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Table 5 Numerical results with error analysis for Example 3

From: Numerical solution of linear integral equations system using the Bernstein collocation method

t= 1 2 r Exact solution Approximate solution Error
F 1 ( t ) F 2 ( t ) F 3 ( t ) F 1 , 3 ( t ) F 2 , 3 ( t ) F 3 , 3 ( t ) e 1 , 3 ( t ) , i = 1 , , 3
r = 1 10.500 −4.5000 1.7500 10.500 −4.5000 1.7500 0.0000
r = 2 9.2500 −4.8750 1.3125 9.2500 −4.8750 1.3125 0.0000
r = 3 8.6250 −4.9688 1.1406 8.6250 −4.9688 1.1406 0.0000
r = 4 8.3125 −4.9922 1.0664 8.3125 −4.9922 1.0664 0.0000
r = 5 8.1563 −4.9980 1.0322 8.1563 −4.9980 1.0322 0.0000
r = 6 8.0781 −4.9995 1.0159 8.0781 −4.9995 1.0159 0.0000
r = 7 8.0391 −4.9999 1.0079 8.0391 −4.9999 1.0079 0.0000
r = 8 8.0195 −5.0000 1.0039 8.0195 −5.0000 1.0039 0.0000
r = 9 8.0098 −5.0000 1.0020 8.0098 −5.0000 1.0020 0.0000