Skip to main content

Advertisement

Table 6 Absolute errors for Example 3

From: Numerical solution of linear integral equations system using the Bernstein collocation method

t= 1 2 r ANN method Trapezoidal quadrature rule
e 1 , 3 ( t ) e 2 , 3 ( t ) e 3 , 3 ( t ) e 1 , 3 ( t ) e 2 , 3 ( t ) e 3 , 3 ( t )
r = 1 2.4 × 10−2 7.2 × 10−3 7.8 × 10−4 6.2 × 10−3 5.8 × 10−3 8.1 × 10−3
r = 2 6.1 × 10−3 4.9 × 10−3 5.7 × 10−4 2.0 × 10−2 2.0 × 10−2 2.1 × 10−2
r = 3 1.3 × 10−2 4.4 × 10−3 5.1 × 10−4 3.7 × 10−2 2.1 × 10−2 2.4 × 10−2
r = 4 1.4 × 10−2 4.2 × 10−3 5.1 × 10−4 2.8 × 10−2 1.5 × 10−2 3.2 × 10−2
r = 5 1.5 × 10−2 4.3 × 10−3 5.1 × 10−4 2.5 × 10−3 4.8 × 10−3 5.7 × 10−3
r = 6 1.6 × 10−2 4.2 × 10−3 5.1 × 10−4 2.1 × 10−2 5.3 × 10−2 6.7 × 10−3
r = 7 1.6 × 10−2 4.3 × 10−3 5.0 × 10−4 4.7 × 10−2 6.9 × 10−3 7.3 × 10−3
r = 8 1.6 × 10−2 4.3 × 10−3 5.0 × 10−4 4.3 × 10−2 3.4 × 10−2 2.2 × 10−2
r = 9 1.6 × 10−2 4.3 × 10−3 5.1 × 10−4 2.4 × 10−2 3.3 × 10−4 2.6 × 10−2