}}{{16}} + \frac{{{y_{1}}\cos 3t}}{9} + \frac{{{y_{2}} + {y_{3}}}}{8}$$, it is easily figured out that $${\gamma _{1}} = {\gamma _{2}} = 0$$, $${\delta _{1}} = 4$$, $${\delta _{2}} = 5$$, $${\eta _{1}} = \frac{1}{4}$$, $${\eta _{2}} = \frac{1}{5}$$, satisfy the condition of Case (i), $${ \Vert {{a_{0}}} \Vert _{\infty}} = { \Vert {{a_{1}}} \Vert _{\infty}} = { \Vert {{a_{2}}} \Vert _{\infty}} = \frac{1}{8}$$, $${ \Vert {{a_{3}}} \Vert _{\infty}} = \frac{1}{{32}}$$, $${ \Vert {{d_{0}}} \Vert _{\infty}} = \frac{1}{{16}}$$, $${ \Vert {{d_{1}}} \Vert _{\infty}} = \frac{1}{9}$$, $${ \Vert {{d_{2}}} \Vert _{\infty}} = { \Vert {{d_{3}}} \Vert _{\infty}} = \frac{1}{8}$$, $${ \Vert {{b_{1}}} \Vert _{\infty}} = { \Vert {{b_{2}}} \Vert _{\infty}} = 0$$, $${ \Vert {{r_{1}}} \Vert _{\infty}} = 1$$, $${ \Vert {{r_{2}}} \Vert _{\infty}} = \frac{1}{7}$$, $${\theta _{1}} = {\theta _{2}} = 0$$, $$M=64$$, $${M^{*}}=32$$, $$0 < t < 1$$, it is easy to verify that the conditions satisfy all assumptions of Theorem 3.1. Hence, BVP (4.1) has at least one set of solutions.

### Example 4.2

Consider the BVP:

$$\textstyle\begin{cases} D_{0 + }^{3.3}u ( t ) = f ( {t,v,v',v'',v'''} ),\quad 0 < t < 1, \\ D_{0 + }^{3.5}v ( t ) = g ( {t,u,u',u'',u'''} ),\quad 0 < t < 1, \\ u ( 0 ) = u' ( 0 ) = 0,\qquad u'' ( 0 ) = 3u''' ( {\frac{1}{3}} ),\qquad u''' ( 1 ) = \frac{2}{7}u'' ( {\frac{1}{2}} ), \\ v ( 0 ) = v' ( 0 ) = 0,\qquad v'' ( 0 ) = 2v''' ( {\frac{1}{2}} ),\qquad v''' ( 1 ) = \frac{3}{7}v'' ( {\frac{1}{3}} ), \end{cases}$$
(4.2)

where $$\alpha = 3.3$$, $$\beta = 3.5$$, $$f ( {t,{x_{0}},{x_{1}},{x_{2}},{x_{3}}} ) = \frac{{{x_{0}}\sin t + {x_{1}}\cos t + {x_{2}}}}{{56}} + \frac{{{x_{3}}}}{{64}} + \cos ( {{x_{1}} + t{x_{2}}} )$$, $$g ( t,{y_{0}},{y_{1}}, {y_{2}},{y_{3}} ) = \frac{t}{6} + \frac{{{y_{0}}\sin ( {3t + 1} )}}{{30}} + \frac{{{y_{1}}\cos ( {2t + 4} )}}{{45}} + \frac{{{y_{2}} + {y_{3}}}}{{50}}$$, it is easily figured out that $${\gamma _{1}} = 3$$, $${\gamma _{2}} = 2$$, $${\delta _{1}} = \frac{2}{7}$$, $${\delta _{2}} = \frac{3}{7}$$, $${\eta _{1}} = \frac{1}{2}$$, $${\eta _{2}} = \frac{1}{3}$$ satisfy the condition of Case (ii), $${ \Vert {{a_{0}}} \Vert _{\infty}} = { \Vert {{a_{1}}} \Vert _{\infty}} = { \Vert {{a_{2}}} \Vert _{\infty}} = \frac{1}{{56}}$$, $${ \Vert {{a_{3}}} \Vert _{\infty}} = \frac{1}{{64}}$$, $${ \Vert {{d_{0}}} \Vert _{\infty}} = \frac{1}{{30}}$$, $${ \Vert {{d_{1}}} \Vert _{\infty}} = \frac{1}{{45}}$$, $${ \Vert {{d_{2}}} \Vert _{\infty}} = { \Vert {{d_{3}}} \Vert _{\infty}} = \frac{1}{{50}}$$, $${ \Vert {{b_{1}}} \Vert _{\infty}} = { \Vert {{b_{2}}} \Vert _{\infty}} = 0$$, $${ \Vert {{r_{1}}} \Vert _{\infty}} = 1$$, $${ \Vert {{r_{2}}} \Vert _{\infty}} = \frac{1}{6}$$, $${\theta _{1}} = {\theta _{2}} = 0$$, $$M=120$$, $${M^{*}}=90$$, $$0 < t < 1$$, it is easy to verify that the conditions satisfy all assumptions of Theorem 3.2. Hence, BVP (4.2) has at least one set of solutions.

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## Acknowledgements

This work is supported by the National Natural Science Foundation of China (11271364).

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Correspondence to Wenbin Liu.

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