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# A discrete-time ruin model with dependence between interclaim arrivals and claim sizes

*Advances in Difference Equations*
**volume 2016**, Article number: 188 (2016)

## Abstract

We construct a discrete-time ruin model with general premium rate and dependent setting, where the time between two occurrences depends on the previous claim size. The generating function and defective renewal equation satisfied by the Gerber-Shiu expected discounted penalty function are derived by using the roots of a generalized Lundberg’s equation. Explicit expressions for the Gerber-Shiu function are obtained with discrete \(K_{m}\)-family claim sizes and geometric thresholds. Numerical illustration is then examined.

## Introduction

In ruin theory, the compound binomial model and the risk model based on a discrete-time renewal process have been extensively analyzed by [1, 2], among many others. Note that, for these mentioned risk models, it is explicitly assumed that claim sizes and claim intervals are independent, which can be restrictive in practical context. Cossette et al. [3] propose a compound Markov binomial model based on the Markov Bernoulli process that introduces dependence between claim occurrences. Woo [4] analyzes a generalized Gerber-Shiu function in a discrete-time renewal risk model with an arbitrary dependence structure. Liu and Bao [5] consider a particular dependence structure among the interclaim time and the subsequent claim size and derive defective renewal equation satisfied by the Gerber-Shiu expected discounted penalty function. We mention that the dependence among claim sizes and interclaim arrivals through bivariate geometric distributions and copula functions have been investigated by Marceau [6], where explicit expressions for the Gerber-Shiu expected penalty function are derived.

As mentioned by Landriault [7], unlike the classical compound Poisson model, in which a unite premium can be assumed without loss of generality, it is clear that such reasoning does not hold for compound binomial model. In that paper, the author studies the evaluation of the generalized expected penalty function in the compound binomial risk model in which the premium rate received per period is *c* (\(c\in\mathbb{N}^{+}\)). See also Liu and Bao [5] for a discrete-time risk model with general premium rate and time-dependent claim sizes.

Inspired by the works [8] and [9] in a continuous-time risk process with dependence, we consider a fully discrete risk model, in which the distribution of the time until the next claim depends on the amount of the previous claim. Moreover, we further assume that the premium rate received per period is an arbitrary positive integer *c*. The surplus process of an insurance company is described as

where \(U(0)=u\in\mathbb{N}\) is the initial surplus, \(c\in\mathbb{N}^{+}\) is the level premium rate, and \(\{N(n),n\in\mathbb{N}\}\) is the claim-counting process. The claim amounts \(\{X_{i},i=1, 2, \dots\}\) are a sequence of independent and identically distributed (i.i.d.) positive random variables with cumulative distribution function (c.d.f.) \(B(\cdot )\), probability function (p.f.) \(b(\cdot)\), and mean *μ*. Assume that the random thresholds \(\{Q_{i}, i=1, 2, \dots\}\) are i.i.d. with c.d.f. \(H(\cdot)=1-\overline{H}(\cdot)\) and are independent of the claim sizes \(\{X_{i}\}\). The distribution of the waiting time until the next claim depends on the size of the previous claim by comparing it to \(\{Q_{i}\}\) as follows: If the size of the \(X_{j}\) is greater than or equal to \(Q_{j}\), then the time until the next claim follows geometric distribution with p.f. \((1-p_{1})p_{1}^{n-1}\), \(n\in\mathbb{N}^{+}\); if \(X_{j}\) is less than \(Q_{j}\), then the time until the next claim follows another geometric distribution with p.f. \((1-p_{2})p_{2}^{n-1}\), \(n\in\mathbb{N}^{+}\), where we assume that \(p_{1}\neq p_{2}\) and \(0< p_{i}<1\), \(i=1,2\). Further, to guarantee that \(U(n)\) has a positive drift, we assume that

which is the positive safety loading condition. Let \(m_{i}(u)\) denote the Gerber-Shiu expected discounted penalty function with initial capital *u* given that the first claim occurs according to the geometric distribution with parameter \(p_{i}\), where we classify the insured as Class *i* for convenience. More precisely, we define

where \(0< v\leq1\) is the discount factor, \(\omega:\mathbb{N}\times\mathbb {N}^{+}\rightarrow\mathbb{N}\) is a penalty function, \(I(A)\) is the indicator function of an event *A*, and \(T_{i}\), \(i=1,2\), is the time to ruin for Class *i*.

The rest of the paper is structured as follows: In Section 2, we analyze the roots of the generalized Lundberg’s equation. The defective renewal equations for the Gerber-Shiu expected discounted penalty function are derived in Section 3. In Section 4, we obtain the explicit expressions for the Gerber-Shiu function when the claim sizes have discrete \(K_{m}\) distributions and the random thresholds follow geometric distributions. A numerical example is also provided.

## Generalized Lundberg’s equation

In this section, we aim to analyze the roots of generalized Lundberg’s equation, which will play an important role in deriving the renewal equation for the Gerber-Shiu function \(m_{i}(u)\) defined by (1.3). Throughout the rest of the entire paper, we use the hat ‘^{∧}’ to designate the generating function of the corresponding quantity. For simplicity, we introduce the following notation:

By (2.1) and (2.2) we can rewrite (1.2) as

Denote

Then conditioning on the time and the amount of the first claim for Class 1 leads to

Replacing *u* with \(u-c\) in (2.5) and then rearranging the resulting equation yield

Combining (2.5) and (2.6), we get

Multiplying both sides of (2.7) by \(z^{u}\) and summing over *u* from *c* to ∞ produce

where ∗ is the convolution factor, and \(T_{z}\) is the discrete version of the Dickson-Hipp operator defined by

See Li [2] for further details about the elegant properties of the discrete operator. After simple rearrangement, (2.8) can be rewritten as

where \(f_{1,u}(z)=p_{1}z^{u}+(1-p_{1})\sum_{y=u+1}^{c-1}z^{y}\xi(y-u)\) and \(f_{2,u}(z)=(1-p_{1})\sum_{y=u+1}^{c-1}z^{y}\chi(y-u)\) are polynomials of degree \(c-1\) in *z*.

For Class 2, along very similar lines as discussed before, we obtain

where \(g_{1,u}(z)=(1-p_{2})\sum_{y=u+1}^{c-1}z^{y}\xi(y-u)\) and \(g_{2,u}(z)=p_{2}z^{u}+(1-p_{2})\sum_{y=u+1}^{c-1}z^{y}\chi(y-u)\) are also polynomials of degree \(c-1\) in *z*. Now we rewrite (2.9) and (2.10) in matrix form as

where the matrices are defined respectively as \(\mathbf{ A}(z)=\operatorname{diag}(z^{c}-vp_{1},z^{c}-vp_{2})\), \(\mathbf{ B}(z)=v\mathbf{ P}(\hat{\xi}(z), \hat {\chi}(z))\), \(\mathbf{ P}=(1-p_{1},1-p_{2})^{T}\), \(\mathbf{ m}(u)=(m_{1}(u),m_{2}(u))^{T}\), \(\hat{\mathbf{ m}}(z)=(\hat{m}_{1}(z),\hat{m}_{2}(z))^{T}\), and

To ultimately invert \(\hat{\mathbf{ m}}(z)\), we need an expression for \(\mathbf{ m}(u)\) for \(u=0, 1, \ldots, c-1\), which depends on the roots of generalized Lundberg’s equation \(\det(\mathbf{ A}(z)-\mathbf{ B}(z))=0\). It is not hard to calculate that Lundberg’s equation is equivalent to

where

In the following lemma, we first apply Rouché’s theorem on a given contour to identify the number of roots of equation (2.12) for \(v\in(0,1)\).

### Lemma 1

*For*
\(v\in(0,1)\), *there are* 2*c*
*solutions of generalized Lundberg’s equation* (2.12), *say*
\(z_{i}=z_{i}(v)\)
*for*
\(i=1,2,\ldots,2c\), *inside the unit circle*
\(\mathcal{C}=\{z:\vert z\vert =1\}\).

### Proof

For \(v\in(0,1)\), it is easy to see that

Note that \(\hat{\chi}(1)+\hat{\xi}(1)=1\) and

Combining (2.15) and (2.16) yields

Therefore, Rouché’s theorem implies that \(\hat{h}_{1,v}(z)=0\) and \(\hat{h}_{1,v}(z)-\hat{h}_{2,v}(z)=0\) have the same number of zeros inside the unit circle \(\mathcal{C}\). Given that \(\hat{h}_{1,v}(z)=0\) has 2*c* zeros inside \(\mathcal{C}\), so does \(\hat{h}_{1,v}(z)-\hat {h}_{2,v}(z)=0\). □

In the case of \(v=1\), the conditions of Rouché’s theorem are no longer satisfied. However, we can determine the roots of (2.12) by applying Theorem 1 of Klimenok [10] as follows.

### Lemma 2

*For*
\(v=1\), *there are*
\(2c-1\)
*roots*, *say*
\(z_{1},\dots, z_{2c-1}\), *to equation* (2.12) *inside*
\(\mathcal{C}\), *in addition to the trivial root*
\(z_{2c}=1\).

### Proof

By direct calculations we obtain that

where the last inequality is due to the positive security loading condition (2.3). On the other hand, we can easily check that \(\vert \hat{h}_{2,1}(z)\vert _{\vert z\vert =1,z\neq1}<\vert \hat{h}_{1,1}(z)\vert _{\vert z\vert =1,z\neq1}\). By Klimenok [10] we conclude that the number of solutions to (2.12) inside \(\mathcal {C}\) is equal to \(2c-1\), that is, the number of roots of \(\hat{h}_{1,1}(z)=0\) inside \(\mathcal{C}\) minus 1. Moreover, a trivial root to generalized Lundberg’s equation (2.12) is \(z_{2c}=1\). □

In what follows, we only consider the case where the roots of Lundberg’s equation (2.12) are distinct. For \(i=1,\dots ,2c\), let the nonzero row vector \((\mathbf{ h}_{i})^{T}=(h_{i,1}, h_{i,2})\) be the left eigenvector of \(\mathbf{ A}(z_{i})-\mathbf{ B}(z_{i})\) associated with the eigenvalue 0. Applying equation (2.11) yields

To identify the expression of \(\mathbf{ m}(u)\) for \(u=0, 1, \ldots, c-1\), we introduce the partitioned matrices \(\mathbf{ H}=\operatorname{diag}((\mathbf{ h}_{1})^{T}, (\mathbf{ h}_{2})^{T}, \ldots, (\mathbf{ h}_{2c})^{T})\) and \(\mathbf{ F}=((\mathbf{ F}(z_{1}))^{T}, (\mathbf{ F}(z_{2}))^{T}, \ldots, (\mathbf{ F}(z_{2c}))^{T})^{T}\) with \(\mathbf{ F}(z_{i})=(\mathbf{ F}_{0}(z_{i}), \mathbf{ F}_{1}(z_{i}), \ldots, \mathbf{ F}_{c-1}(z_{i}))\), \(i=1, 2, \ldots, 2c\). Thus, equation (2.18) can be reexpressed as

where the matrix \(\mathbf{ Q}=\mathbf{HF}\).

### Theorem 3

*For*
\(i=1,2\), *the Gerber*-*Shiu expected discounted penalty function*
\(m_{i}(u)\)
*with the initial surplus*
\(u\in\{0,1,\dots,c-1\}\)
*can be determined as*

*where*
\(\alpha_{l,i}(\mathbf{ Q})\)
*is the cofactor associated with the element in row*
*l*
*and column*
*i*
*of matrix*
**Q**.

## Defective renewal equations

The main goal of this section is to obtain the defective renewal equation for \(m_{i}(u)\), \(i=1,2\). To do so, we solve the linear system of equations (2.9) and (2.10):

where

is a polynomial of degree \(2c-1\) in *z*, and \(\delta _{1}(u)=p_{1}(1-p_{2})m_{1}(u)-p_{2}(1-p_{1})m_{2}(u)\) for \(u=0, 1, \ldots, c-1\).

Since \(\hat{m}_{1}(z)\) is analytic, the solutions of generalized Lundberg’s equation are also zeros of the numerator in (3.1), we have

Thus, applying the Lagrange interpolating theorem for \(l(z)\) leads to

where \(\pi(z)=\prod_{i=1}^{2c}(z-z_{i})\) and \(\pi^{\prime}(z_{j})=\prod_{i=1,i\neq j}^{2c}(z_{i}-z_{j})\). From (3.2) we conclude that

where the last equality is due to the following formula in interpolation theory:

Observing that \(\hat{h}_{1,v}(z)\) is a polynomial of degree 2*c* in *z*, we deduce that \(\hat{h}_{1,v}(z)-\pi(z)\) is a polynomial of degree \(2c-1\) in *z*. We use the Lagrange interpolating polynomial to obtain

Since \(z_{j}\), \(j=1, 2, \ldots, 2c\), are roots of generalized Lundberg’s equation, we know that \(\hat{h}_{1,v}(z_{j})=\hat{h}_{2,v}(z_{j})\). Then equation (3.4) is equivalent to

Therefore, we can employ a similar procedure to find an alternative expression for the denominator of the right side of (3.1) as

Substituting (3.3) and (3.5) into (3.1), we deduce

where

For the Gerber-Shiu function \(m_{2}(u)\), following a similar procedure, we have

where

with \(\delta_{2}(u)=p_{2}(1-p_{1})m_{2}(u)-p_{1}(1-p_{2})m_{1}(u)\) for \(u=0, 1, \ldots , c-1\).

Equations (3.6) and (3.9) eventually lead to the defective renewal equation for the Gerber-Shiu discounted penalty function \(m_{i}(u)\), as presented in the following theorem.

### Theorem 4

*The Gerber*-*Shiu expected discounted penalty function*
\(m_{i}(u)\)
*defined in* (2.3) *satisfies the following defective renewal equation*:

*where*
\(\tau(\cdot)\)
*is defined by* (3.8), *and*
\(\eta_{1}(\cdot)\)
*and*
\(\eta_{2}(\cdot)\)
*are determined by* (3.7) *and* (3.10), *respectively*.

### Proof

The renewal equation (3.11) follows by inverting (3.6) and (3.9) directly. For (3.11) to be a defective renewal equation, it remains to show that \(k_{v}\doteq v\hat {\tau}(1)<1\). Let us first assume that \(v\in(0,1)\). Using (3.5), we have \(k_{v}=1-\frac{\hat{h}_{1,v}(1)-\hat{h}_{2,v}(1)}{\pi (1)}\). We easily calculate that

and then deduce that \(k_{v}<1\).

Now we turn to the case of \(v=1\). Since \(z_{2c}\) is a root of generalized Lundberg’s equation (2.12), we have

Differentiating (3.12) with respect to \(z_{2c}\) and taking the limit \(v\rightarrow1\), we eventually find

where the inequality is derived via (2.3). Thus,

□

## Applications with geometric thresholds

The thresholds can be viewed as a criterion for classifying claims as large or small. In this section, we suppose that the random thresholds \(\{Q_{i},i=1,2,\dots\}\) follow a geometric distribution with p.f. \((1-p_{3})p_{3}^{n-1}\), \(n\in\mathbb{N}^{+}\), \(0< p_{3}<1\). We derive an explicit expression for the Gerber-Shiu function when the claim sizes belong to the discrete \(K_{m}\)-family and present some special cases.

### The Gerber-Shiu function with \(K_{m}\)-family claim sizes

We assume that the claim sizes \(\{X_{i},i=1,2,\dots\}\) follow a distribution from discrete \(K_{m}\)-family, that is, the generating function of the density function \(b(\cdot)\) satisfies the following form:

where \(0< q_{i}<1\), \(i=1,2,\dots,m\), and the coefficients \(\beta_{1},\beta _{2},\dots,\beta_{m-1}\) are such that \(b(\cdot)\) is a p.f. This class of distributions includes, as particular cases, the shifted geometric, shifted or truncated negative binomial, and linear combinations of these; see Li [2] for more examples. Let \(p_{m}(z)=\prod_{i=1}^{m}(1-q_{i}z)\) and \(p_{m-1}^{*}(z)=\prod_{i=1}^{m}(1-q_{i})+\sum_{j=1}^{m}\beta_{j}(z-1)^{j}\). Then (4.1) becomes \(\hat{b}(z)=\frac{zp_{m-1}^{*}(z)}{p_{m}(z)}\).

Applying definition (2.2), it follows that

On the other hand, we can rewrite generalized Lundberg’s equation (2.12) as

We further denote \(q_{m}(z)=p_{m}(p_{3}z)\) and \(q_{m-1}^{*}(z)=p_{m-1}^{*}(p_{3}z)\). Then (4.2) can be rewritten as

or, equivalently,

It is obvious that the left side of equation (4.3) is a polynomial of degree \(2c+2m\) in *z* with leading coefficient \(\alpha=p_{3}^{m}\prod_{i=1}^{m}q_{i}^{2}\), which implies that there are \(2c+2m\) roots in total. According to Lemmas 1 and 2, exactly 2*c* roots are located in the unit circle \(\mathcal {C}\), denoted by \(z_{1}, z_{2}, \dots, z_{2c}\) as before. Therefore, we conclude that the remaining 2*m* roots must lie in the region \(\{z:\vert z\vert >1\}\), denoted by \(\rho_{1}, \rho_{2}, \dots, \rho_{2m}\). Since the left side of (4.3) is equivalent to \(p_{m}(z)q_{m}(z)[\hat{h}_{1,v}(z)-\hat{h}_{2,v}(z)]\), equation (4.3) can be reexpressed as

where \(p_{m}^{o}(z)=\prod_{i=1}^{m}(z-\frac{1}{q_{i}})\) and \(q_{m}^{o}(z)=\prod_{i=1}^{m}(z-\frac{1}{p_{3}q_{i}})\) are both polynomials of degree 2*m* in *z* with the leading coefficient 1. Substituting (4.4) into (3.1), we have

where \(S(z)=p_{m}^{o}(z)q_{m}^{o}(z)-\prod_{l=1}^{2m}(z-\rho_{l})\) is a polynomial of degree \(2m-1\) or less, and \(D(z)=\prod_{l=1}^{2m}(z-\rho _{l})\) is a polynomial of degree *m*. Further, if \(\rho_{1}, \rho_{2}, \dots, \rho_{2m}\) are distinct, then \(\hat{g}(z)\doteq\frac{S(z)}{D(z)}\) can be obtained by partial fractions as

where

Thus, inverting the generating function of (4.6) gives

Utilizing (4.7), we can invert the generating function in (4.5) to

Similarly, from (3.9) we obtain

### The generating function of the time to ruin with geometric distribution

In this section, we consider the generating function of the time to ruin, which is one of important quantities in risk analysis. Let the penalty function \(\omega(x_{1},x_{2})=1\) for all \(x_{1}\in\mathbb{N}\) and \(x_{2}\in\mathbb{N}^{+}\). Then the Gerber-Shiu function (1.3) reduces to

We assume that the claim sizes \(\{X_{i}, i=1, 2, \ldots\}\) follow geometric distribution with p.f. \(b(y)=(1-q)q^{y-1}\), \(y\in\mathbb {N}^{+}\), and the generating function \(\hat{b}(z)=\frac{z(1-q)}{1-zq}\). By (2.1) and (2.2) some simple algebras lead to

Implementing the expressions into (4.8), generalized Lundberg’s equation (2.12) becomes

which can be further rearranged to the following equation without changing the roots:

As discussed in Section 4.1, there are two roots lying in the complex plane \(\{z:\vert z\vert >1\}\), denoted by \(\rho_{1}\), \(\rho_{2}\). Henceforth, we assume that \(\rho_{1}\neq\rho_{2}\). The other 2*c* roots are in the unit circle \(\mathcal {C}\), still denoted by \(z_{i}\), \(i=1,2,\dots,2c\). Moreover, we have

On the other hand, substituting (4.8) into the expression of \(\hat{\eta}_{1}(z)\) finally proves that

where the constants \(\kappa_{1}\) and \(\kappa_{2}\) are determined respectively by

Inserting (4.10) and (4.11) into (3.6), we obtain

Using partial fractions, we rewrite (4.12) as

where

Finally, the inversion of (4.11) yields

As for \(\varphi_{2}(u)\), direct calculations yield

where the constants \(\iota_{i}\), \(i=1, 2, 3\), are given by

Consequently, \(\varphi_{2}(u)\) can be obtained by partial fractions as

where

### Example

In this example, we assume that the thresholds \(\{Q_{i}\}\) and claim sizes \(\{X_{i}\}\) both follow geometric distributions with parameters \(p_{3}=0.2\) and \(q=0.6\). Let \(c=1\), \(p_{1}=0.7\), \(p_{2}=0.8\), \(v=0.85\). It is easy to check that the positive loading condition is fulfilled. Generalized Lundberg’s equation has four roots: \(z_{1}=0.7410\), \(z_{2}=0.6601\), \(\rho _{1}=1.3692\), \(\rho_{2}=8.3914\). Furthermore, we use (4.14) and (4.15) to calculate the exact values for \(\varphi_{i}(u)\):

Figure 1 describes the behavior of \(\varphi_{i}(u)\), \(i=1, 2\), with respect to initial surplus *u*. As expected, \(\varphi _{i}(u)\) decreases as the initial surplus *u* increases. Moreover, \(\varphi_{1}(u)\) is always smaller than \(\varphi_{2}(u)\).

## Conclusions

We study a discrete-time ruin model with general premium rate and dependence structure, in which the distribution of the time until the next claim depends on the amount of the previous claim. Some analytic techniques are applied to study the Gerber-Shiu expected discounted penalty function. In particular, we show that the Gerber-Shiu function satisfies a defective renewal equation. Explicit expressions for the Gerber-Shiu function are obtained with discrete \(K_{m}\)-family claim sizes and geometric thresholds. The model in this paper can be further extended. For instance, suppose that the premium charged varies depending on the possible change in the distribution of interclaim time. Then the related ruin problems can be solved for this modified model.

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## Acknowledgements

The authors are very grateful to the anonymous referee for his/her valuable comments and suggestions. This research was supported by the Ministry of Education of Humanities and Social Science Project (15YJC910001) and the Program for Liaoning Excellent Talents in University (LR2014031).

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### Cite this article

Bao, Z., Liu, Y. A discrete-time ruin model with dependence between interclaim arrivals and claim sizes.
*Adv Differ Equ* **2016, **188 (2016). https://doi.org/10.1186/s13662-016-0893-4

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DOI: https://doi.org/10.1186/s13662-016-0893-4

### MSC

- 62P05
- 91B30

### Keywords

- dependence
- Gerber-Shiu discounted penalty function
- defective renewal equation
- Lundberg’s equation